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IBPS Clerk 2025 Aptitude Test - 2
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IBPS Clerk 2025 Aptitude Test - 2
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  • Question 1/10
    1 / -0.25

    The sum of the age of A and B after 5 years is 90 years and the sum of the present age of B and C together is 70 years. The present age of A is 40% more than the present age of C. If the present age of D is 8 years more than that of C, then find the present age of D.

    Solutions

    Answer: E

    A + 5 + B + 5 = 90

    A + B = 80 —----->(1)

    B + C = 70 —----->(2)

    By solving equation (1) and (2), we get

    A - C = 10

    The ratio of the present age of C to A = 100: 140 = 5: 7

    Let, the present age C and A be 5x years and 7x years respectively.

    7x - 5x = 10

    2x = 10

    x = 5

    The present age of C = 5 * 5 = 25 years

    The present age of D = (25 + 8) = 33 years

    Hence, the correct answer is option E

  • Question 2/10
    1 / -0.25

    A and B started a business by investing Rs. 18000 and Rs. 22000 respectively. After 6 months, A decreased his investment by (m - 5)% and B decreased his investment by Rs. 2000. At the end of the year, the ratio of the profit share of A to B is 27: 35, then find the value of m.

    Solutions

    Answer: C

    The ratio of the profit share of A to B = (18000 * 6 + (18000 * (100 - m + 5)/100 * 6): (22000 * 6 + (22000 - 2000) * 6)

    = (18000 + 180 * (105 - m)): (22000 + 20000)

    = (18000 + 18900 - 180m) : (42000)

    = (36900 - 180m): 42000

    = (3690 - 18m): 4200

    = (1230 - 6m): 1400

    = (615 - 3m): 700

    (615 - 3m)/700 = 27/35

    (205 - m)/20 = 9/1

    205 - m = 180

    m = 25

    Hence, the correct answer is option C

  • Question 3/10
    1 / -0.25

    In a company of 75 employees, the average weight of males is (z + 5) kg and the average weight of females is 56.25 kg and the number of females is 5 more than that of the number of males. If the average weight of all the employees in the company is 44 kg, then find the value of z.

    Solutions

    Answer: D

    Let, the number of male employees in the company = P

    The number of female employees in the company = (P + 5)

    P + P + 5 = 75

    2P = 70

    P = 35

    The number of male employees in the company = 35

    The number of female employees in the company = (35 + 5) = 40

    35 * (z + 5) + 40 * 56.25 = 44 * 75

    35z + 175 + 2250 = 3300

    35z + 2425 = 3300

    35z = 875

    z = 25

    Hence, the correct answer is option D

  • Question 4/10
    1 / -0.25

    The time taken by Train A to cross a platform of length 300 m is equal to the time taken by Train B to cross a bridge of 1000 m and the length of Train A is 70% of the length of Train B. If the speed of Train A and B is 72 km/hr and 144 km/hr, respectively, then find the length of train B.

    Solutions

    Answer: E

    The speed of Train A = 72 * 5/18 = 20 m/s

    The speed of Train B = 144 * 5/18 = 40 m/s

    The ratio of the length of Train A to Train B  = 70: 100 = 7: 10

    Let, the length of train A = 7x m

    The length of train B = 10x m

    (7x + 300)/20 = (10x + 1000)/40

    (7x + 300)/1 = (10x + 1000)/2

    14x + 600 = 10x + 1000

    4x = 400

    x = 100

    The length of train B = 10 * 100 = 1000 m

    Hence, the correct answer is option E

  • Question 5/10
    1 / -0.25

    Ram invested Rs. (3x + 160) in  scheme A at the rate of 10% per annum for compound interest and the Rs. 5x is invested in simple interest at the rate of 25% per annum for 2 years. If the interest received after 2 years in scheme A is Rs. (x - 33), then find the simple interest received by Ram.

    Solutions

    Answer: D

    For scheme A,

    Compound interest CI = P(1 + R/100)n - P

    (x - 33) = (3x + 160) * 1.1 * 1.1 - (3x + 160)

    (x - 33) = (3.63x + 193.6) - 3x - 160

    (x - 33) = 0.63x + 33.6

    x - 0.63x = 33.6 + 33

    0.37x = 66.6

    x = 180

    5x  = 5 * 180 = Rs. 900

    Simple interest = PNR/100

    SI = 900 * 25 * 2/100

    SI = Rs. 450

    Hence, the correct answer is option D

  • Question 6/10
    1 / -0.25

    What value should come in the place of (?) in the following questions.

    (121 + 149 - 10)/10 + ?2 = 16 * 18 - 37

    Solutions

    Answer: C

    (121 + 149 - 10)/10 + ?2 = 16 * 18 - 37

    (270 - 10)/10 + ?2 = 288 - 37

    260/10 + ?2 = 251

    26 + ?2 = 251

    ?2 = 225

    ? = 15

    Hence, the correct answer is option C

  • Question 7/10
    1 / -0.25

    What value should come in the place of (?) in the following questions.

    ?% of 880 - 42 = 1890 - 15 * 12 + 30% of 700

    Solutions

    Answer: A

    ?% of 880 - 42 = 1890 - 15 * 12 + 30% of 700

    8.8 * ? - 16 = 1890 - 180 + 210

    8.8 * ? = 1936

    ? = 220

    Hence, the correct answer is option A

  • Question 8/10
    1 / -0.25

    What value should come in the place of (?) in the following questions.

    (192/24) * 12 + 252 = ?3 - 5121/3

    Solutions

    Answer: C

    (192/24) * 12 + 252 = ?3 - 5121/3

    8 * 12 + 625 = ?3 - 8

    96 + 625 + 8 = ?3

    729 = ?3

    ? = 9

    Hence, the correct answer is option C

  • Question 9/10
    1 / -0.25

    What value should come in the place of (?) in the following questions.

    {4(1/6) + 6(3/8) - 2(1/12)} * 96 = ? - 412

    Solutions

    Answer: B

    {4(1/6) + 6(3/8) - 2(1/12)} * 96 = ? - 412

    {(25/6) + (51/8) - (25/12)} * 96 = ? - 412

    {(200 + 306 - 100)/48} * 96 = ? - 412

    406 * 2 + 412 = ?

    ? = 1224

    Hence, the correct answer is option B

  • Question 10/10
    1 / -0.25

    What value should come in the place of (?) in the following questions.

    125% of ? + (15 * 22) = 125 + √400 * 3

    Solutions

    Answer: E

    125% of ? + (15 * 22) = 125 + √400 * 3

    125% of ? + (15 * 4) = 125 + 20 * 3

    125% of ? + 60 = 185

    125% of ? = 125

    ? = 100

    Hence, the correct answer is option E

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