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Delhi Police 2025 Aptitude Test - 1
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Delhi Police 2025 Aptitude Test - 1
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  • Question 1/10
    1 / -0.25

    What is the value of (84 ÷ 12 × 3 − 4 ÷ 12 × 9 + 5 × 6 − 2 × 3)/(8 ÷ 12 × 3)

    Solutions

    The correct answer is option 2 i.e. 21

    (84 ÷ 12 × 3 − 4 ÷ 12 × 9 + 5 × 6 − 2 × 3)/(8 ÷ 12 × 3)

    ⇒ (7 × 3 - 3 + 30 - 6)/(2)

    ⇒ (21 - 3 + 30 - 6)/2

    ⇒ (51 - 9)/2

    ⇒ 42/2 = 21

  • Question 2/10
    1 / -0.25

    What is the second smallest number which upon dividing by 3, 5, 7 and 11 leaves a remainder of 2 in each case?

    Solutions

    The correct answer is option 2 i.e. 2312.

    Smallest number divisible by 3, 5, 7, and 11 = LCM (3, 5, 7, 11)

    ⇒ 3 × 5 × 7 × 11 = 1155

    Second smallest number = 2 × 1155 = 2310

    To leave a remainder of 2, the number should be = 2310 + 2 = 2312

  • Question 3/10
    1 / -0.25

    If 4p75684q2 is divisible by 72 then, find the value of p + q.

    Solutions

    The correct answer is Option 1 i.e. 9.

    4p75684q2 is divisible by 72, it will also be divisible by 8 and 9

    Divisibility of 8 = Number formed by the last three digits must be divisible by 8

    4q2 is divisible by 8, q must be 3 or 7

    4p7568432 or 4p7568472 must be divisible by 9

    Divisibility of 9 = sum of digits must be divisible by 9

    4p7568432 = 4 + 7 + 5 + 6 + 8 + 4 + 3 + 2 + p = 39 + p; p must be 6

    4p7568472 = 4 + 7 + 5 + 6 + 8 + 4 + 7 + 2 + p = 43 + p; p must be 2

    p + q = 6 + 3 or 2 + 7 = 9

  • Question 4/10
    1 / -0.25

    A sum of money amounts to ₹14,112 at the rate of 20% per annum compounded annually for 3 years. Find the sum of money.

    Solutions

    The correct answer is option 4 i.e. ₹8,166.67.

    Amount A = ₹14,112

    Rate = r = 20% per annum compounded annually

    Time = n = 3 years

    Principal = P = ?

    A = P(1 + r/100)n

    ⇒ 14112 = P(1 + 20/100)3

    ⇒ 14112 = 216P/125

    ⇒ P = 49000/6 = Rs 8,166.67

  • Question 5/10
    1 / -0.25

    P invested 20% of the total investment, Q invested 40% of the remaining investment and R invested the rest. The profit at the end of the year is Rs 50,000.

    What is the investment of R (in Rs)?

    Solutions

    The correct answer is option 3 i.e. Rs 24,000.

    Given:

    Total profit at the end of the year = Rs 50,000.

    Explanation:

    Let the total invested by P, Q and R be 100x.

    Now, Investment of P = 20% of 100x = 20x

    Remaining investment = 100x - 20x = 80x

    Investment of Q = 40% of 80x = 32x

    Investment of R = 100x - (20x + 32x) = 48x

    So ratio of profits of P, Q and R = 20x : 32x : 48x = 5 : 8 : 12

    Hence the investment of R is Rs 24,000.

  • Question 6/10
    1 / -0.25

    The present population of the city is estimated to be 10 lakh and is expected to increase to 12.10 lakh during the next 2 years. The uniform annual rate of growth is:

    Solutions

    The correct answer is option 3 i.e.10%.

    Given that

    The current population of the city is 10 lakhs

    In the next 2 years, it will increase to 12.10 lakhs

    Let the uniform annual rate of growth be r%

    According to the question;

    The Increased population after 2 years = The current population × (100 + r)/100 × (100 + r)/100

    ⇒ 12.10 = 10 × (100 + r)/100 × (100 + r)/100

    ⇒ (100 + r)2 = 12100

    ⇒ 100 + r = 110

    ⇒ r = 110 - 100 = 10%

  • Question 7/10
    1 / -0.25

    In a company, there are only two types of employees, workers, and officers. 35% of the employees are officers and the average monthly salary of an officer is ₹3,9000 more than the combined average monthly salary of an employee. What is the difference between the average monthly salaries of an officer and a worker?

    Solutions

    The correct answer is Option 4 i.e. Rs 60,000.

    Let the total number of employees = 100

    Number of workers = 65% of 100 = 65

    Number of officers = 35% of 100 = 35

    Let, the average monthly salary of officers and workers be x and y

    Now,

    ⇒ x = Average monthly salary + 39000

    ⇒ x = (35x + 65y)/100 + 39000

    ⇒ 100x = 35x + 65y + 390000

    ⇒ 65x = 65y + 390000

    ⇒ 65x - 65y = 390000

    ⇒ 65(x - y) = 390000

    ⇒ x - y = 60000

    Thus, the difference between the average salary of an officer and a worker is Rs.60000

  • Question 8/10
    1 / -0.25

    A works thrice as fast as B. If B can complete a work in 280 days independently, then find the number of days A and B can finish the work together.

    Solutions

    The correct answer is Option 4 i.e. 70.

    Efficiency of A : Efficiency of B = 3 : 1 and,

    Time taken by B = 280 days

    We know that,

    Work = Efficiency × Time

    Efficiency of B × Time of B = (Efficiency of A + B) × (Time taken by A and B together)

    ⇒ 1 × 280 = (3 + 1) × (Time taken by A and B together)

    ⇒ Time taken by A and B together = 280/4 = 70 days

    The time taken by A and B together is 70 days.

  • Question 9/10
    1 / -0.25

    The width of a rectangle is 2 m less than its length. If the perimeter of the rectangle is 68 m, then what is the length (in metres) of the rectangle?

    Solutions

    The correct answer is option 2 i.e. 18.

    Let, the length of rectangle be L meter.

    The width of the rectangle (b) = (L - 2) meter

    Perimeter of a rectangle = 2(l + b)

    ⇒ 2(l + b) = 68

    ⇒ L + L - 2 = 34

    ⇒ 2L = 36

    ⇒ L = 36/2 = 18 m

  • Question 10/10
    1 / -0.25

    A cone and a cylinder with equal radii have equal volumes. The ratio of their heights is:

    Solutions

    The correct answer is Option 4 i.e. 3 : 1.

    The volume of cone = 1/3 𝜋r12h1

    here, r1 = radius of cone, h1 = height of cone

    The volume of cylinder = 𝜋r22h2

    here, r2 = radius of cylinder, h2 = height of cylinder

    Given that,

    Volume of cone = volume of cylinder and,

    ⇒ r1 = r2

    ⇒ 1/3 𝜋r12h1 = 𝜋r22h2

    ⇒ h1/h2 = 3/1

    ⇒ h1 : h2 = 3 : 1

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