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In an examination, the average marks of 50 students is 70. Afterwards, it is found that the marks of three students are misread as 68, 65, and 73 instead of 70, 62, and 84 respectively. Find the correct average.
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The correct answer is Option 4 i.e. 70.2.
Given,
The number of students = 50
Average marks = 70
Total marks of 50 students = 50 × 70 = 3500
Incorrect marks of 3 students = 68 + 65 + 73 = 206
Correct marks of 3 students = 70 + 62 + 84 = 216
Marks required to add = 216 - 206 = 10
New total marks = 3500 + 10 = 3510
∴ Correct average = 3510/50 = 70.2
If x% of half of 84 is 7 times the y% of one-fourth of 48, then x is what percentage more/less than y?
The correct answer is Option 4 i.e. 100%.
x% of half of 84 = x/100 × 1/2 × 84 = 0.42x
y% of one fourth of 48 = y/100 × 1/4 × 48 = 0.12y
⇒ 0.42x = 7 × 0.12y
⇒ 6x = 12y
⇒ x/y = 2/1
Required percentage = (2 - 1)/1 × 100
⇒ 100%
A, B and C are angles of a triangle, then what is the value of 1/(tan A tan B) + 1/(tan B tan C) + 1/(tan C tan A)?
The correct answer is Option 2 i.e. 1.
⇒ 1/(tan A tan B) + 1/(tan B tan C) + 1/(tan C tan A) = (tan A + tan B + tan C)/(tan A tan B tan C)
⇒ {tan A + tan B + tan (π – A – B)}/(tan A tan B tan C) [∵ Sum of angles in triangle is π]
⇒ {tan A + tan B – tan (A + B)}/(tan A tan B tan C)
[We know that ⇒ tan A + tan B = tan (A + B)/(1 – tan A tan B)]
⇒ {tan (A + B)/(1 – tan A tan B) – tan (A + B)}/(tan A tan B tan C)
⇒ - tan (A + B) (tan A tan B)/(tan A tan B tan C)
⇒ (tan A tan B tan C)/(tan A tan B tan C) = 1 [∵ tan (A + B) = tan (π – C) = - tan C]
If the area of a rhombus and the length of the diagonal are 1176 cm2 and 56 cm respectively, then what is the length of altitude of the rhombus? (in cm)
The correct answer is option 2 i.e. 33.6.
Let the length of the other diagonal be x cm
The Area of rhombus = 1/2 × d1d2
⇒ 1176 = 1/2 × 56 × x
⇒ 1176 = 28x
⇒ x = 42 cm
Its diagonals bisect each other at 90°. So by using the Pythagoras theorem
Side2 = Sum of squares of lengths of semi-diagonals
⇒ Side2 = (56/2)2 + (42/2)2
⇒ Side2 = 1225
⇒ Side = 35 cm
Area = Side × Height
⇒ 1176 = 35 × Height
⇒ Height = 33.6 cm
If a + b = c then find the value of (a + b - c)3 + 3abc.
The correct answer is option 2 i.e. c3 - a3 - b3.
(x + y)3 = x3 + y3 + 3xy(x + y)
If a + b = c ..........(I)
a + b - c = 0
So, (a + b - c)3 = 0
Cubing eq. (I) On both sides we get
(a + b)3 = c3
⇒ a3 + b3 + 3ab(a + b) = c3
⇒ 3abc = c3 - a3 - b3
So,
(a + b - c)3 + 3abc
= 0 + c3 - a3 - b3
= c3 - a3 - b3
A train running at 58 km/hr is trying to overtake a train running at 49 km/hr. The faster train overtakes the slower train in 3 minutes. If train with faster speed is shorter than the other train by 10 m, find the length of the longer train.
The correct answer is Option 3 i.e. 230 m.
Speed of faster train = 58 km/hr
Speed of slower train = 49 km/hr
Relative speed (same direction) = 58 - 49 = 9 km/hr = 9 × (5/18) = 2.5 m/s
Time = 3 minutes = 3 × 60 = 180 seconds.
Distance travelled = Sum of lengths of both trains = Relative speed × time
Let length of trains be x and x + 10.
⇒ x + x + 10 = 2.5 × 180
⇒ 2x + 10 = 450
⇒ 2x = 440
⇒ x = 220
Length of longer train = x + 10 = 220 + 10 = 230 m
Directions For Questions
Direction: The line graph below shows the number of youth addicted to Drugs and the number of youth inclined towards Yoga in 5 different states A, B, C, D and E. Study the graph carefully and answer the questions that follow. All the values in the graph are in lakhs.
...view full instructions
The total number of youth addicted to drugs in states A and E is approximately what percentage of the total number of youth inclined towards yoga in states C and D?
The correct answer is option 3 i.e. 88.5%.
Total number of youth addicted to drugs in states A and E
= 12 + 15 = 27 lakhs
And
Total number of youth inclined towards Yoga in states C and D
= 18 + 12.5 = 30.5 lakhs
Hence,
Required percentage = [27/30.5] × 100 = 88.5% (Approx.)
In a cyclic quadrilateral PQRS, SR, and PQ are extended to meet at point T. If TS = 16 cm, TR = 12 cm, and TQ = 8 cm, then the length of the TP in cm is?
The correct answer is option 1 i.e. 24 cm.
TS × TR = TP × TQ
⇒ 16 × 12 = TP × 8
⇒ TP = (16 × 12)/8
⇒ TP = (2 × 12) cm = 24 cm
Hence, the length of TP is 24 cm
Rs. 5000 was divided into two parts, if one part is deposited at 8% and another at 10%, the whole annual interest sums up to Rs. 450. How much was lent at 8%?
The correct answer is option 1 i.e. Rs. 2500.
Let the amount lent at an interest rate of 8% be Rs. x
Amount lent at 10% interest rate = Rs. (5000 - x)
Simple Interest = (P × R × T)/100
Where, P = Principal , R = Rate of interest, T = time period in years
Simple Interest from amount lent at 8% = x × 8 × 1/100 = 0.08x
Simple Interest from amount lent at 10% = (5000 - x) × 10 × 1/100 = 500 - 0.1x
According to the question -
⇒ 0.08x + 500 - 0.1x = 450
⇒ 0.02x = 50
⇒ x = 50/0.02
⇒ x = Rs. 2500
If 450 apples are distributed among Sita, Reeta, and Geeta in the ratio of 27 : 11 : 7. How many more apples does Sita have than Reeta?
The correct answer is option 1 i.e. 160.
Total apples = 450
⇒ Number of apples with Sita = [450/(27 + 11 + 7)] × 27
⇒ 450 × 27/45
⇒ 270
⇒ Number of apples with Reeta = [450/(27 + 11 + 7)] × 11
⇒ 450 × 11/45
⇒ 110
Required number of apples = 270 - 110 = 160
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