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IBPS RRB (OA) 2025 Aptitude Test - 5
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IBPS RRB (OA) 2025 Aptitude Test - 5
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  • Question 1/10
    1 / -0.25

    The ratio of alcohol and water in vessel A and B is 5 : 3 and 5 : 7 respectively. In what ratio the mixture from both the vessel mixed to get new mixture containing alcohol and water in the ratio 4:3.

    Solutions

    Given:

    Ratio of alcohol and water in A = 5:3

    Ratio of alcohol and water in B = 5:7

    Ratio of alcohol and water after mixing A and B = 4:3

    Formula used:

    Quantity of Cheaper Quantity of Dearer

    Mean

    Dearer-Mean Mean-Cheaper

    Explanation:

  • Question 2/10
    1 / -0.25

    A car and a bus started a race from same point. The speed of car is 116.66% of speed of bus. After four hours distance between them is 28 km. Find the time taken by car to cover 196 km distance.

    Solutions

    Given:

    Speed of car is 116.66% of speed of bus.

    Distance between them after four hours = 28 km.

    Formula used:

    Speed = distance/time

    Explanation:

    Let speed of bus be 6x km/hr

    So, the speed of car 7x km/hr

    (7x – 6x) × 4 = 28

    x = 7

  • Question 3/10
    1 / -0.25

    A can do a work in x days. While B can do the same work in (x + 4) days. Ratio of work done by A in three days to work done by B in four days is 15 : 16. Find the value of ‘x’.

    Solutions

    Given:

    Ratio of work done by A in three days and B in four days is 15 : 16

    Formula used:

    Total work = efficiency ×time

    Explanation:

    One day work of A = 1/x

    3 day work of A = 3/x

    One day work of B = 1/((x+4) )

    4 day work of B = 4/(x+4)

  • Question 4/10
    1 / -0.25

    A man sells two identical articles. On one he gets a profit of 15% and on another article he gets a loss of 10%. Find his overall profit/ loss percent.

    Solutions

    Given:

    Profit percentage of one article = 15%

    Loss percentage of second article = 10%

    Formula used:

    Profit = selling price – cost price

    Loss = cost price – selling price

  • Question 5/10
    1 / -0.25

    Vande bharat train can cross a platform of length 98 m in 24 second. Tejas train of same length as vande bharat crosses a pole in 12 second. If speed of vande bharat is 20% more than speed of tejas . Find length of vande bharat train.

    Solutions

    Given:

    Vande bharat train can cross a platform of length 98 m in 24 second

    Length of VANDE BHARAT = length of Tejas train = l m

    Tejas train can cross the pole in 12 sec.

    Formula used:

  • Question 6/10
    1 / -0.25

    A mixture of milk and water contains 75% milk. If 8 liter of mixture is taken out and 7 liters of milk is added, then ratio of milk to water becomes 7 : 2. Find the quantity of mixture initially.

    Solutions

    Given:

    Mixture contains 75% of milk.

    Ratio of milk to water in final mixture 7 : 2.

    Formula used:

    Explanation:

    Let total quantity of mixture initially = 100x

    Quantity of milk initially = 75x

    Quantity of water initially = 25x

    Now,

    ATQ,

  • Question 7/10
    1 / -0.25

    The average weight of a class of 45 girls is 53 kg. It was found that weight of two girls was read as 49 kg and 57 kg instead of 45 kg and 52 kg. Find the actual average weight of the class.

    Solutions

    Given:

    Average weight of a class of 45 girls is 53 kg

    Formula used:

  • Question 8/10
    1 / -0.25

    The ratio of speed of boat in still water to speed of stream is 11 : 1. If the boat takes 1 hour more to cover 220 km upstream than to cover same distance in still water. Then find the speed of boat in still water.

    Solutions

    Given:

    Ratio of speed of boat in still water to speed of stream is 11 : 1.

    Formula used:

    Speed = (distance )/time

    Downstream speed = speed of boat +speed of stream

    Upstream speed = speed of boat - speed of stream

    Explanation:

    Let speed of boat in still water = 11x

    Speed of stream = x

    ATQ,

    So speed of boat in still water = 11 × 2 = 22 km/hr

  • Question 9/10
    1 / -0.25

    A shopkeeper sold an article at a profit of 10%. If the article is mark up by 30% above cost price and gives a discount of 10%, the the difference between the profit becomes Rs. 56. Find the cost price of article.

    Solutions

    Given:

    Profit percentage = 10%

    Mark up percentage = 30%

    Discount = 10%

    Formula used:

    Profit = selling price – cost price

    Explanation:

    Cost price of the article = 100x

    Selling price = 110% of 100x = 110x

    New selling price of the article = 100x×130%×90%= 117x

    ATQ,

    117x –110x = 56

    x = 8

    cost price of article = 100x

    = 100 × 8

    = Rs. 800

  • Question 10/10
    1 / -0.25

    Directions For Questions

    The table shows the percentage of boys in two school A and B in five different years.

    Years

    School A

    School B

    2012

    54%

    52%

    2013

    60%

    64%

    2014

    48%

    44%

    2015

    62%

    56%

    2016

    48%

    50%

    Note - Total students in any school = Total boys + Total girls in each school

    ...view full instructions

    In 2012, ratio of boys in school A to school B is 45 : 52 and total students in both school in 2012 is 1100. Find the total number of girls in both school in same year.

    Solutions

    Let total boys in school A = 45x

    and total boys in school B = 52x

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