Verify mobile number to view the solution
Solutions
The correct answer is Option 1 i.e. Rs 396.
The surface area of the cylinder = 2πrh
Total area for leveling the ground = Number of revolutions × Surface area
The cost of leveling = Cost per unit × total area
Radius of the roller = 21/2 cm and, its length = 100 cm
Area covered by the roller in 1 revolution = 2πrh
⇒ 2 (22/7) (21/2) × 100 = 6600 cm2
Area covered by the roller in the 1200 revolution
⇒ 1200 × 6600 = 7920000 cm2 = 792 m2
The cost of leveling the ground
⇒ 792 × (50/100) = Rs.396