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SSC Selection Post-XIV 2026 (Graduation) Aptitude Test - 1
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SSC Selection Post-XIV 2026 (Graduation) Aptitude Test - 1
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  • Question 1/10
    2 / -0.5

    Which percentage discount is greater among the following.

    (1) Two consecutive discounts of 12% and 18%

    (2) A discount of 27.5%

    Solutions

    The correct answer is option 3 i.e. (1) is greater by 0.34%.

    (1) Let the cost price of the article be 100 units.

    After applying a discount of 12%

    ⇒ 100 × (100 - 12)/100 = 88

    After applying a discount of 18%

    ⇒ 88 × (100 - 18)/100 = 72.16

    Total discount: 100 - 72.16 = 27.84%

    (2) A discount of 27.5%

    (1) is greater than (2) by 0.34%

  • Question 2/10
    2 / -0.5

    A hole in a tank can empty the tank in 5 hours so the owner upgraded the pipe, now the new pipe can fill the tank in 3 hours only. How many hours extra would it take to fill the tank compared to when the tank has no hole?

    Solutions

    The correct answer is option 4 i.e. 4.5.

    Total quantity to be filled in the tank = LCM(3, 5) = 15 units

    ⇒ Efficiency of new pipe = 15/3 = 5 units

    ⇒ Efficiency of the hole = 15/5 = -3 units

    Total work in 1 hour = 5 - 3 = 2 units

    Total number of hours = 15/2 = 7.5 hours

    Number of hours when there is no hole = 3 hours

    ⇒ 7.5 - 3 = 4.5 hours

  • Question 3/10
    2 / -0.5

    An equilateral triangular prism has the side of the base and the height in the ratio of 1 : √3. If the volume of the prism is 48 cm3, what is the length of the side of the base? (in cm)

    Solutions

    The correct answer is Option 2 i.e. 4.

    Let the length of the side of the equilateral triangle be x cm

    ∴ Height of prism = √3x

    Volume of prism = √3/4 × side2 × Height

    ⇒ 48 = √3/4 × x2 × (√3)x

    ⇒ 64 = x3

    ⇒ x = 4 cm

  • Question 4/10
    2 / -0.5

    Solutions

  • Question 5/10
    2 / -0.5

    If O is the ortho centre of ΔABC and ∠BOC = 100°, the measure of ∠BAC is?

    Solutions

    The correct answer is option 3 i.e. 80°.

    O is the orthocentre of ΔABC

    And

    ∠BOC = 100°

    In the figure:

    ∠OPA = ∠OQA = 90°

    And

    ∠BOC = ∠POQ = 100°

    In quadrilateral APOQ:

    ∠APO + ∠POQ + ∠OQA + ∠ QAP = 360°

    ⇒ 90° + 100° + 90° + ∠QAP = 360°

    ⇒ ∠QAP = 360° – 280° = 80°

  • Question 6/10
    2 / -0.5

    How many factors of 63 × 154 × 182 have a number of factors of the format 2n + 1 where 'n' is any whole number?

    Solutions

    The correct answer is option 4 i.e. 54.

    ⇒ 63 × 154 × 182

    ⇒ 23 × 33 × 34 × 54 × 22 × 34

    ⇒ 25 × 311 × 54

    All perfect squares have odd factors.

    ⇒ (22)2 × (32)5 × (52)2

    The number of factors of the given number as we have converted the real number into the nearest square.

    ⇒ Number of factors = (2 + 1)(5 + 1)(2 + 1)

    ⇒ 3 × 6 × 3

    ⇒ 54

  • Question 7/10
    2 / -0.5

    A shopkeeper sold two articles for Rs. 9831 each. On one, he gained 13% and on the other, he lost 13%. What is the overall percentage gain or loss?

    Solutions

    The correct answer is Option 3 i.e. 1.69% loss.

    Cost Price = Selling Price × 100/(100 + profit %)

    Cost Price = Selling Price × 100/(100 - loss %)

    The cost price of the first article(gain is 13%) = (100 × 9831)/113 = 8700

    The cost price of the second article(loss is 13%) = (100 × 9831)/87 = 11300

    So,

    Total cost price of both the articles = 8700 + 11300 = 20000

    Total selling price = 9831 × 2 = 19662

    ⇒ Loss = 20000 - 19662 = 338

    Loss% =  (Loss)/Cost price × 100

    ⇒ % loss = (338/20000) × 100 = 1.69

  • Question 8/10
    2 / -0.5

    If 3x + 2 - 3x = 72, find the value of x2 + 2x + 2.

    Solutions

    The correct answer is option 3 i.e. 10.

    Given:

    3x + 2 - 3x = 72

    Concept used:

    Am + n = Am.An ------ (1)

    Ax = Ay then x = y because the base of the number is the same. ------ (2)

    Calculations:

    Using concept (1) in the given equation

    ⇒ 3x.32 -  3x = 72

    ⇒ 3x (9 - 1) = 72

    ⇒ 3x × 8 = 72

    ⇒ 3x = 72/8

    ⇒ 3x = 9

    ⇒ 3x = 32

    Using concept (2), we get

    ⇒ x = 2

    ⇒ x2 + 2x + 2. ----- (3)

    Put the value of x in equation (3)

    ⇒ 4 + 4 + 2 = 10

  • Question 9/10
    2 / -0.5

    Arpit covers a distance in 3.5 hours, with a speed of 12 km/hr in the first half and 15 km/hr in the second half while his sister Arpita covers a distance in 4 hours, with a speed of 18 km/hr in the first half and 20 km/hr in the second half then, find the one-third of the total distance covered by both Arpit and Arpita.

    Solutions

    The correct answer is Option 3 i.e. 41 km.

    Concept:- If a person covers a distance in t hours, with the speed of p km/hr in the first half and with the speed of q km/hr in the second half, then the total distance D covered by him is

    D = 2 × t × (p × q)/(p + q)

    Now, according to the question

    Distance covered by Arpit

    D1 = 2 × 3.5 × (12 × 15)/(12 + 15)

    ⇒ D1 = 1260/27

    ⇒ D1 = 46.66 or 47 km

    Distance covered by Arpita

    D2 = 2 × 4 × (18 × 20)/(18 + 20)

    ⇒ D2 = 2880/38

    ⇒ D2 = 75.78 or 76 km

    Total distance = D1 + D2 = 47 + 76 = 123

    one third of 123 = 1/3 × 123 = 41 km

  • Question 10/10
    2 / -0.5

    Write the following in the correct descending order.

    25/49, 5/8, 12/25, 78/155

    Solutions

    The correct answer is option 3 i.e. 5/8 > 25/49 > 78/155 > 12/25.

    Simplifying the given fractions,

    We could observe that,

    5/8 = 0.625

    25/49 = 0.510

    78/155 = 0.503

    12/25 = 0.48

    So, the correct descending order = 5/8 > 25/49 > 78/155 > 12/25

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