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Solutions
The correct answer is option 1 i.e. 2
For the number to be divisible by 99, it should be divisible by 9 and 11
Divisibility by 9:
Sum of the digits should be divisible by 9
1 + x + 4 + x + 3 + 0 + y + 5 = 13 + 2x + y should be divisible by 9
Case I:
13 + 2x + y = 18
2x + y = 5
Case II:
13 + 2x + y = 27
2x + y = 14
x,y ≤ 5
2x + y + 13 ≤ 27
Divisibility of 11:
Sum of odd digits – Sum of even digits = 0 or Number divisible by 11
x + x + 0 + 5 – (1 + 4 + 3 + y) = 0 or divisible by 11
2x - y – 3 = 0 or divisible by 11
But maximum value 2x – y – 3 = 7 [∵ x,y ≤ 5]
∴ 2x – y = 3
Case I:
2x + y = 5
2x – y = 3
Adding both the equation
4x = 8
x = 2
Substituting in equation 2
4 – y = 3
∴ y = 1
In that case x/y = 2
Case II:
2x + y = 14
2x – y = 3
Adding both the equation
4x = 17
x = 17/4, Not possible [∵ x is a digit hence has to be a natural number]
So, x = 2 and y = 1
∴ x/y = 2/1 = 2