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SSC MTS 2025 Aptitude Test - 1
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SSC MTS 2025 Aptitude Test - 1
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  • Question 1/10
    3 / -0

    Directions For Questions

    Direction: The bar graph shows the number of parties (Birthday, Anniversaries, Farewell and Success) held in two restaurants P and Q of a city in a month. Study the graph carefully and answer the questions that follow.

    ...view full instructions


    The total number of Anniversary parties held in the 2 restaurants is how much percentage more than the total number of Farewell parties held in them?

    Solutions

    The correct answer is option 1 i.e. 30%.

    From the bar graph:

    Total number of Anniversary parties held in 2 restaurants = (45 + 20) = 65

    And, Total number of Farewell parties held in 2 restaurants = (35 + 15) = 50

    Hence, Required percentage = [(65 – 50)/50] × 100 = 30%

  • Question 2/10
    3 / -0

    The curved surface area of the cone and the radius of the cone are 180 cm2 and 6 cm, respectively. Find the volume of the cone. (Take π = 3.)

    Solutions

    The correct answer is option 1 i.e. 288 cm3.

    Let the slant height of the cone be ‘l’ cm

    Curved surface area of the cone = π × r × l = 180

    ⇒ 3 × 6 × I = 180

    ⇒ I = 10 cm

    Let the height of the cone be ‘h’ cm.

    According to Pythagoras' theorem: r2 + h2 = l2

    ⇒ 62 + h2 = 102

    ⇒ h2 = 100 - 36

    ⇒ h = √64 = 8

    So, the volume of the cone = 1/3 × π × r2 × h = 1/3 × 3 × 36 × 8 = 288 cm3

  • Question 3/10
    3 / -0

    There are 21 boys in a class which is 3 more than twice the number of girls in the class. What is the total number of girls in the class?

    Solutions

    The correct answer is Option 3 i.e. 9.

    Let the number of girls be x

    Number of boys = 2x + 3

    ⇒ 21 = 2x + 3

    ⇒ 18 = 2x

    ∴ x = 9

  • Question 4/10
    3 / -0

    Ramesh sold an article for Rs 46 as a profit of 15%, What is the cost price at which Ramesh bought the article?

    Solutions

    The correct answer is option 3 i.e. 40

    Profit% = (Selling price - Cost price)/Cost price × 100

    ⇒ 15/100 = (46 - cost price)/cost price

    ⇒ 3/20 = (46 - cost price)/cost price

    ⇒ Cost price = Rs. 40

  • Question 5/10
    3 / -0

    If the price of a book is first decreased by 30% and then increased by 20%, then the net change in the price will be:

    Solutions

    The correct answer is option 3 i.e 16%

    Let the initial number be 100 then,

    First it decreases by 30 i.e. it becomes 70

    Then it increases 20% i.e,

    70 + 20% of 70 = 84

    Net decrease = (100 - 84)/100 × 100 = 16%

  • Question 6/10
    3 / -0

    What value should come in place of questions (?) in the following equation?

    7011 ÷ 19  – ?% of 654 = – 4195

    Solutions

    The correct answer is option 3 i.e. 698

    7011 ÷ 19  – ?% of 654 = – 4195

    ⇒ 369 – ?% × 654 = – 4195

    ⇒ 369 + 4195 = ?% × 654

    ⇒ ? = 4564  × 100/654

    ⇒ ? = 697.85

    ⇒ ? ~ 698

  • Question 7/10
    3 / -0

    Find the smallest three-digit number that is exactly divisible by 12, 45, and 24.

    Solutions

    The correct answer is option 3 i.e. 360.

    Let us factorize the given numbers first:

    12 = 2 × 2 × 3

    45 = 3 × 3 × 5

    24 = 2 × 2 × 2 × 3

    Hence,

    LCM of the numbers = 2 × 2 × 2 × 3 × 3 × 5 = 360

    So, the smallest three-digit number that is exactly divisible by 12, 45, and 24 = 360

  • Question 8/10
    3 / -0

    Aman and Ankit can together complete a piece of work in 40 days. Aman alone can complete the work in 60 days. How long will Ankit take to complete the work if he works alone?

    Solutions

    The correct answer is option 3 i.e. 120 days.

    If A and B together can complete a piece of work in x days and A alone can complete it in y days then B can complete it alone in {(xy)/(y - x)} days.

    Time taken by Ankit and Aman together to complete the work = 40 days

    Aman alone takes 60 days to complete the work.

    So, Ankit alone takes (60 × 40)/(60 - 40) = 120 days

  • Question 9/10
    3 / -0

    A sailor can row downstream at 24 km/h and upstream at 14 km/h. What is the speed of the sailor in still water?

    Solutions

    The correct answer is Option 2 i.e. 19 km/h.

    Let the speed of the sailor and stream be x and y respectively

    So, In the downstream speed of the sailor = x + y

    In the upstream speed of sailor = x - y

    According to question

    ⇒ x + y = 24 ---(1)

    ⇒ x - y = 14 ---(2)

    From equation (1) and (2) 

    x = 19 and y = 5

    ∴ Speed of sailor = 19 km/h

  • Question 10/10
    3 / -0

    In a family of 10 persons whose average age is 33. When the oldest person dies at the age of 69. What would be the new average age of the family?

    Solutions

    The correct answer is option 1 i.e. 29.

    Average = (Sum of all observations/Number of observations)

    Sum of age = (10 × 33) = 330 years

    When the oldest person dies,

    The sum of age = (330 - 69) = 261 years

    New average = 261/9 = 29 years

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