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RRB Group D 2025 Mix Test - 91
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RRB Group D 2025 Mix Test - 91
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  • Question 1/10
    1 / -0.33

    Directions For Questions

    Directions: Bar graph given below that shows the amount spent by a customer on different products. Study the bar graph and answer the question carefully.

    ...view full instructions


    Find the ratio between the amount spent on food to that of amount spent on cleaning products.

    Solutions

    The correct answer is option 1 i.e. 2 : 3

    Calculations:

    Amount spent on food products = 2000

    Amount spent on cleaning products = 3000

    Required ratio = 2000 : 3000 = 2 : 3

  • Question 2/10
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    If the diagonal of the cube is 212 then find the ratio of its volume to its total surface area.

    Solutions

    The correct answer is Option 1 i.e. 2 : 3.

    The diagonal of the cube = a3

    The diagonal of the cube = 212

    a3 = 2√(2 × 2× 3)

    a3 = 4√3

    a = 4

    Volume of cube = a3 = 43 = 64

    Total surface area = 6a2 = 6(4)2 = 6 × 16 = 96

    Required ratio = 64 : 96 = 2 : 3

  • Question 3/10
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    A sphere of a radius of 10 cm is cut into two pieces. Find the percentage increase in total surface area.

    Solutions

    The correct answer is Option 1 i.e. 50%.

    The surface area of the sphere = 4πr= 4π × 102

    Now

    The total surface area of the half-sphere = 3πr= 3π × 102

    Here, Ratio = The surface area of the sphere/(2 × The total area of the half-sphere)

    = 4π × 102/[2 × 3π × 102] = 2 : 3

    Difference = 3 - 2 = 1

    Hence, Percentage change = 1/2 × 100 = 50%

  • Question 4/10
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    In a triangle ABC, (sin A + sin B) = √3(cos A + cos B). What is the value of the ∠C?

    Solutions

    The correct answer is Option 2 i.e. 60°.

    We know that:

    sin A + sin B = 2 sin {(A + B)/2} cos{(A - B)/2}

    cos A + cos B = 2 cos {(A + B)/2} cos {(A - B)/2}

    Substituting these formulas in the given equation:

    ⇒ 2 sin {(A + B)/2} cos{(A - B)/2} = √3 [2 cos {(A + B)/2} cos {(A - B)/2}]

    ⇒ sin {(A + B)/2} = √3cos{(A + B)/2}

    ⇒ tan {(A + B) /2} = √3

    ⇒ (A + B)/2 = 60°

    ⇒ A + B = 120°

    Hence,

    ⇒ ∠C = 180° - (A + B) [∵ Angle Sum property of triangle]

    ⇒ ∠C = 60°

  • Question 5/10
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    If x = 2 then, find the value of x3 + 27x2 + 243x + 631.

    Solutions

    The correct answer is option 4 i.e. 1233.

    x3 + 27x2 + 243x + 631

    ⇒ x(x2 + 27x + 243) + 631

    Now, put the value of x = 2

    ⇒ 2(22 + 27 × 2 + 243) + 631

    ⇒ 2(4 + 54 + 243) + 631

    ⇒ 2(301) + 631

    ⇒ 602 + 631 = 1233

  • Question 6/10
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    If the cost price of a product is Rs 30 and it is sold at Rs 33.33, then what is the profit/loss percentage?

    Solutions

    The correct answer is option 4 i.e. 11.1%.

    Cost price = Rs 30

    Selling price = Rs 33.33

    Profit percentage = (Selling price - Cost price)/cost price × 100

    ⇒ (33.33 - 30)/30 × 100

    ⇒ 3.33/30 × 100

    ⇒ 11.1%

  • Question 7/10
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    Evaluate:

    20% of 300 - {40 ÷ 1/(2)-1}[5.64 + 0.36]2

    Solutions

    The correct answer is option 3 i.e. -660.

    20% of 300 - {40 ÷ 1/(2)-1}[5.64 + 0.36]2

    By using the BODMAS rule:

    = (20/100) × 300 - (40 ÷ 2)[6.00]2

    = 60 - 20 [36]

    = 60 - 720

    = -660

  • Question 8/10
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    An eight digit number of form 1x4x30y5 is divisible by 99. If both x and y are less than or equal to 5, then what is the value of x/y?

    Solutions

    The correct answer is option 1 i.e. 2

    For the number to be divisible by 99, it should be divisible by 9 and 11

    Divisibility by 9:

    Sum of the digits should be divisible by 9

    1 + x + 4 + x + 3 + 0 + y + 5 = 13 + 2x + y should be divisible by 9

    Case I:

    13 + 2x + y = 18

    2x + y = 5

    Case II:

    13 + 2x + y = 27

    2x + y = 14

    x,y ≤ 5

    2x + y + 13 ≤ 27

    Divisibility of 11:

    Sum of odd digits – Sum of even digits = 0 or Number divisible by 11

    x + x + 0 + 5 – (1 + 4 + 3 + y) = 0 or divisible by 11

    2x - y – 3 = 0 or divisible by 11

    But maximum value 2x – y – 3 = 7 [∵ x,y ≤ 5]

    ∴ 2x – y = 3

    Case I:

    2x + y = 5

    2x – y = 3

    Adding both the equation

    4x = 8

    x = 2

    Substituting in equation 2

    4 – y = 3

    ∴ y = 1

    In that case x/y = 2

    Case II:

    2x + y = 14

    2x – y = 3

    Adding both the equation

    4x = 17

    x = 17/4, Not possible [∵ x is a digit hence has to be a natural number]

    So, x = 2 and y = 1

    ∴ x/y = 2/1 = 2

  • Question 9/10
    1 / -0.33

    20 men building a wall at a rate of 10 hours per day can be completed in 12 days. What would be the number of days taken by 25 men at 6 hours per day to build it?

    Solutions

    The correct answer is option 4 i.e. 16.

    We know that, M1D1H1/W1 = M2D2H2/W2

    Where M1, M2 is the number of men, D1, D2 is the number of days, H1, H2 is the number of hours per day, and W1, W2 is the amount of work.

    Here work in both cases is the same.

    ⇒ 20 × 10 × 12 = 25 × 6 × D2

    ⇒ D2 = 16 days

  • Question 10/10
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    Two cars were running at the speed of 25 km/h and 35 km/h respectively. If a train crosses these cars in time 4 sec and 6.5 sec respectively, what would be the speed of the train?

    Solutions

    The correct answer is Option 1 i.e. 51 km/h.

    Let the speed of the train be x km/h.

    When the train crosses these cars it covers its own length.

    Distance = Speed(Time)

    Relative speed when train crosses 1st car = (x - 25) km/h

    Relative speed when train crosses 2nd car = (x - 35) km/h

    Time taken to cross 1st car = 4 sec = 4/3600 h

    Time taken to cross 2nd car = 6.5 sec = 6.5/3600 h

    According to question-

    ⇒ (x - 25)(4/3600) = (x - 35)(6.5/3600)

    ⇒ 4x - 100 = 6.5x - 227.5

    ⇒ 6.5x - 4x = 227.5 - 100

    ⇒ 2.5x = 127.5

    ⇒ x = 127.5/2.5 = 51 km/h

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