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SSC GD 2026 Aptitude Test - 6
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SSC GD 2026 Aptitude Test - 6
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  • Question 1/10
    2 / -0.5

    The salaries of a father, mother, and daughter are in the ratio 2 : 3: 5. What will be the ratio of their salaries if there was an increase of 15%, 10%, and 20%, respectively?

    Solutions

    The correct answer is option 2 i.e. 23: 33: 60.

    Let the salaries of a father, mother, and daughter be 2x, 3x, and 5x respectively.

    The increased salary of father = 2x × 1.15 = 2.3x

    The increased salary of mother = 3x × 1.1 = 3.3x

    The increased salary of daughter = 5x × 1.2 = 6x

    Hence, the required ratio = 2.3x : 3.3x : 6x = 23 : 33 : 60

  • Question 2/10
    2 / -0.5

    Two taps A and B can fill a bathtub in 42 minutes and 48 minutes respectively. If the drain valve is open they can together fill in 50 minutes. Find the time in which the valve of drain can empty the bathtub. (approx.)

    Solutions

    The correct answer is Option 1 i.e. 40.58 minutes.

    Tap A can fill the bathtub in 42 minutes.

    Part of a bathtub filled by tap A in 1 minute = 1/42

    Tap B can fill the bathtub in 48 minutes.

    Part of a bathtub filled by tap B in 1 minute = 1/48

    Let’s assume that the drain pipe can empty the bathtub in x minutes.

    Part of bathtub emptied by the outlet pipe in 1 minute = 1/x

    According to the question - 

    ⇒ (1/42 + 1/48 - 1/x) = 1/50

    ⇒ 1/x = 1/42 + 1/48 - 1/50

    ⇒ 1/x = (200 + 175 - 168)/8400

    ⇒ 1/x = 207/8400

    ⇒ x = 8400/207 = 40.5797

    which is equal to 40.58 minutes

  • Question 3/10
    2 / -0.5

    Solutions

  • Question 4/10
    2 / -0.5

    If 45% of Ram’s money is added to 50% of Soham’s money, then the total amount will be 86% of Soham’s money. What percentage of Ram’s money did Soham have?

    Solutions

    The correct answer is Option 3 i.e. 125%.

    45% of Ram’s money is added to 50% of Soham’s money

    ⇒ 45% × Ram + 50% × Soham = 86% × Soham

    ⇒ 45 × Ram + 50 × Soham = 86 Soham

    ⇒ 45 × Ram = 86 × Soham - 50 × Soham

    ⇒ 45 × Ram = 36 × Soham

    ⇒ Ram/Soham = 36/45 = 4/5

    ⇒ Ram = 4/5 × Soham

    So,

    Percentage = Soham/(4/5 × Soham) × 100

    ⇒ 5/4 × 100 = 25 × 5 = 125%

  • Question 5/10
    2 / -0.5

    The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is:

    Solutions

    The correct answer is Option 2 i.e. 12 years.

    The average age of 30 students in a class = 12 years

    The average age of a group of 5 of the students = 10 years

    The average age of another group of 5 of them = 14 years

    According to the question,

    The average of the remaining students = (30 × 12 - 5 × 10 - 14 × 5)/20 = 240/20 = 12 years

  • Question 6/10
    2 / -0.5

    How much should we add to each of 7 and 9 so that the ratio of the two numbers thus formed is 13: 14.

    Solutions

    The correct answer is option 4 i.e. 19.

    Let the number that needs to be added to both 7 and 9 = x

    So, (7 + x)/(9 + x) = 13/14

    ⇒ 98 + 14x = 117 + 13x

    ⇒ x = 19

    So, we should add 19 to each of 7 and 9.

  • Question 7/10
    2 / -0.5

    A person first increases the price of a commodity by 8% and then he announces a discount of 18% The actual discount (in%) on the original price is:

    Solutions

    The correct answer is option 1 i.e. 11.44.

    Let the original price of the commodity be 100x

    The new price = 100x + (8/100) × 100x = 100x + 8x = 108x

    Discount = 18%

    The discount amount = (18/100) × 108x = 19.44x

    Final selling price = 108x - 19.44x = 88.56x

    Discount amount = 100x - 88.56x = 11.44x

    Discount percentage = (11.44x /100x) × 100 = 11.44%

    Therefore, the actual discount on the original price is 11.44%.

  • Question 8/10
    2 / -0.5

    Find the product:

    0.5 × 0.05 × 0.005 × 500

    Solutions

    The correct answer is option 1 i.e. 0.0625.

    0.5 × 0.05 × 0.005 × 500

    = 5/10 × 5/100 × 5/1000 × 500

    = (5 × 5 × 5 × 500)/(10 × 100 × 1000)

    = (5 × 5 × 5 × 5)/(10 × 100 × 10)

    = (625)/(10000) = 0.0625

  • Question 9/10
    2 / -0.5

    A fruit seller has 10 kg of apples and 5 kg of grapes. The price of 1 kg of apples is ₹94.50 and that of grapes is ₹105. He sold all the fruits with him. What is the average amount (in ₹) received by the fruit seller?

    Solutions

    The correct answer is option 3 i.e. 98.

    Total value of apples = 10 × 94.50 = 945

    Total value of grapes = 5 × 105 = 525

    Total amount = 945 + 525 = 1470

    Total quantity = 10 + 5 = 15 kg

    Average amount = 1470/15 = ₹98/kg

  • Question 10/10
    2 / -0.5

    A train, 1775 metres long is running at a speed of 133 km/hr. How many seconds will it take to cross a 1675 metres long train running in the same direction at a speed of 103 km/hr?

    Solutions

    The correct answer is Option 1 i.e. 414.

    Relative speed = 133 - 103 = 30 × 5/18 = 25/3 m/s

    Total distance to be covered = 1775 + 1675 = 3450 m

    Time taken to cross = 3450/(25/3) = 414 seconds

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