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RRB Group D 2025 Mix Test - 93
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RRB Group D 2025 Mix Test - 93
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  • Question 1/10
    1 / -0.33

    if x + 1/x = 3√3 then Find the value of x5 + 1/x5.

    Solutions

    The correct answer is option 1 i.e. 1797√3.

    x + 1/x = 3√3

    We know that,

    ⇒ x2 + 1/x2 = (x + 1/x)2 - 2

    ⇒ x2 + 1/x2 = 27 - 2 = 25

    And also

    ⇒ x3 + 1/x3 = (x + 1/x)3 - 3(x + 1/x)

    ⇒ (3√3)3 - 3(3√3)

    ⇒ 81√3 - 9√3 = 72√3

    Now multiplying both,

    ⇒ (x2 + 1/x2)(x3 + 1/x3) = x5 + 1/x5 + x + 1/x

    ⇒ (25)(72√3) =  x5 + 1/x5 + 3√3

    ⇒ 1800√3= x5 + 1/x5 + 3√3

    ⇒ x5 + 1/x5 = 1797√3

  • Question 2/10
    1 / -0.33

    A vendor marks up the price by 33.33% but still gets 20% profit after selling it at a specific discount. Find the discount percentage.

    Solutions

    The correct answer is option 1 i.e. 10%.

    Let the cost price is 300x

    After marking up the price by 33.33%,

    ⇒ 300x × (4/3) = 400x

    The profit is 20%

    Selling price = 1.2 × 300x ⇒ 360x

    Discount = 400x - 360x ⇒ 40x

    Discount% = 40x/400x × 100 ⇒ 10%

  • Question 3/10
    1 / -0.33

    Solve : √289 + 16 ( 8 ÷ 4 + 3 - 9 + 121)

    Solutions

    The correct answer is Option 4 i.e. None of these.

    ⇒ √289 + 16 ( 8 ÷ 4 + 3 - 9 + 121)

    ⇒ 17 + 16 (2 + 3 - 9 + 11)

    ⇒ 17 + 16 × 7

    ⇒ 129

  • Question 4/10
    1 / -0.33

    What is the second smallest number which upon dividing by 3, 5, 7 and 11 leaves a remainder of 2 in each case?

    Solutions

    The correct answer is option 2 i.e. 2312

    Smallest number divisible by 3, 5, 7 and 11 = LCM (3, 5, 7, 11)

    ⇒ 3 × 5 × 7 × 11 = 1155

    Second smallest number = 2 × 1155 = 2310

    To leave a remainder of 2, the number should be = 2310 + 2 = 2312

  • Question 5/10
    1 / -0.33

    2 men and 3 women can do a piece of work in 10 days while 3 men and 2 women can do the same work in 8 days. Then find in how many days 3 men and 5 women can do the same work.

    Solutions

    The correct answer is option 3 i.e. 6.45 days.

    2 men and 3 women can do a piece of work in 10 days while 3 men and 2 women can do the same work in 8 days

    So, 

    Total work = total person × total time

    (2M + 3W) × 10 = (3M + 2W) × 8 

    ⇒ M/W = 7/2

    So, the total work = (2M × 3W) × 10 = (2 × 7 + 3 × 2) × 10 = 200 unit

    3 men and 5 women can do the same work = 200/(3 × 7 + 5 × 2) = 200/31 = 6.45 days

  • Question 6/10
    1 / -0.33

    Shri, Shankar, and Sabri started a business. Shri invested Rs.1000 for 8 months, Shankar invested Rs.1200 for 5 months, and Sabri invested Rs.800 for 10 months. If the total profit is Rs.4400 then what is the difference between the profit of Shankar of Shri?

    Solutions

    The correct answer is option 4 i.e. Rs.400.

    Effective investment of Shri = 8 × 1000 = Rs.8000

    Effective investment of Shankar = 5 × 1200 = Rs.6000

    Effective investment of Sabri = 10 × 800 = Rs.8000

    Share of Shri = 8000/(8000 + 6000 + 8000) = 4/11

    Share of Shankar = 6000/(8000 + 6000 + 8000) = 3/11

    Difference between the share of Shri and Shankar

    ⇒ 4/11 - 3/11 = 1/11

    ⇒ (1/11) × 4400 = 400

  • Question 7/10
    1 / -0.33

    In a village election, three candidates Ram, Shyam, and Manoj participated. The total no of votes cast by villagers was 8000 votes. Candidate Manoj secured 20% of total votes which were later considered invalid as he dropped out of election campaign. If candidate Ram got 60% of the valid votes, how many votes did Shyam receive?

    Solutions

    The correct answer is Option 2 i.e. 2560.

    The total number of votes cast by villagers was 8000 votes.

    As 20% of votes which Manoj received are invalid, the total number of valid votes remaining is 80% votes.

    ⇒ 8000 × 0.8 = 6400 votes.

    Since candidate Ram received 60% of valid votes, Shyam must have received the remaining 40% of total valid votes.

    ⇒ 6400 × 0.4 = 2560 votes.

  • Question 8/10
    1 / -0.33

    A natural number N leaves remainder of 1 when it is divided by 2, 3, 4, 5 or 7. Find the number of possible values of N if N < 10000.

    Solutions

    The correct answer is option 3 i.e. 24

    Such a number can be found out if we take LCM of all given number and add 1 to it.

    N = n × LCM of (2, 3, 4, 5 and 7) + 1 , where n = 0, 1, 2, 3 etc.

    LCM of (2, 3, 4, 5 and 7) = 420

    N = n × 420 + 1

    Minimum value of n = 0

    Maximum value of n (N < 10000),

    n × 420 + 1 < 10000

    420n < 9999

    n < 23.8 or n can be 23

    Number of values = (0, 23) = 24

  • Question 9/10
    1 / -0.33

    What is the fourth proportional to 189, 273, and 153?

    Solutions

    The correct answer is option 3 i.e. 221.

    Let's assume x is the fourth proportion of 189, 273, and 153.

    189 : 273 :: 153 : x

    ⇒ 189x = 273 × 153

    ⇒ x = (273 × 153)/189

    ⇒ x = 221

  • Question 10/10
    1 / -0.33

    What will be the unit digit of 12 × 33 × 75 × 542 × 183 × 64?

    Solutions

    The correct answer is Option 4 i.e. 0.

    For the expression 12 × 33 × 75 × 542 × 183 × 64 

    12 × 75 will have the unit digit as 0. Thus the expression will also have a unit digit as 0.

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