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IBPS RRB OS-1 2025 Aptitude Test - 6
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IBPS RRB OS-1 2025 Aptitude Test - 6
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  • Question 1/10
    1 / -0.25

    What approximate value should come in the place of (?) in the following questions.

    (59.99 * 2.99) + 455.12 - ? = 280.12

    Solutions

    Answer: A

    (59.99 * 2.99) + 455.12 - ? = 280.12

    (60 * 3) + 455 - ? = 280

    180 + 455 - ? = 280

    635 - ? = 280

    ? = 635 – 280

    ? = 355

  • Question 2/10
    1 / -0.25

    What approximate value should come in the place of (?) in the following questions.

    (? + 120.12) * 2 + 40% of 999.99 = 1200.12

    Solutions

    Answer: C

    (? + 120.12) * 2 + 40% of 999.99 = 1200.12

    (? + 120) * 2 + 400 = 1200

    (? + 120) * 2 = 800

    ? + 120 = 400

    ? = 280

  • Question 3/10
    1 / -0.25

    A mixture contains milk and water in the ratio of 16:9. After 250 ml of the mixture is taken out, 40 ml of milk and 10 ml of water are added to the remaining mixture. The ratio of milk to water then becomes 2:1. Find the initial quantity of milk in the mixture.

    Solutions

    Answer: A

    Let the quantity of milk and water in the initial mixture be 16x ml and 9x ml, respectively.

    The quantity of milk in 250 ml of mixture = (16/25) * 250 = 160 ml

    The quantity of water in 250 ml of mixture = 250 - 160 = 90 ml

    (16x - 160 + 40)/(9x - 90 + 10) = 2/1

    16x – 120 = 18x – 160

    2x = 40

    x = 20

    The initial quantity of milk in the mixture = 16 * 20 = 320 ml

  • Question 4/10
    1 / -0.25

    A bought a cycle for Rs.x and he sold it to B at a profit of y% and B sold it to C at a loss of 20%. If B paid Rs.3600 and C paid Rs.(x – 120) for the cycle, then find the value of y?

    Solutions

    Answer: C

    x * (100 + y)/100 = 3600 ---- (1)

    x * (100 + y)/100 * 80/100 = x – 120 ---- (2)

    From (1) and (2),

    3600 * 80/100 = x – 120

    2880 = x – 120

    x = Rs.3000

    3000 * (100 + y)/100 = 3600

    500 + 5y = 600

    5y = 100

    y = 20%

  • Question 5/10
    1 / -0.25

    B and C entered into a business by investing Rs. (x + 300) and Rs. 800, respectively. B and C invested for 8 months and 10 months, respectively. If the ratio of the profit share of B to C is 9:10, find the value of x.

    Solutions

    Answer: A

    The ratio of the profit share of B to C =[(x + 300) * 8] :(800 * 10)

    According to the question,

    [(x + 300) * 8]/(800 * 10) = 9/10

    (x + 300)/1000 = 9/10

    x + 300 = 900

    x = 600

  • Question 6/10
    1 / -0.25

    Two cars, A and B, are at Delhi and Mumbai, respectively, which are 810 km apart. Both cars start their journey at 10:00 am. They meet at 2:48 pm, and car B reaches Delhi at 11:30 pm on the same day. Approximately how many hours will it take for car A to reach Mumbai?

    Solutions

    Answer: D

    Car B travels from Mumbai to Delhi from 10:00 am to 11:30 pm = 13.5 hours

    So, the speed of car B = 810/13.5 = 60 km/h 

    The time taken by car A and car B to meet from 10:00 am to 2:48 pm = 4 hours 48 minutes = 4.8 hours 

    (Speed of car A + Speed of car B) * 4.8 = 810

    Speed of car A + 60 = 810/4.8

    Speed of car A = 168.75 – 60 = 108.75 km/h

    The time taken by car A to reach Mumbai = 810/108.75 = 7.448 = 7.5 hours

  • Question 7/10
    1 / -0.25

    The difference between the simple interest and compound interest on a certain sum at the rate of 25% per annum after 2 years is Rs.250. Find the simple interest, if he invested the same amount at the rate of 10% per annum for 3 years.

    Solutions

    Answer: D

    Let the principal = P

    250 = P * (25/100)2

    P * (1/4)2 = 250

    P = 250 * 16

    P = 4000

    Required simple interest = 4000 * 10 * 3/100 = Rs.1200

  • Question 8/10
    1 / -0.25

    A boat covers 240 km downstream in 8 hours and the boat covers d km in still water in 5 hours. If the ratio of the speed of the boat to the speed of the stream is 11:4, then find the value of d.

    Solutions

    Answer: A

    Let the speed of the boat in still water = 11x

    And the speed of the stream = 4x

    11x + 4x = 240/8

    15x = 30

    x = 2

    The speed of the boat in still water = 11 * 2 = 22 km/hr

    d = 22 * 5

    d = 110 km

  • Question 9/10
    1 / -0.25

    A box contains 25 red balls, 16 blue balls and 19 green balls. If four balls are drawn at random from the box, then find the probability of getting two red balls, one blue ball and one green ball?

    Solutions

    Answer: B

    The total number of balls in the box = 25+16+19 = 60 balls

    Required probability = 25C2*16C1*19C1/60C4

    = (25*24/2)*16*19/(60/4*59/3*58/2*57)

    = 25*12*16*19/(5*59*29*57)

    = 320/1711

  • Question 10/10
    1 / -0.25

    The ratio of the present age of A to B is 9:11 and after 5 years, the ratio of the age of A to B is 5:6. If the present age of C is 20% more than that of B and the ratio of the present age of C to D is 3:4, find the present age of D.

    Solutions

    Answer: D

    Let, the present age of A and B be 9x and 11x years respectively.

    (9x + 5)/(11x + 5) = 5/6

    54x + 30 = 55x + 25

    x = 5

    The present age of B = 11 * 5 = 55 years

    The present age of C = 55 * 120/100 = 66 years

    The present age of D = 66 * 4/3 = 88 years

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