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A alone can do 60% of the work in 12 days and B alone can do 20% of the work in 12 days. A works for 2 days and rest of the work done by B. Find the total time taken by B to complete the remaining work.
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Given:
A alone can do 60% of the work in 12 days
B alone can do 20% of the work in 12 days
Formula used:
Total work = efficiency ×time
Explanation:
A alone can complete the work = 100/60×12=20
B alone can complete the work = 100/20×12=60
Total work = LCM (20 and 60) = 60 units
Efficiency of A = 60/20=3 units/day
Efficiency of B = 60/60=1 units/day
Time taken by B complete the work be d days
3 × 2 + 1 × d = 60
54 days = d
Three friends P, Q ad R share Rs. 13000. Q gets Rs 2000 from the total amount and P has 20% more amount than R. Find the difference between amount received by Q and R.
Total share = Rs. 13000
Share received by Q = 2000
Let the amount received by P, Q & R is Rs 13000
P = 120% R
6x+5x + 2000 = 13000
11000 = 11x
1000 = x
Required answer = 5000 - 2000 = Rs. 3000
100 liters of mixture contains milk and water in the ratio of 7: 3 respectively. 50 liter mixture of milk and water contains 20% milk. If both the mixture mixed together, then find the difference between milk and water.
Total quantity of mixture = 100 liter (milk : water = 7:3)
Total quantity of mixture = 50 liter (milk% = 20%)
Amount of milk in the mixture of 100 liter = 7/10×100=70 liters
Amount of water in the mixture of 100 liter = 3/10×100=30 liters
Amount of milk in the mixture of 50 liter = 20% of 50 = 10 liters
Amount of water in the mixture of 50 liter = (100-20)% of 50 =40 liters
Total milk = 70 +10 = 80
Total water = 40+30 = 70
Required difference = 80 – 70 = 10 liter
Alternate method:
Total mixture = 100 + 50 = 150 liter
Total water = 150 -80 = 70
Required answer = 80 – 70 = 10
The area of right-angled triangle is 18 sq cm. If the side of the square is the product of base and height of the triangle, then find the area of the square.
Area of right-angled triangle = 182 sq cm
Area of the right angle triangle = ½ base × height
Area of square = (side)²
Area = ½ ×base×height
½ ×base×height =18
base×height = 36
Required area= 36 × 36 = 1296 cm²
Series A consist of four consecutive odd numbers whose average is 66 and series B consist of four consecutive even numbers whose average is 51. Find the difference between the second smallest number of series A and smallest number of series B.
Average of four consecutive odd numbers =66
Average of four consecutive even numbers = 51
Four consecutive odd number = a-2, a, a+2,a+4
Four consecutive even number = b-2, b, b+2,b+4
For series A
4a + 4 = 66×4
4a = 260
a = 65
For series B
4b + 4=51 ×4
b = 50
Required difference = 65 – 48 = 17
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