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RRB Group D 2025 Mix Test - 71
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RRB Group D 2025 Mix Test - 71
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  • Question 1/10
    1 / -0.33

    Directions For Questions

    The following pie chart gives the distribution of various students who were selected for IIT and the coaching institute they belonged to. Total number of selected students were 10,000. Read the chart and answer the questions:

    ...view full instructions


    If 10% of candidates who are selected with self studies moved to coaching A, What would be the ratio of candidates in self study group and in coaching A?

    Solutions

    The correct answer is option 2 i.e. 36 : 23.

    Total candidate who cleared from self studies = 40/100 × 10000 = 4000

    10% of them moved to coaching A i.e. 10/100 × 4000 = 400

    Total candidate who cleared from Coaching A = 19/100 × 10000 = 1900

    Hence, required ratio: (4000 - 400) : (1900 + 400)

    = 3600 : 2300

    = 36 : 23

  • Question 2/10
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    Area of the equilateral triangle is 49√3 m2 and the length of the rectangle is 6m more than the side of the equilateral triangle. If the breadth of the rectangle is 25 m, then find the area of the rectangle.

    Solutions

    The correct answer is Option 2 i.e. 500 m2.

    Area of the equilateral triangle = 49√3 m2

    √3/4 × a2 = 49√3

    a2 = 196

    a = 14 m

    Then Length of the rectangle = 14 + 6 = 20 m

    Area of the rectangle = 20 × 25 = 500 m2

  • Question 3/10
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    The diameter of a 100 cm long roller, is 21 cm. If it takes 1200 complete revolutions to level a playground then, find the cost of leveling it at 50 paise per square meter.

    Solutions

    The correct answer is Option 1 i.e. Rs 396.

    The surface area of the cylinder = 2πrh

    Total area for leveling the ground = Number of revolutions × Surface area

    The cost of leveling = Cost per unit × total area

    Radius of the roller = 21/2 cm and, its length = 100 cm

    Area covered by the roller in 1 revolution = 2πrh 

    ⇒ 2 (22/7) (21/2) × 100 = 6600 cm2

    Area covered by the roller in the 1200 revolution

    ⇒ 1200 × 6600 = 7920000 cm2 = 792 m2

    The cost of leveling the ground

    ⇒ 792 × (50/100) = Rs.396

  • Question 4/10
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    Find the value of 6√3(cosec 60° + tan 60°).

    Solutions

    The correct answer is option 3 i.e. 30.

    Calculate the value

    6√3(cosec 60° + tan 60°) 

    = 6√3(2/√3 + √3) = 6√3(5/√3) = 30

  • Question 5/10
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    If x2y + 1/(x2y) + y/x2 + x2/y = 28 and x4 + 1/x4 = 194, then what is the value xy15 + 1/(xy18) (Given x, y > 0)?

    Solutions

    The correct answer is option 2 i.e. 4.

    x4 + 1/x4 = 194

    Adding 2 on both the sides

    ⇒ x4 + 1/x4 + 2 = 196

    ⇒ (x2 + 1/x2)2 = 196

    ⇒ x2 + 1/x2 = 14

    And x2y + 1/(x2y) + y/x2 + x2/y = 28

    ⇒ x2y + x2/y + 1/(x2y) + y/x2 = 28

    ⇒ x2 (y + 1/y) + 1/x2 (y + 1/y) = 28

    ⇒ (x2 + 1/x2) (y + 1/y) = 28

    ⇒ 14 × (y + 1/y) = 28

    ⇒ y + 1/y = 2

    ⇒ y2 + 1 = 2y

    ⇒ y2 – 2y + 1 = 0

    ⇒ (y – 1)2 = 0

    ⇒ y = 1

    Substituting y = 1 in xy15 + 1/(xy18):

    xy15 + 1/(xy18) = x + 1/x

    To find x + 1/x:

    x2 + 1/x2 = 14

    Adding 2 on both sides:

    ⇒ x2 + 1/x+ 2 = 16

    ⇒ (x + 1/x)2 = 16

    ⇒ x + 1/x = 4

  • Question 6/10
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    A person bought a chair and a table together for Rs. 500. If he sells the chair at a loss of 10% and the table at a profit of 15%, then he gets neither profit nor loss. Find the cost price of the table.

    Solutions

    The correct answer is Option 2 i.e. Rs. 200.

    Let the cost price of the table = x

    And the cost price of the chair = 500 – x

    According to the question,

    (500 – x) × (100 – 10)/100 + x × 115/100 = 500

    500 × 9/10 – x × 9/10 + 23x/20 = 500

    4500 × 2/20 – 18x/20 + 23x/20 = 500

    5x/20 + 9000/20 = 500

    5x = 500 × 20 – 9000

    x = 1000/5

    x = 200

    Therefore, the cost price of the table = Rs. 200

  • Question 7/10
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    Let x = (633)24 - (277)38 + (266)54. What is the unit digit of x?

    Solutions

    The correct answer is option 4 i.e. 8.

    x = (633)24 - (277)38 + (266)54

    is of the form

    x = 34x - 74x + 2 + 6

    x = 1 - 9 + 6

    x = 7 - 9 [17 - 9] for unit digit

    x = 8

  • Question 8/10
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    A number, when divided by 108, leaves a remainder of 19. What will be the remainder when the same number is divided by 12?

    Solutions

    The correct answer is option 3 i.e. 7.

    Concept Used:

    Number = Divisor × Quotient + Remainder

    Explanation:

    According to the given question,

    The given number is 108Q + 19.

    Now, 108Q + 19 = 12 × 9 × Q + (12 + 7)

    ⇒ 12 × (9Q + 1) + 7

    Hence the remainder is 7.

  • Question 9/10
    1 / -0.33

    Two people P and Q started the work, P can complete the work in 18 days and Q can complete the work in 24 days. They both started working together, and after 6 days P left the job. What is the number of days required to complete the job?

    Solutions

    The correct answer is option 1 i.e. 16 days.

    Total work = LCM (24, 18) = 72 units

    The efficiency of P = 72/18

    ⇒ 4 units/day

    The efficiency of Q = 72/24

    ⇒ 3 units/day

    The total amount of work done in the first 6 days,

    ⇒ 6(4 + 3) = 42

    Work left = 72 - 42 = 30 units

    Number of days required by Q to complete the work = 30/3

    ⇒ 10 days

    Total number of days = 10 + 6 = 16 days

  • Question 10/10
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    The time taken by the train to cross x m platform A is two-thirds of the time taken by the train to cross (x + 150) m platform B. Find the speed of the train if the length of the train is 200 m.

    Solutions

    The correct answer is Option 4 i.e. Can’t be determined.

    Let the speed of the train be a.

    (200 + x)/a = 2/3 × (200 + x + 150)/a

    600 + 3x = 400 + 2x + 300

    x = 100

    (200 + 100)/a = 2/3 × (200 + 100 + 150)/a

    300/a = 300/a

    Can’t be determined.

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