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RRB Technician (Grade-III) 2025 Mix Test - 21
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RRB Technician (Grade-III) 2025 Mix Test - 21
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  • Question 1/10
    1 / -0.33

    Directions For Questions

    Directions: Given bar graph shows the data of the number of students present in 3 classes 6, 7, and 8 on 2 days (Monday and Tuesday). Study the chart carefully and answer the following questions.

    ...view full instructions


    What is the average number of students present on Monday in Class 7th and 8th together?

    Solutions

    The correct answer is Option 1 i.e. 40.

    From the Bar graph:

    The average number of students present on Monday in Class 7th and 8th together 

    ⇒ [36 + 44]/2 = 40

  • Question 2/10
    1 / -0.33

    In a triangle ABC, AB = 8 cm and AC = 5 cm. What is true about the value of side BC?

    Solutions

    The correct answer is option 3 i.e. 3 < BC < 13.

    In any triangle, the length of a side is always greater than the difference of the other 2 sides and less than the sum of the other 2 sides.

    Here, AB = 8 cm and AC = 5 cm

    So,

    (8 – 5) < BC < (8 + 5)

    3 < BC < 13

    Hence, option 3 is correct

  • Question 3/10
    1 / -0.33

    What will come in place of question mark (?) in the following question?

    (0.25)4 × (0.125/0.5) × (0.5)8 = (0.5)? × 0.25

    Solutions

    The correct answer is option 1 i.e. 16.

    (0.25)4 × (0.125/0.5) × (0.5)8 = (0.5)? × 0.25

    ⇒ (0.5)8 × {(0.5)3/0.5} × (0.5)8=(0.5)? × (0.5)2

    ⇒ (0.5)(8 +3 -1 +8) = (0.5)(? + 2)

    ⇒18 = ? + 2

    ⇒ ? = 16

  • Question 4/10
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    The breadth of a rectangular plot is 40% more than its length. If the difference between the breadth and the length of that rectangle is 18 cm, what is the area of that rectangle?

    Solutions

    The correct answer is Option 1 i.e. 2835 cm2.

    The breadth of a rectangular plot is 40% more than its length

    Difference between the breadth and the length of that rectangle = 18 cm

    Let the length and breadth of the rectangle be l and b respectively

    Area of the rectangle = lb

    Bredth (b) = l + 40% of l = l + 2l/5 = 7l/5

    ⇒ b = 7l/5

    ATQ - 

    ⇒ b - l = 18 cm

    ⇒ 7l/5 - l = 18

    ⇒ (7l - 5l)/5 = 18

    ⇒ 2l = 90

    ⇒ l = 45 cm

    b = 7l/5 = 7(45)/5 = 63 cm

    Area of the rectangle = lb = 45(63) = 2835 cm2

  • Question 5/10
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    If 4y7858x4 is divisible by 24, find the smallest possible value of xy.

    Solutions

    The correct answer is option 4 i.e. None of these.

    4y7858x4 is divisible by 24, so it will be divisible by 8 and 3.

    Divisibility rule of 8: The last three numbers are zero or divisible by 8, the whole number is divisible by 8.

    8x4 is divisible by 8, x can be 2 or 6.

    If we put x = 6,

    4y785864 is divisible by 3.

    ⇒ 4 + y + 7 + 8 + 5 + 8 + 6 + 4 is divisible by 3, y can be 0.

    Hence xy = 0

    The lowest possible value will be 0.

  • Question 6/10
    1 / -0.33

    What is the value of the following trigonometric expression?

    tan 210° + cot 120° + sec 240° + sin 150°

    Solutions

    The correct answer is option 2 i.e. -3/2

    tan 210° = tan (180° + 30°) = tan 30° = 1/√3

    cot 120° = cot (180° - 60°) = - cot 60° = -1/√3

    sec 240° = sec (180° + 60°) = - sec 60° = -2

    sin 150° = sin (180° - 30°) = sin 30° = 1/2

    ⇒ tan 210° + cot 120° + sec 240° + sin 150° = 1/√3 – 1/√3 – 2 + 1/2

    ⇒ -3/2

  • Question 7/10
    1 / -0.33

    If a = 3 and b = -5 then find the value of 11a3 - 2b3 + 5a2b - 8ab2.

    Solutions

    The correct answer is option 3 i.e. -278.

    a = 3 and b = -5

    ⇒ 11a3 - 2b3 + 5a2b - 8ab2

    ⇒ 11(3)3 - 2(-5)3 + 5(3)2(-5) - 8(3)(-5)2

    ⇒ 297 + 250 - 225 - 600

    ⇒ 547 - 825

    ⇒ -278

  • Question 8/10
    1 / -0.33

    If a = 3 and b = -5 then find the value of 11a3 - 2b3 + 5a2b - 8ab2.

    Solutions

    The correct answer is option 3 i.e. -278.

    a = 3 and b = -5

    ⇒ 11a3 - 2b3 + 5a2b - 8ab2

    ⇒ 11(3)3 - 2(-5)3 + 5(3)2(-5) - 8(3)(-5)2

    ⇒ 297 + 250 - 225 - 600

    ⇒ 547 - 825

    ⇒ -278

  • Question 9/10
    1 / -0.33

    A man bought 40 apples for Rs. 224. How many apples should he sell at Rs. 49 if he wishes to earn 25% profit?

    Solutions

    The correct answer is option 3 i.e. 7.

    According to question,

    Cost price of each apple = 224 ÷ 40 = Rs. 5.60

    Selling price of each apple when selling at 25% profit = 5.60 × 1.25 = Rs. 7

    So, the man should sell 49 ÷ 7 = 7 apples at Rs. 49 to earn 25% profit.

  • Question 10/10
    1 / -0.33

    In a festive season, the rate of an article goes up by 20% due to which the sale of an article goes down by 12.5%. If the shopkeeper earned a net profit then find the percentage increase in the revenue of the shop.

    Solutions

    The correct answer is Option 2 i.e. 5%.

    Increase in rate of articles = + 20%

    Decrease in sale of an article = - 12.5%

    Revenue = Price × Sale

    Let, the initial price of an article = 5x

    The new price of an article = 6x

    Let, the initial sale of an article = 8y

    New sale of an article = 7y

    Initial revenue = 40xy

    New revenue = 42xy

    Change in revenue = New revenue - initial revenue = 2xy

    Percentage Increase in revenue = (change in revenue/initial revenue) × 100

    Percentage change in revenue = (2xy/40xy) × 100 = 5%

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