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SSC CHSL 2025 Aptitude Test - 1
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SSC CHSL 2025 Aptitude Test - 1
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  • Question 1/10
    2 / -0.5

    Directions For Questions

    Direction: 6 persons A, B, C, D, E, and F participate in an online quiz and win different amounts. The pie chart below shows the percentage of the total amount won by these 6 persons. Study the chart carefully and answer the question that follows. (Total amount won by all 6 persons is Rs. 12500)

    ...view full instructions


    Find the ratio of the difference between the amounts won by A and C to the difference between the amounts won by D and F.

    Solutions

    The correct answer is option 3 i.e. 3 : 1.

    From the pie chart:

    Percentages of the total amount won by A and C are 15% and 9% respectively.

    So, The difference in amounts won by A and C

    = 15% - 9%

    = 6%

    From the pie chart:

    Percentages of the total amount won by D and F are 14% and 16% respectively.

    So, The difference in amounts won by D and F

    = 16% - 14%

    = 2%

    Hence, Required ratio

    = (12500 × 6%) : (12500 × 2%)

    = 3 : 1

  • Question 2/10
    2 / -0.5

    Directions For Questions

    Direction: In a museum, only 2 types of tickets are sold: Local and Foreigner. The bar graph below shows the number of local tickets sold and the percentage of foreigner tickets sold in 5 different months: January, February, March, April, and May. Study the graph carefully and answer the questions that follow.

    ...view full instructions


    The total number of tickets sold in January is what percentage more than the total number of tickets sold in April?

    Solutions

    The correct answer is option 4 i.e. 80%.

    We have:

     

    Total number of tickets sold

    Number of foreigner tickets sold

    January

    468/0.65 = 720

    720 – 468 = 252

    February

    374/0.68 = 550

    550 – 374 = 176

    March

    352/0.55 = 640

    640 – 352 = 288

    April

    292/0.73 = 400

    400 – 292 = 108

    May

    456/0.57 = 800

    800 – 456 = 344

    So,

    Total number of tickets sold in January = 720

    Total number of tickets sold in April = 400

    Required percentage = {(720 - 400)/400} × 100 = 80%

  • Question 3/10
    2 / -0.5

    Directions For Questions

    Direction: The line graph below shows the number of youth addicted to Drugs and the number of youth inclined towards Yoga in 5 different states A, B, C, D and E. Study the graph carefully and answer the questions that folow. All the values in the graph are in lakhs.

    ...view full instructions


    Total number of youth addicted to drugs and those inclined towards Yoga in state A is how much percentage less than total number of youth addicted to drugs and those inclined towards Yoga in state C?

    Solutions

    The correct answer is option 2 i.e. 25%.

    Total number of youth addicted to drugs and those inclined towards Yoga in state A

    = 12 + 16.5 = 28.5 lakhs

    And

    Total number of youth addicted to drugs and those inclined towards Yoga in state C

    = 20 + 18 = 38 lakhs

    Hence,

    Required percentage = [(38 - 28.5)/38] × 100 = 25%

  • Question 4/10
    2 / -0.5

    In the following figure, AB and CD are the diameters of the circle. If ∠AOD = 80°, then what is the value of ∠ADC?

    Solutions

    The correct answer is option 3 i.e. 50°.

    If AB and CD are diameters, then O is the center of the circle.

    For chord AD, the angle subtended at center = ∠AOD = 80°

    ∴ ∠ACD = ∠AOD/2 = 40° [∵ Angle subtended by the chord on any point of the circle is half the central angle]

    In triangle CAD

    ∠CAD = 90° [∵ Diameter subtends right angle on the circle]

    ∠ACD + ∠CAD + ∠ADC = 180° [∵ Angle sum property of triangle]

    40° + 90° + ∠ADC = 180°

    ∴ ∠ADC = 50°

  • Question 5/10
    2 / -0.5

    Find the height of the triangle whose base is 5/7th of its height and its area is 18.207 cm2.

    Solutions

  • Question 6/10
    2 / -0.5

    In the triangle ABC, find the exterior angle to A if the interior angle to B is 60° and the exterior angle to C is 150°.

    Solutions

    The correct answer is option 3 i.e. 90°.

    Interior angel + Exterior angle = 180°

    Convert the exterior angles given to interior angles,

    Thus interior angle C = 180 - 150 = 30°

    The sum of the three angles of a triangle is 180°.

    Thus, A + 60° + 30° = 180°

    A = 90°

    Thus, the exterior angle to A = 180 - 90 = 90°

  • Question 7/10
    2 / -0.5

    The curved surface area of the cone and the radius of the cone are 180 cm2 and 6 cm, respectively. Find the volume of the cone. (Take π = 3)

    Solutions

    The correct answer is option 1 i.e. 288 cm3.

    Let the slant height of the cone be ‘l’ cm

    Curved surface area of the cone = π × r × l = 180

    ⇒ 3 × 6 × I = 180

    ⇒ I = 10 cm

    Let the height of the cone be ‘h’ cm.

    According to Pythagoras' theorem: r2 + h2 = l2

    ⇒ 62 + h2 = 102

    ⇒ h2 = 100 - 36

    ⇒ h = √64 = 8

    So, the volume of the cone = 1/3 × π × r2 × h = 1/3 × 3 × 36 × 8 = 288 cm3

  • Question 8/10
    2 / -0.5

    If cos A cosec A + cosec A = 2, and A is in between 0 to 90 then what will be the value of cos A?

    Solutions

    The correct answer is option 3 i.e. 3/5.

    Here cos A cosec A + cosec A  = 2

    ⇒ (cos A/sin A) + (1/sin A) = 2

    ⇒ cos A + 1 = 2 sin A

    Squaring both sides.

    ⇒ (cos A + 1)2 = 4 sin2 A

    ⇒ cos2 A + 2 cos A + 1 = 4 (1 - cos2 A)

    ⇒ 5 cos2A  +  2 cos A - 3 = 0

    ⇒ (5 cos A - 3)(cos A + 1) = 0

    Cos A = 3/5, -1

    (∵ A is between 0 to 90)

    ∴ cos A = (3/5)

  • Question 9/10
    2 / -0.5

    The radius of a roller is 49 cm and its length is 200 cm. It takes 700 complete rotations to level a playground once. Find the area of ​​the playground. (Use π = 22/7)

    Solutions

    The correct answer is option 1 i.e. 4312 × 104 cm².

    The radius of a roller, r = 49 cm

    The length of the roller i.e., the height of the cylinder, h = 200 cm

    [The distance covered by the roller in 1 revolution] = [Curved Surface Area of the cylinder] = 2πrh

    ⇒ The distance covered by the roller in 1 revolution is,

    = 2 × 22/7 × 49 × 200 = 61600 cm²

    Thus, the distance covered by the roller in 700 revolutions is given by,

    = 700 × 61600 cm² =  4,31,20,000 cm² = 4312  × 104 

  • Question 10/10
    2 / -0.5

    A boy stands at 12√3 feet from the foot of a hill of height 17 feet. The angle of elevation to the hill from the head of the boy is 30º. Find the height of the boy.

    Solutions

    The correct answer is option 1 i.e. 5 feet.

    AB = CD

    In triangle CDE, 

    tan30o = CE/DC

    ⇒ 1/√3 = CE/12√3

    ⇒ CE = 12

    Hence,

    BC = (BE - CE) = (17 - 12) = 5 

    BC = AD = 5

    Height of boy = 5 feet

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