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SSC Selection Post-XIV 2026 (Matric) Aptitude Test - 1
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SSC Selection Post-XIV 2026 (Matric) Aptitude Test - 1
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  • Question 1/10
    2 / -0.5

    Three pipes A, B, and C can fill a cistern in 138 hours. After working together for 46 hours, C is closed, and A and B can fill the remaining part in 138 hours. Find the number of hours taken by C alone to fill the cistern.

    Solutions

    The correct answer is option 1 i.e. 414.

    Three pipes A, B, and C can fill a cistern in 138 hours

    Total work = worker × efficiency

    According to the question

    ⇒ 138 × (A + B + C) = 46 × (A + B + C) + 138 × (A + B)

    ⇒ 92 × (A + B + C) = 138 × (A + B)

    ⇒ 92 C = 46 × (A + B)

    ⇒ C/(A + B) = 1/2

    ⇒ So, C/(A + B + C) = 1/3

    Total capacity of tank = 3 × 138 = 414 units

    Hence, the time taken by C alone to fill the tank = 414/1 = 414 hours

  • Question 2/10
    2 / -0.5

    Arvind works 4 times as fast as Suresh. If Suresh can complete a work in 20 days alone, then find the number of days in which Arvind and Suresh can together finish the work.

    Solutions

    The correct answer is Option 4 i.e. 4.

    Arvind works 4 times as fast as Suresh.

    Time taken by Suresh = 20 days

    ⇒ Total work = Efficiency × Time

    Let the efficiency of Suresh be 1 unit/day

    ⇒ Efficiency of Arvind = 4 unit/day

    ⇒ Total work = 1 × 20 = 20 units

    Work done by Arvind and Suresh in a day = 4 + 1 = 5 units

    Time taken by Arvind and Suresh to complete the same work = 20/(4 + 1) = 20/5 = 4 days.

  • Question 3/10
    2 / -0.5

    A shopkeeper marks up the price of an article by 20%. He then gives a discount of 25% on it. By what percent should he increase his selling price so that he reaches a condition of no profit, no loss?

    Solutions

    The correct answer is Option 1 i.e. 11.11%.

    Let Cost price = 100

    Marked price = 100 + 20% of 100 = 120

    Discount per cent = 25%

    Selling price = (100 - 25) % of 120 = 90

    Selling price for no profit, no loss = 100

    Increase required = 100 - 90 = 10

    Hence,

    Percentage increase = (10/90) × 100 = 11.11%

  • Question 4/10
    2 / -0.5

    If the perimeter of a regular hexagon is 684 cm, then find the area of the hexagon.

    Solutions

  • Question 5/10
    2 / -0.5

    Jehangir had to cover a distance of 90 km in an hour. During the first 25 minutes, he traveled at a speed of 15.2 meters per second. How many meters did Jehangir cover per second during the remaining period to reach his destination just in time?

    Solutions

    The correct answer is option 3 i.e. 32.

    Speed = Distance/time

    In the first 25 minutes, he travelled the distance with a speed of 15.2 m/s = 25 × 60 × 15.2 = 22800 meters = 22.8 km

    The remaining distance = 90 km - 22.8 km = 67.2 km

    Hence, this distance covered by him in 35 minutes with a speed of = 67.2/35 × (1000/60) = 32 meters/second

  • Question 6/10
    2 / -0.5

    The average of 29 observations is 40. If the average of the first 15 observations is 38, and that of the last 15 observations is 45, then the 15th observation is:

    Solutions

    The Correct answer is Option 3 i.e. 85.

    Average = Sum of observations/Number of observations

    Sum of 29 observations = 29 × 40 = 1160

    Sum of first 15 observations = 15 × 38 = 570

    Sum of last 15 observations = 15 × 45 = 675

    Hence, 15th observation will be = (570 + 675) - 1160

    ⇒ 1245 - 1160 = 85

  • Question 7/10
    2 / -0.5

    A grocer has a sale of ₹8,435, ₹8,927, ₹8,855, ₹9,230 and ₹8,562 in 5 consecutive weeks. How much sale must he have in the 6th week so that he gets an average sale of ₹8,500?

    Solutions

    The correct answer is Option 3 i.e. ₹6991.

    Let the sale for the 6th week be Rs. x

    Average = Sum of observations/Number of observations

    Now,

    ⇒ 8500 = (8435 + 8927 + 8855 + 9230 + 8562 + x)/6

    ⇒ 8500 × 6 = 44009 + x

    ⇒ 51000 = 44009 + x

    ⇒ x = 51000 - 44009

    ⇒ x = 6991

    Hence, the sale required for the 6th week is Rs 6,991

  • Question 8/10
    2 / -0.5

    The selling price of a desktop is 9 times of the profit earned on selling this desktop. What is the profit percentage?

    Solutions

    The correct answer is option 2 i.e. 12.5%

    Profit = Selling price - Cost price

    Profit% = (Profit/Cost price)

    According to the question;

    ⇒ Selling price = 9 × (Selling price - Cost price)

    ⇒ SP = 9SP - 9CP

    ⇒ 9 CP = 8 SP

    ⇒ CP/SP = 8/9

    Let the CP and SP be 8x and 9x.

    Profit = 9x - 8x = x

    Required profit percentage = (x/8x) × 100 = 12.5%

  • Question 9/10
    2 / -0.5

    In a race of 1000 m, John beats Khan by 120 m. If the speed of John is 40 km/h, then the speed of Khan is:

    Solutions

    The correct answer is Option 4 i.e. 35.2 km/h.

    Distance covered by John = 1000 m

    Distance covered by Khan = 1000 - 120 = 880 m

    Speed of John = 40 km/hr = 40 × 5/18 = (20 × 5)/9 = 100/9 m/sec

    Time taken by John = 1000/(100/9) = 90 sec

    Speed of John = (880/990) × 18/5 = 35.2 km/hr.

  • Question 10/10
    2 / -0.5

    A sum of Rs. 8000 becomes Rs. 21520 when invested in a scheme of simple interest. If the annual rate of interest and the number of years for which the sum was invested are the same, then what is the annual rate of interest?

    Solutions

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