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SSC CHSL 2025 Aptitude Test - 4
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SSC CHSL 2025 Aptitude Test - 4
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  • Question 1/10
    2 / -0.5

    The average speed of Gaurav during a two-way journey is 15 km/h. If he walked a distance of 20 km every hour while going, then his speed while returning will be:

    Solutions

    The correct answer is option 3 i.e. 12 km/h.

    Average Speed = 2 × Distance× Distance/ Distance1 + Distance2

    D = 20 km 

    Time taken to go  = D / 20 = 1  hour 

    Time returning = D / v

    Total Time = 1 + D / v = 1 + 20 / v

    ⇒ 15 = (40) / (1 + 20 / v)

    ⇒ 15 (1 + 20 / v )= 40

    ⇒ 15 + 300 / v= 40

    ⇒ 300 / v = 25

    ⇒ 300 = 25v

    v = 12  km/h

  • Question 2/10
    2 / -0.5

    Three numbers are given in which the second is triple the first and is also double the third. If the average of the three numbers is 66, find the second number.

    Solutions

    The correct answer is Option 1 i.e. 108.

    As per the given question,

    ⇒ 1st number = 2x (let)

    ⇒ 2nd number = 3(2x) = 6x

    ⇒ 3rd number = 6x/2 = 3x

    We know that,

    Average = Sum of observations/Number of observations

    ⇒ (2x + 6x + 3x)/3 = 66

    ⇒ 11x = 66 × 3

    ⇒ x = 6 × 3

    ⇒ x = 18

    2nd number = 3(2x) = 3(2 × 18) = 108

  • Question 3/10
    2 / -0.5

    The ratio of the number of marbles that Joyee and Minati had was 5 : 8 while the ratio of the number of marbles that Jacob and Minati had was 7 : 12. What is the ratio of the number of marbles that Joyee and Jacob had?

    Solutions

    The correct answer is option 2 i.e. 15:14.

    Given that

    The ratio of the number of marbles that Joyee and Minati had was 5 : 8

    the ratio of the number of marbles that Jacob and Minati had was 7 : 12

    According to the question

    Joyee/Minati = 5x/8x ...........(1

    Jacob/Minati = 7x/12x  ........(2

    Now, Joyee/Jacob = (5x/8x)/(7x/12x) = 5/8 × 12/7 = 15/14

    Hence, the ratio of Joyee and Jacob is 15 : 14

  • Question 4/10
    2 / -0.5

    The interest on ₹ 1250 for 6 years at the rate of 4% simple interest per annum will be:

    Solutions

    The correct answer is option 4 i.e. ₹300.

    Given that

    Principal (P) =  ₹ 1250

    Time (T) = 6 years

    Rate of simple interest (R) = 4% p.a.

    Formula used:

    S.I. = P × R × T/100

    where, S.I. = Simple interest, P = Principal, T = time

    Calculation:

    S.I. = 1250 × 4 × 6/100 

    S.I. = 50 × 6

    S.I. = ₹ 300

  • Question 5/10
    2 / -0.5

    The given diagram depicts the distribution of salaries per annum (in lakh) of CEOs of six MNCs (C1, C2, C3, C4, C5 and C6).

    By what percent is the income of the highest paid CEO more than the income of the lowest paid CEO?

    Solutions

    The correct answer is option 3 i.e. 50.

    ⇒ salary drawn by highest paid CEO = 75 lakh

    ⇒ salary drawn by lowest paid CEO = 50 lakh

    ⇒ Difference between these salaries = 75 lakh - 50 lakh = 25 lakh

    ⇒ Difference Percentage = 25/50 × 100 = 50 %

  • Question 6/10
    2 / -0.5

    In △ ABC if ∠A = 40° and ∠B = 70°, find the measure of exterior angle A.

    Solutions

    The correct answer is option 1 i.e. 140°.

    ∠ A = 40° , ∠ B = 70°

    ∠ C  = 180° - ∠A - ∠ B = 180° - 40° - 70° = 70°

    Exterior  ∠ A = ∠ B + ∠ C = 70° + 70°= 140°

  • Question 7/10
    2 / -0.5

    The dimension of the floor of a room is 6 m × 4 m and the height of the room is 3 m. What is the cost of painting the walls of the room at Rs 320/m2?

    Solutions

    The correct answer is Option 4 i.e. Rs 19200.

    Lateral surface = 2h (l + b)

    ⇒ 2 × 3 × (6 + 4) = 60 m2

    Cost of painting = 60 × 320

    ⇒ Rs 19200

  • Question 8/10
    2 / -0.5

    Find the value of  5sin260° + 7sin245° + 8cos245°.

    Solutions

    The correct answer is option 3 i.e. 45/4.

     5sin260° + 7sin245° + 8cos245°

    = 5 × (√3/2)+ 7 × (1/√2)+ 8 × (1/√2)2

    = 5 × (3/4) + 7 × (1/2) + 8 × (1/2)

    = (15/4) + (7/2) + (8/2)

    = (45/4)

  • Question 9/10
    2 / -0.5

    What will be the value of cosec(- 45°) + sec (π/2 - 45°) - sin(- 90°) - tan2(- 30°)?

    Solutions

    The correct answer is option 3 i.e. 2/3.

    cosec(- 45°) + sec (π/2 - 45°) - sin(- 90°) - tan2(- 30°)

    We know that

    ⇒ cosec(- θ) = - cosecθ

    ⇒ sec(90 - θ) = cosecθ

    ⇒ sin(- θ) = - sinθ and,

    ⇒ tan(- θ) = - tanθ

    Now, according to the question 

    ⇒ - cosec 45° + cosec 45° - (-sin 90°) - tan2 30°

    ⇒ -(-1) - 1/3

    ⇒ 1 - (1/3) = 2/3

  • Question 10/10
    2 / -0.5

    A shopkeeper sold a television at a loss of 10%. Instead, if he had sold it for Rs. 1540 more, he would have earned 25% profit. Find the price at which he bought the television.

    Solutions

    The correct answer is Option 4 i.e. Rs. 4400.

    Selling price = Cost price (1 - Loss %)

    Selling price = Cost price (1 + Profit %)

    Let the cost price of the television = Rs. X

    Selling Price (SP) = Cost Price (1 - 10 %) = X [1 - (10/100)]

    = 90X/100

    If the shopkeeper had instead sold the television for Rs. 1540 more, he would have made 25% profit
    (i.e)

    SP + 1540 = X + (25/100) X

    ⇒ (90X/100) + 1540 = (125X/100)

    ⇒ (125X/100) - (90X/100) = 1540

    ⇒ 35X/100 = 1540

    ⇒ X = (1540 × 100)/35 = Rs. 4400

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