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RRB JE 2025 Mix Test - 1
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RRB JE 2025 Mix Test - 1
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  • Question 1/10
    1 / -0.33

    The length of the perpendicular drawn from vertex A on the unequal side of an isosceles triangle ABC is 30 cm and the length of its equal sides is 34cm. What will be the area of ​​the triangle?

    Solutions

    The correct answer is option 1 i.e. 480 cm2.

    The perpendicular line from the vertex to the unequal side bisects the side

    Applying Pythagoras' theorem in the triangle,

    ⇒ AD2 = √(342 - 302)

    ⇒ AD= √(256) = 16 cm

    Unequal side of the triangle = (16 × 2) = 32 cm

    Area of a triangle = (1/2 × b × h)

    ⇒ (1/2) × 32 × 30

    ⇒ 480 cm2

  • Question 2/10
    1 / -0.33

    The area of the circular park is 5544 m2. There is a 7m wide path for running inside the park. Park owners decide to pave the running track. If the cost of paving Rs 12 per meter square then find the total cost of paving the running track of the park.

    Solutions

    The correct answer is option 4 i.e. Rs 20328.

    Area of circular park = πr2

    ⇒ 5544 = πr2

    ⇒ r2 = 5544/π = 1764 (where  π = 22/7)

    ⇒ r = √1764 = 42 m

    The path length is 7 m (given)

    Inner circle area (without including path area)

    Radius of inner circle = (42 - 7) m = 35 m

    Area2 = 22/7 × 35 × 35 = 3850 m2

    Total area of path = Area1 - Area2

    = (5544 - 3850) m2

    = 1694 m2

    Total cost for paving = 1694 × 12 

    = Rs 20328

  • Question 3/10
    1 / -0.33

    The difference between height and radius of the cylinder is 6 cm. The ratio of the radius and height of the cylinder is 4 : 5. Calculate the total surface area of the cylinder.

    Solutions

    The correct answer is Option 1 i.e. 2592π cm2.

    let the radius of the cylinder = 4x

    Let the height of the cylinder  = 5x

    Now 5x – 4x = 6, x = 6

    ∴ radius  = 4 × 6 = 24cm

    Height  = 5 × 6 = 30 cm

    Total surface area of cylinder  = 2π r(r + h)

    =2 × π × 24 (24 + 30)

    =π × 48 × 54 = 2592π cm2

  • Question 4/10
    1 / -0.33

    Which among the following options is equal to the value of sec A – cos A?

    Solutions

  • Question 5/10
    1 / -0.33

    Solutions

  • Question 6/10
    1 / -0.33

    Which of the following is equivalent to the given trigonometric expression?

    2 sin2 x cos2 x (1 + cos 4x)

    Solutions

    The correct answer is Option 4 i.e. (1 – cos 8x)/8.

    1 + cos 4x = 2 cos2 2x [∵ 1 + cos 2A = 2 cos2 A]

    2 sin2 x cos2 x (1 + cos 4x) = 2 sin2 x cos2 x × 2 cos2 2x

    ⇒ 4 sin2 x cos2 × cos2 2x

    ⇒ (2 sin x cos x)2 × cos2 2x

    ⇒ sin2 2x × cos2 2x [∵ 2 sin A cos A = sin 2A]

    ⇒ (2 sin22x cos22x)2/4

    ⇒ sin2 4x/4

    ⇒ (1 – cos 8x)/8 [∵ sin2 A = (1 – cos 2A)/2]

  • Question 7/10
    1 / -0.33

    The L.C.M. and H.C.F. of the two numbers are 300 and 50 respectively. If the sum of these two numbers is 250 then what is the difference between the two numbers?

    Solutions

    The correct answer is option 3 i.e. 50.

    H.C.F. of the two numbers = 50

    L.C.M. of the two numbers = 300

    Let the two numbers be a and b.

    LCM × HCF = Product of numbers

    300 × 50 = 15000

    ab = 15000

    a + b = 250

    (a - b)2 = (a + b)2 - 4ab

    ⇒ (a - b)2 = (250)2 - 4 × 15000

    ⇒ (a - b)2 = 62500 - 60000 = 2500

    a - b = 50

  • Question 8/10
    1 / -0.33

    Mohan and Bhagwat decided to play a game. They choose a number in their mind and told the number to the judge after that judge announces the lcm of the number and the sum of the number as 240 and 128 respectively. What is the HCF of those two numbers?

    Solutions

    The correct answer is option 3 i.e. 16.

    Let the H.C.F. of those two numbers be 'k'

    The first number would be = N1k

    The second number would be = N2k

    ⇒ N1k + N2k = 128

    ⇒ k(N1 + N2) = 128   (1)

    ⇒ N1N2k = 240

    ⇒ N1N2k = 24 × 3 × 5   (2)

    By (1) and (2)

    ⇒ k = 16

  • Question 9/10
    1 / -0.33

    If x + 1/(x - 4) = 8. Find the value of (x - 4)2 + 1/(x - 4)2.

    Solutions

    The correct answer is option 1 i.e. 14.

    Given:

    x + 1/(x - 4) = 8

    Formula used:

    a2 + b2 + 2ab = (a + b)2 ---- (1)

    Calculations:

    ⇒ x + 1/(x - 4) = 8

    Subtracting 4 from both sides, we get

    ⇒ (x - 4) + 1/(x - 4) = 8 - 4

    ⇒ (x - 4) + 1/(x - 4) = 4

    Using equation (1), we get

    ⇒ (x - 4)2 + 1/(x - 4)2 + 2 = 42

    ⇒ (x - 4)2 + 1/(x - 4)2 = 16 - 2 = 14

  • Question 10/10
    1 / -0.33

    If a = 53 and b = 13. Find the value of (a + b)2 - (a - b)2.

    Solutions

    The correct answer is option 3 i.e. 2756.

    Given:

    a = 53 and b = 13

    Formula used:

    (a + b)2 - (a - b)2 = 4ab ---- (1)

    Calculations:

    Using equation (1), we get

    ⇒ (a + b)2 - (a - b)2 = 4ab

    ⇒ 4 × 53 × 13 = 2756

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