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SSC CGL 2026 Aptitude Test - 3
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SSC CGL 2026 Aptitude Test - 3
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  • Question 1/10
    2 / -0.5

    Pankaj, Meera, and Ashok invest ₹41,000, ₹39,000, and ₹84,000, respectively, to start a business. At the end of the year, the total profit earned is ₹49,200. 29% of the total profit earned is given to charity, and the rest is divided among them in the ratio of their investments. What will be the share of Ashok (in ₹)?

    Solutions

    The correct answer is Option 4 i.e. 17,892.

    Profit ∝ Investment

  • Question 2/10
    2 / -0.5

    On selling a wardrobe at ₹3,437, the value of gain is 75% more than the value of loss incurred on selling it at ₹3,338. In order to gain 50%, find the selling price (in ₹).

    Solutions

  • Question 3/10
    2 / -0.5

    The ratio of the number of boys and girls in a school is 3 : 4. If the number of boys increases by 10% and the number of girls increases by 15%, what will be the new ratio of the number of boys to the number of girls?

    Solutions

    The correct answer is option 3 i.e.

    The ratio of the number of boys and girls in a school = 3 : 4

    Let the number of boys and girls be 3x and 4x respectively.

    According to the question;

    The new ratio of boys and girls = (3x × 110)/(4x × 115) = 33/46

  • Question 4/10
    2 / -0.5

    Solutions

  • Question 5/10
    2 / -0.5

    Jitesh sold an article at a loss of 11%. If he had bought the item at 5% less and had sold it for ₹739 more, then he would have gained 20%. Find the cost price (in ₹) of the article.

    Solutions

  • Question 6/10
    2 / -0.5

    The mean proportional between 0.04 and 0.36 is:

    Solutions

    The correct answer is option 4 i.e. 0.12.

    Mean proportional between a and b = √ab

    = √(0.04 × 0.36)

    = 0.2 × 0.6 = 0.12

  • Question 7/10
    2 / -0.5

    When 1272, 2636, and 4209 are divided by the greatest number x, the remainder in each case is y. What is the value of (3x − 14y)?

    Solutions

    The correct answer is Option 2 i.e. -65.

    The greatest number = x = HCF [(2636 - 1272), (4209 - 2636), (4209 - 1272)]

    ⇒ x = HCF(1364, 1573, 2937)

    ⇒ x = 11

    Now,

    ⇒ 1272 ÷ 11 ⇒ Remainder = 7 = y

    ⇒ (3x - 14y) = 3 × 11 - 7 × 14 = -65

  • Question 8/10
    2 / -0.5

    ABCD is a trapezium in which AB || DC, and E and F are the midpoints of the diagonals AC and BD, respectively. If AB = 30 cm, BC = 20 cm, DC = 86 cm, and AD = 84 cm, then what is the length (in cm) of EF?

    Solutions

  • Question 9/10
    2 / -0.5

    Due to a decrease in manpower, the production in a factory decreased by 12%. By what percentage (rounded off to two decimal places) should the working hours be increased to restore the original production?

    Solutions

  • Question 10/10
    2 / -0.5

    P is any point inside the rectangle ABCD. If PA = 94 cm, PB = 61 cm, and PC = 67 cm, then the length of PD (in cm) is:

    Solutions

    The correct answer is Option 3 i.e. 98.

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