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SSC GD 2026 Aptitude Test - 7
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SSC GD 2026 Aptitude Test - 7
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  • Question 1/10
    2 / -0.5

    Simplify: [(12/5 + 13/40) × (500 - 20 × 5)] ÷ [(13/3 + 1/9 ÷ 12/27) ÷ (15 - 7/4)]  ÷ [(218 × 159)/121]

    Solutions

    The correct answer is Option 1 i.e. 11.

    [(12/5 + 13/40) × (500 - 20 × 5)] ÷ [(13/3 + 1/9 ÷ 12/27) ÷ (15 - 7/4)]  ÷ [(218 × 159)/121]

    ⇒ [(109/40) × (500 - 100)] ÷ [(13/3 + 1/4) ÷ (53/4)] ÷ [(218 × 159)/121]

    ⇒ [(109/40) × (400)] ÷ [(55/12) ÷ (53/4)] ÷ [(218 × 159)/121]

    ⇒ [1090] ÷ [55/159] ÷ [(218 × 159)/121]

    ⇒ [1090] × [159/55] × [121/(218 × 159)]

    ⇒ 121/11 = 11

  • Question 2/10
    2 / -0.5

    A sphere of a radius of 10 cm is cut into two pieces. Find the percentage increase in total surface area.

    Solutions

    The correct answer is Option 1 i.e. 50%.

    The surface area of the sphere = 4πr= 4π × 102

    Now

    The total surface area of the half-sphere = 3πr= 3π × 102

    Here, Ratio = The surface area of the sphere/(2 × The total area of the half-sphere)

    = 4π × 102/[2 × 3π × 102] = 2 : 3

    Difference = 3 - 2 = 1

    Hence, Percentage change = 1/2 × 100 = 50%

  • Question 3/10
    2 / -0.5

    A shopkeeper purchased 15 dozen eggs for Rs 54 per dozen and sold them at 5 for Rs 23.75. Find his profit.

    Solutions

    The correct option is 2 i.e Rs 45

  • Question 4/10
    2 / -0.5

    There are two mixture of equal volume. One mixture contains 60% milk and the rest is water and another mixture contains 80% milk and 20% water. If these mixtures mixed and make a new mixture, find the percentage of milk in a new mixture

    Solutions

    The correct option is 2 i.e 70%.

    Understanding Application

    A complete mixture contains

    100% volume.

    The percentage amount of milk in a mixture

    = (amount of milk×100)/total mixture.

    One mixture contains 60% milk.

    Rest water = 100% - 60%

    = 40%

    Another mixture of contains

    = 80% of milk

    And water = 20%

    Let the volume of each mixture

    = 100L.

    In the first mixture,

    The amount of milk = 100×60/100

    = 60 L

    The amount of water = 40 L

    In the second mixture,

    The amount of milk = 100×80/100

    = 80 L

    The amount of water = 20 L

    If these two mixture is mixed, the total volume of the new mixture is 200 L 

    And the amount of milk = 60 + 80

    = 140

    Percentage of milk in new mixture

    = (140×100)/200 = 70%.

  • Question 5/10
    2 / -0.5

    Rs. 350 is to be distributed among three persons A, B and C. A is 8 years older than B and 17 years older than C. The Difference in money received by A and B is 4 times their age difference and the difference in money received by B and C is twice their age difference. Find the amount received by B.

    Solutions

    The correct answer is Option 3 i.e. Rs. 112.

    A is 8 years older than B and 17 years older than C

    So,

    The age difference of A and B = 8 years

    Age difference of B and C = 17 – 8 = 9 years

    The difference in money received by A and B is 4 times of their age difference and difference of money received by B and C is twice of their age difference

    Suppose Money received by A = Rs. X

    So,

    Money received by B = X – 4 × 8 = Rs. (X – 32)

    And,

    Money received by C = (X – 32) – 2 × 9 = Rs. (X – 50)

    Total money = Rs. 350

    So,

    X + X – 32 + X – 50 = 350

    ⇒ 3X = 432

    ⇒ X = 144

    Hence,

    Money received by B = X – 32 = Rs. 112

  • Question 6/10
    2 / -0.5

    2 trains P and Q running in opposite directions cross each other in 30 seconds. The length of train Q is half of the length of train P. Speeds of trains P and Q are 90 km/h and 72 km/h respectively. If the train Q crosses a bridge in 32 seconds then find the length of the bridge.

    Solutions

    The correct answer is Option 3 i.e. 190 meters

    Speeds of trains P and Q are 90 km/h and 72 km/h respectively.

    Converting them to m/s:

    90 × 5/18 = 25 m/s

    72 × 5/18 = 20 m/s

    So, relative speed when running in opposite directions = 25 + 20 = 45 m/s

    Suppose the lengths of trains P and Q are ‘2x’ and ‘x’ meters.

    So,

    ⇒ (2x + x)/45 = 30

    ⇒ 3x = 1350

    ⇒ x = 450

    Hence, length of train B = 450 m

    Now, suppose length of bridge = a meter

    So,

    ⇒ (450 + a)/20 = 32

    ⇒ 450 + a = 640

    ⇒ a = 190

    Hence, length of bridge = 190 meters

  • Question 7/10
    2 / -0.5

    Two pipes are filling a tank whereas a leak at a height that is equal to 3/5th of the height of the tank empties the tank. The pipes filling tank can fill at 15 minutes and 20 minutes respectively. Due to this leak, it takes 4/7 minutes more than the usual time to fill the tank. What is the time taken by the leak to empty the portion of the tank above it? (in minutes)

    Solutions

    The correct answer is option 4 i.e. 24

    Time taken by two pipes alone to fill the tank = (1/15 + 1/20) - 1 = 60/7 minutes

    But the time difference arises only for filling the 2/5th of the tank above the leak

    Let the time taken by the leak to empty the portion above it be x minutes

    Time taken by two pipes to fill 2/5th of the tank = 2/5 × 60/7 = 24/7 minutes

    Time taken when also leak is opened

    {1/(24/7) – 1/x} - 1 = Original time + 4/7

    (7/24 – 1/x) - 1 = 24/7 + 4/7

    24x/(7x – 24) = 4

    24x = 28x – 96

    96 = 4x

    x = 24 minutes

  • Question 8/10
    2 / -0.5

    A man travels for 5 hr at the rate of 4 km/hr and for 4 hr at the rate of 6 km/hr. What will be the average speed of the whole journey in km/hr?

    Solutions

    The correct answer is option 2 i.e. 44/9 km/hr.

    Average speed if various distances covered at different time = (distance covered in x hr + distance covered in y hr)/(x + y)

    x + y is the total time

    Distance = speed × time

    A man travels for 5 hr at a speed of 4 km/hr

    Next, he travels for 4 hr at a speed of 6 km/hr

    The distance covered by him in 5 hr = (5 × 4) = 20 km

    The distance covered by him in the next 4 hr = (6 × 4) = 24 km

    The total distance covered = (20 + 24) = 44 km

    Total time = (5 + 4) = 9 hr

    The average speed = 44/9

  • Question 9/10
    2 / -0.5

    A man has sold some book at 10% profit and some pen at 12% profit. If he sells the book at 12% profit and pen at 10% profit, then he will get Rs 60 more. Find the cost price of the book, if he buys both in Rs 5000.

    Solutions

    The correct answer is option 3 i.e. Rs 4000.

    Profit = (C.P × P%)/100

    Let the CP of the book = x and the SP of the book = y, and Let the profit = P

    Given, x + y = 5000

    A/Q,

    ⇒ 10% of x + 12% of y = P........(I)

    ⇒ 12% of x + 10% of y = P + 60.......(II)

    Subtract (I) from (II) we get

    ⇒ 2% of x - 2% of y = 60

    ⇒ x - y = 3000

    ⇒ x + y = 5000 (given)

    ⇒ x = 4000

    So, the cost price of the book = Rs.4000

  • Question 10/10
    2 / -0.5

    Rakesh and Shyam had money in the ratio 4 : 7 while Vimal and Amit had money in ratio 9 : 16. What would be ratio of product of money with Rakesh and Vimal to product of money with Shyam and Amit?

    Solutions

    The correct answer is option 4 i.e. 9 : 28.

    The ratio of money of Rakesh and Shyam = 4 : 7

    The ratio of money of Vimal and Amit = 9 : 16

    Ratio of product of money with Rakesh and Vimal to Shyam and Amit:

    ⇒ (4 × 9) : (7 × 16) = 9 : 28

    Hence, the required ratio is 9 : 28

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