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IBPS RRB OS-1 2025 Aptitude Test - 1
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IBPS RRB OS-1 2025 Aptitude Test - 1
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  • Question 1/10
    1 / -0.25

    Directions For Questions

    Study the following information carefully and answer the questions.

    The given table chart shows the difference between the number of Ford and Audi cars sold in five different shops: A, B, C, D and E. It also provides the ratio of the number of Ford cars to Audi cars sold in these five shops and the percentage of the number of Honda cars sold out of the total number of cars sold in these five shops.

    Note:

    The total number of cars sold = The number of Ford cars sold + The number of Audi cars sold + The number of Honda cars sold

    ...view full instructions

    The number of Ford cars sold in shop E is what percentage of the total number of cars sold in shop B?

    Solutions

    For Shop A:

    Let the number of Ford cars and Audi cars sold be 3a and 7a respectively.

    7a – 3a = 20

    a = 20/4 = 5

    The number of Ford cars sold = 3 * 5 = 15

    The number of Audi cars sold = 7 * 5 = 35

    The number of Honda cars sold = (15 + 35) * 50/(100 – 50) = 50 * (50/50) = 50

    The total number of cars sold = 15 + 35 + 50 = 100

    For Shop B:

    Let the number of Ford cars and Audi cars sold be 4b and 3b respectively.

    4b – 3b = 20

    b = 20

    The number of Ford cars sold = 4 * 20 = 80

    The number of Audi cars sold = 3 * 20 = 60

    The number of Honda cars sold = (80 + 60) * 30/(100 - 30) = 140 * (30/70) = 60

    The total number of cars sold = 80 + 60 + 60 = 200

    For Shop C:

    Let the number of Ford cars and Audi cars sold be 7c and 8c respectively.

    8c – 7c = 5

    c = 5

    The number of Ford cars sold = 7 * 5 = 35

    The number of Audi cars sold = 8 * 5 = 40

    The number of Honda cars sold = (35 + 40) * 40/(100 – 40) = 75 * (40/60) = 50

    The total number of cars sold = 35 + 40 + 50 = 125

    For Shop D:

    Let the number of Ford cars and Audi cars sold be 11d and 4d respectively.

    11d – 4d = 28

    d = 28/7 = 4

    The number of Ford cars sold = 11 * 4 = 44

    The number of Audi cars sold = 4 * 4 = 16

    The number of Honda cars sold = (44 + 16) * 25/(100 – 25) = 60 * 25/75 = 20

    The total number of cars sold = 44 + 16 + 20 = 80

    For Shop E:

    Let the number of Ford cars and Audi cars sold be 2e and e respectively.

    2e – e = 32

    e = 32

    The number of Ford cars sold = 2 * 32 = 64

    The number of Audi cars sold = e = 32

    The number of Honda cars sold = (64 + 32) * 36/(100 – 36) = 96 * (36/64) = 54

    The total number of cars sold = 64 + 32 + 54 = 150

    Answer: B

    The required percentage = (64/200) * 100 = 32%

  • Question 2/10
    1 / -0.25

    Directions For Questions

    Study the following information carefully and answer the questions.

    The given table chart shows the difference between the number of Ford and Audi cars sold in five different shops: A, B, C, D and E. It also provides the ratio of the number of Ford cars to Audi cars sold in these five shops and the percentage of the number of Honda cars sold out of the total number of cars sold in these five shops.

    Note:

    The total number of cars sold = The number of Ford cars sold + The number of Audi cars sold + The number of Honda cars sold

    ...view full instructions

    If the ratio of the number of Honda cars sold in shop B to shop E is R:9 and the number of Ford cars sold in shop B is T times the number of Audi cars sold in shop D, find the value of (4T + R2).

    Solutions

    For Shop A:

    Let the number of Ford cars and Audi cars sold be 3a and 7a respectively.

    7a – 3a = 20

    a = 20/4 = 5

    The number of Ford cars sold = 3 * 5 = 15

    The number of Audi cars sold = 7 * 5 = 35

    The number of Honda cars sold = (15 + 35) * 50/(100 – 50) = 50 * (50/50) = 50

    The total number of cars sold = 15 + 35 + 50 = 100

    For Shop B:

    Let the number of Ford cars and Audi cars sold be 4b and 3b respectively.

    4b – 3b = 20

    b = 20

    The number of Ford cars sold = 4 * 20 = 80

    The number of Audi cars sold = 3 * 20 = 60

    The number of Honda cars sold = (80 + 60) * 30/(100 - 30) = 140 * (30/70) = 60

    The total number of cars sold = 80 + 60 + 60 = 200

    For Shop C:

    Let the number of Ford cars and Audi cars sold be 7c and 8c respectively.

    8c – 7c = 5

    c = 5

    The number of Ford cars sold = 7 * 5 = 35

    The number of Audi cars sold = 8 * 5 = 40

    The number of Honda cars sold = (35 + 40) * 40/(100 – 40) = 75 * (40/60) = 50

    The total number of cars sold = 35 + 40 + 50 = 125

    For Shop D:

    Let the number of Ford cars and Audi cars sold be 11d and 4d respectively.

    11d – 4d = 28

    d = 28/7 = 4

    The number of Ford cars sold = 11 * 4 = 44

    The number of Audi cars sold = 4 * 4 = 16

    The number of Honda cars sold = (44 + 16) * 25/(100 – 25) = 60 * 25/75 = 20

    The total number of cars sold = 44 + 16 + 20 = 80

    For Shop E:

    Let the number of Ford cars and Audi cars sold be 2e and e respectively.

    2e – e = 32

    e = 32

    The number of Ford cars sold = 2 * 32 = 64

    The number of Audi cars sold = e = 32

    The number of Honda cars sold = (64 + 32) * 36/(100 – 36) = 96 * (36/64) = 54

    The total number of cars sold = 64 + 32 + 54 = 150

    Answer: D

    The ratio of the number of Honda cars sold in shop B to shop E = 60:54 = 10:9 = R:9

    R = 10

    The number of Ford cars sold in shop B = T * the number of Audi cars sold in shop D

    80 = T * 16

    T = 5

    The required value = (4 * 5) + 102 = 20 + 100 = 120

  • Question 3/10
    1 / -0.25

    Directions For Questions

    Study the following information carefully and answer the questions.

    The given table chart shows the difference between the number of Ford and Audi cars sold in five different shops: A, B, C, D and E. It also provides the ratio of the number of Ford cars to Audi cars sold in these five shops and the percentage of the number of Honda cars sold out of the total number of cars sold in these five shops.

    Note:

    The total number of cars sold = The number of Ford cars sold + The number of Audi cars sold + The number of Honda cars sold

    ...view full instructions

    If the number of Ford cars sold in shop F is 50% more than that in shop D and the number of Audi cars sold in shop C is  8/5th of the number of Audi cars sold in shop F and the total number of Honda cars sold in shops C and F together is 99, find the total number of cars sold in shop F.

    Solutions

    For Shop A:

    Let the number of Ford cars and Audi cars sold be 3a and 7a respectively.

    7a – 3a = 20

    a = 20/4 = 5

    The number of Ford cars sold = 3 * 5 = 15

    The number of Audi cars sold = 7 * 5 = 35

    The number of Honda cars sold = (15 + 35) * 50/(100 – 50) = 50 * (50/50) = 50

    The total number of cars sold = 15 + 35 + 50 = 100

    For Shop B:

    Let the number of Ford cars and Audi cars sold be 4b and 3b respectively.

    4b – 3b = 20

    b = 20

    The number of Ford cars sold = 4 * 20 = 80

    The number of Audi cars sold = 3 * 20 = 60

    The number of Honda cars sold = (80 + 60) * 30/(100 - 30) = 140 * (30/70) = 60

    The total number of cars sold = 80 + 60 + 60 = 200

    For Shop C:

    Let the number of Ford cars and Audi cars sold be 7c and 8c respectively.

    8c – 7c = 5

    c = 5

    The number of Ford cars sold = 7 * 5 = 35

    The number of Audi cars sold = 8 * 5 = 40

    The number of Honda cars sold = (35 + 40) * 40/(100 – 40) = 75 * (40/60) = 50

    The total number of cars sold = 35 + 40 + 50 = 125

    For Shop D:

    Let the number of Ford cars and Audi cars sold be 11d and 4d respectively.

    11d – 4d = 28

    d = 28/7 = 4

    The number of Ford cars sold = 11 * 4 = 44

    The number of Audi cars sold = 4 * 4 = 16

    The number of Honda cars sold = (44 + 16) * 25/(100 – 25) = 60 * 25/75 = 20

    The total number of cars sold = 44 + 16 + 20 = 80

    For Shop E:

    Let the number of Ford cars and Audi cars sold be 2e and e respectively.

    2e – e = 32

    e = 32

    The number of Ford cars sold = 2 * 32 = 64

    The number of Audi cars sold = e = 32

    The number of Honda cars sold = (64 + 32) * 36/(100 – 36) = 96 * (36/64) = 54

    The total number of cars sold = 64 + 32 + 54 = 150

    Answer: C

    The number of Ford cars sold in shop F = 44 * (150/100) = 66

    The number of Audi cars sold in shop F = 40 * (5/8) = 25

    The number of Honda cars sold in shop F = 99 – 50 = 49

    The total number of cars sold in shop F = 66 + 25 + 49 = 140

  • Question 4/10
    1 / -0.25

    Directions For Questions

    Study the following information carefully and answer the questions.

    The given table chart shows the difference between the number of Ford and Audi cars sold in five different shops: A, B, C, D and E. It also provides the ratio of the number of Ford cars to Audi cars sold in these five shops and the percentage of the number of Honda cars sold out of the total number of cars sold in these five shops.

    Note:

    The total number of cars sold = The number of Ford cars sold + The number of Audi cars sold + The number of Honda cars sold

    ...view full instructions

    Out of the total number of Honda cars manufactured in shops B and D, 75% and 62.5% were sold, respectively. Find the difference between the number of Honda cars unsold in shop B and D

    Solutions

    For Shop A:

    Let the number of Ford cars and Audi cars sold be 3a and 7a respectively.

    7a – 3a = 20

    a = 20/4 = 5

    The number of Ford cars sold = 3 * 5 = 15

    The number of Audi cars sold = 7 * 5 = 35

    The number of Honda cars sold = (15 + 35) * 50/(100 – 50) = 50 * (50/50) = 50

    The total number of cars sold = 15 + 35 + 50 = 100

    For Shop B:

    Let the number of Ford cars and Audi cars sold be 4b and 3b respectively.

    4b – 3b = 20

    b = 20

    The number of Ford cars sold = 4 * 20 = 80

    The number of Audi cars sold = 3 * 20 = 60

    The number of Honda cars sold = (80 + 60) * 30/(100 - 30) = 140 * (30/70) = 60

    The total number of cars sold = 80 + 60 + 60 = 200

    For Shop C:

    Let the number of Ford cars and Audi cars sold be 7c and 8c respectively.

    8c – 7c = 5

    c = 5

    The number of Ford cars sold = 7 * 5 = 35

    The number of Audi cars sold = 8 * 5 = 40

    The number of Honda cars sold = (35 + 40) * 40/(100 – 40) = 75 * (40/60) = 50

    The total number of cars sold = 35 + 40 + 50 = 125

    For Shop D:

    Let the number of Ford cars and Audi cars sold be 11d and 4d respectively.

    11d – 4d = 28

    d = 28/7 = 4

    The number of Ford cars sold = 11 * 4 = 44

    The number of Audi cars sold = 4 * 4 = 16

    The number of Honda cars sold = (44 + 16) * 25/(100 – 25) = 60 * 25/75 = 20

    The total number of cars sold = 44 + 16 + 20 = 80

    For Shop E:

    Let the number of Ford cars and Audi cars sold be 2e and e respectively.

    2e – e = 32

    e = 32

    The number of Ford cars sold = 2 * 32 = 64

    The number of Audi cars sold = e = 32

    The number of Honda cars sold = (64 + 32) * 36/(100 – 36) = 96 * (36/64) = 54

    The total number of cars sold = 64 + 32 + 54 = 150

    Answer: A

    The number of Honda cars unsold in shop B = 60 * (100 – 75)/75 = 60 * (25/75) = 20

    The number of Honda cars unsold in shop D = 20 * (100 – 62.5)/62.5 = 20 * (37.5/62.5) = 12

    The required difference = 20 – 12 = 8

  • Question 5/10
    1 / -0.25

    Directions For Questions

    Study the following information carefully and answer the questions.

    The given table chart shows the difference between the number of Ford and Audi cars sold in five different shops: A, B, C, D and E. It also provides the ratio of the number of Ford cars to Audi cars sold in these five shops and the percentage of the number of Honda cars sold out of the total number of cars sold in these five shops.

    Note:

    The total number of cars sold = The number of Ford cars sold + The number of Audi cars sold + The number of Honda cars sold

    ...view full instructions

    If the number of Jaguar cars sold in shop X is equal to the average of the total number of cars sold in shops A and E, find the ratio of the number of Honda cars sold in shop A to the number of Jaguar cars sold in shop X.

    Solutions

    For Shop A:

    Let the number of Ford cars and Audi cars sold be 3a and 7a respectively.

    7a – 3a = 20

    a = 20/4 = 5

    The number of Ford cars sold = 3 * 5 = 15

    The number of Audi cars sold = 7 * 5 = 35

    The number of Honda cars sold = (15 + 35) * 50/(100 – 50) = 50 * (50/50) = 50

    The total number of cars sold = 15 + 35 + 50 = 100

    For Shop B:

    Let the number of Ford cars and Audi cars sold be 4b and 3b respectively.

    4b – 3b = 20

    b = 20

    The number of Ford cars sold = 4 * 20 = 80

    The number of Audi cars sold = 3 * 20 = 60

    The number of Honda cars sold = (80 + 60) * 30/(100 - 30) = 140 * (30/70) = 60

    The total number of cars sold = 80 + 60 + 60 = 200

    For Shop C:

    Let the number of Ford cars and Audi cars sold be 7c and 8c respectively.

    8c – 7c = 5

    c = 5

    The number of Ford cars sold = 7 * 5 = 35

    The number of Audi cars sold = 8 * 5 = 40

    The number of Honda cars sold = (35 + 40) * 40/(100 – 40) = 75 * (40/60) = 50

    The total number of cars sold = 35 + 40 + 50 = 125

    For Shop D:

    Let the number of Ford cars and Audi cars sold be 11d and 4d respectively.

    11d – 4d = 28

    d = 28/7 = 4

    The number of Ford cars sold = 11 * 4 = 44

    The number of Audi cars sold = 4 * 4 = 16

    The number of Honda cars sold = (44 + 16) * 25/(100 – 25) = 60 * 25/75 = 20

    The total number of cars sold = 44 + 16 + 20 = 80

    For Shop E:

    Let the number of Ford cars and Audi cars sold be 2e and e respectively.

    2e – e = 32

    e = 32

    The number of Ford cars sold = 2 * 32 = 64

    The number of Audi cars sold = e = 32

    The number of Honda cars sold = (64 + 32) * 36/(100 – 36) = 96 * (36/64) = 54

    The total number of cars sold = 64 + 32 + 54 = 150

    Answer: E

    The number of Jaguar cars sold in shop X = (100 + 150)/2 = 250/2 = 125

    The required ratio = 50:125 = 2:5

  • Question 6/10
    1 / -0.25

    A vessel contains a mixture of milk and water in the ratio of 5:3. If 40 liters of mixture is taken out and 70 liters of milk is added to the mixture, then the ratio of milk to water becomes 7:3. Find the initial quantity of mixture in the vessel?

    Solutions

    Answer: A

    [5x – 40 * 5/(5 + 3) + 70]/[(3x – 40 * 3/(5 + 3)) = 7/3

    [5x – 40 * 5/8 + 70]/[(3x – 40 * 3/8)] = 7/3

    [5x –25 + 70]/[(3x – 15)] = 7/3

    5x + 45 = 7/3 * (3x – 15)

    15x + 135 = 21x – 105

    6x = 240

    x = 40

    The initial quantity of mixture in the vessel = (5 + 3) * 40

    = 8 * 40 = 320 liters

  • Question 7/10
    1 / -0.25

    The time taken by a boat to cover 110 km downstream is one-third of the time taken to cover 210 km upstream. The speed of the boat in still water is 18 km/hr. If the speed of the stream decreases by 2 km/hr, find the total distance covered by the boat 12.5 hours upstream.

    Solutions

    Answer: B

    Let the initial speed of the stream be x km/hr.

    The downstream speed of the boat = (18 + x) km/hr

    The upstream speed of the boat = (18 – x) km/hr

    According to the question,

    110/(18 + x) = (1/3) * 210/(18 – x)

    110 * (18 – x) = 70* (18 + x)

    1980 – 110x = 1260 + 70x

    180x = 720

    x = 4

    The new speed of the stream = 4 – 2 = 2 km/hr

    The new upstream speed of the boat = 18 – 2 = 16 km/hr

    The required distance = 16 * 12.5 = 200 km

  • Question 8/10
    1 / -0.25

    A dishonest seed seller charges the cost price per kg, but gives only (x – 2) kg instead of x kg, there by making a 25% profit. Find the value of x.

    Solutions

    Answer: D

    Let the cost price of seeds per kg be Rs.100.

    According to the question,

    100 * {x/(x – 2)} = 100 * (125/100)

    100x = 125 * (x – 2)

    100x = 125x – 250

    x = 250/25

    x = 10

  • Question 9/10
    1 / -0.25

    A, B and C started a business with initial investments in the ratio of 8:5:15 respectively. After 9 months, A and B increased their investments by 25% and 40%, respectively, while C left the business. At the end of 1.5 years, the difference between the profit shares of A and C is Rs.920. Find the total profit of the business.

    Solutions

    Answer: E

    Let the initial investments of A, B and C be Rs.8x, Rs.5x and Rs.15x respectively.

    The ratio of profit share of A, B and C = [8x * 9 + (8x * (125/100)) * 9]: [5x * 9 + (5x * (140/100)) * 9] : [15x * 9]

    = (8x + 10x): (5x + 7x): 15x

    = 18x: 12x: 15x

    = 6: 4: 5

    The total profit of the business = 920 * (6 + 4 + 5)/(6 – 5) = 920 * (15/1) = Rs.13800

  • Question 10/10
    1 / -0.25

    P can complete half of the work in 18 days and Q can complete 5/8th of the work in 45 days. P, Q and R together can complete the work in (96/7) days and they receive a total wage of Rs.13650. Find the difference between wage shares of Q and R.

    Solutions

    Answer: A

    P alone can complete the work = 18 * 2 = 36 days

    Q alone can complete the work = 45 * (8/5) = 72 days

    R alone can complete the work = 7/96 – 1/36 – 1/72 = ((7 * 3) – 8 – 4)/288 = 9/288 = 1/32 = 32 days

    The ratio of the efficiency of P, Q and R = (1/36): (1/72): (1/32) = 8:4:9

    The wage of Q = 13650 * 4/(8 + 4 + 9) = 13650 * (4/21) = Rs.2600

    The wage of R = 13650 * (9/21) = Rs.5850

    The difference between the wages share of Q and R = 5850 – 2600 = Rs.3250

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