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SSC GD 2026 Aptitude Test - 8
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SSC GD 2026 Aptitude Test - 8
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  • Question 1/10
    2 / -0.5

    Rohan invested equal amount of money in both Compound and Simple interest at the rate of 11%. After 2 years, the difference in interest amount was Rs. 605. What will be the interest on money put on compound interest after 3 years?

    Solutions

    The correct answer is option 2 i.e. Rs. 18381.

    We know, the interest rate is 11% and difference in CI and SI for 2 years is Rs. 605.

    Or,

    (P × 11 × 11)/(100 × 100) = 605

    ⇒ P = 6050000/121 = Rs. 50000

    Now, interest earned in 3 years:

    ⇒ (50000 × 1.11 × 1.11 × 1.11) - 50000

    ⇒ 68381.55 - 50000

    ⇒ Rs. 18381.55 = Rs. 18381 (Approx.)

  • Question 2/10
    2 / -0.5

    Three bells A, B and C rings at an interval of 25 minutes, 20 minutes and 30 minutes respectively. If they first ring together at 9 : 38 AM, when will they ring again?

    Solutions

    The correct answer is option 3 i.e. 2 : 38 PM.

    The time interval between the successive rings when they ring together = LCM of (25, 20, 30)

    ⇒ 300 minutes

    ⇒ 5 hours

    If it rang first at 9: 38 AM then, they will ring after 5 hours = 2 : 38 PM

  • Question 3/10
    2 / -0.5

    The average weight of students in Class A, Class B, and Class C is 54 kg, 48 kg, and 50 kg respectively, and the ratio of the number of students in Class A, Class B, and Class C is 1 : 2 : 3. Find the average weight of all classes together.

    Solutions

    The correct answer is Option 2 i.e. 50 kg.

    Average = Sum of weight of students/total students

    Let the number of students in class A, class B, and class C = x, 2x, and 3x

    The sum of the weight of students in class A = 54 × x = 54x

    The sum of the weight of students in class B = 48 × 2x= 96x

    The sum of weight of students in class C = 50 × 3x = 150x

    The sum of total weight of students in all the class

    ⇒ 54x + 96x + 150x = 300x

    The total number of students = x + 2x + 3x = 6x

    The average weight of students of all classes together

    ⇒ 300x/6x = 50 kg

  • Question 4/10
    2 / -0.5

    A three-digit number N27 is divisible by 9. What will be a possible value of N, if N is a single digit?

    Solutions

    The correct answer is Option 4 i.e. 9.

    If a number is divisible by 9, then the sum of digits of the number should be divisible by 9

    Given number N27 = N + 2 + 7 = N + 9

    Here, if we take N = 0 the sum will be 9 which is divisible by 9

    But, if take 0 then the number formed will not be the three-digit number

    So, we take N = 9 

    Then 9 + 9 =18 which is divisible by 9

  • Question 5/10
    2 / -0.5

    The ratio of ages of father, mother and son in a family is 8 : 7 : 2. After sixteen years, the son get married to a woman who is 2 years younger to him. Now the ratio the sum of ages of father and mother and the sum of ages son and his wife is 2 : 1.

    What is the age of the mother when the son was born?

    Solutions

    The correct answer is Option 2 i.e. 20.

    Let the ages of father, mother, and son earlier be 8x, 7x, and 2x respectively

    After 16 years,

    Age of father = (8x + 16)

    Age of mother = (7x + 16)

    Age of son = (2x + 16)

    Age of his wife = (2x + 16) – 2 = (2x + 14)

    Sum of ages of father and mother = (8x + 16) + (7x + 16) = (15x + 32)

    Sum of ages of son and his wife = (2x + 16) + (2x + 14) = (4x + 30)

    ⇒ (15x + 32)/(4x + 30) = 2/1

    ⇒ (15x + 32) = (8x + 60)

    ⇒ 7x = 28

    ⇒ x = 4

    Age of mother when the son was born = Age of mother – Age of son

    ⇒ 7x – 2x = 5x

    ⇒ 5 × 4 = 20 years

  • Question 6/10
    2 / -0.5

    In how much time will Rs 1350 become Rs 1728 at the rate of 8% simple interest?

    Solutions

    The correct answer is option 2 i.e. 3.5 years.

    Simple interest = (principal × rate × time)/100

    Amount = Principal + S.I

    Given, A = 1728

    P = 1350

    R = 8%

    Time = {(A - P) × 100}/(P × r)

    = {(1728 - 1350) × 100}/1350 × 8

    = (378 × 100)/(1350 × 8)

    = 3.5 years

  • Question 7/10
    2 / -0.5

    Polynomial x4 - 4x3 - 7x2 + kx - 1 gives remainder 3 when it is divided by (x + 2). Value of k is:

    Solutions

    The correct answer is Option 3 i.e. 8

    Remainder Theorem: If a polynomial is divided by (x + a), and remainder is R, then f(-a) = R

    Polynomial = x4 - 4x3 - 7x2 + kx - 1

    Dividend = (x + 2)

    Remainder = 3

    According to remainder theorem,

    f(-2) = 3

    ⇒ (-2)- 4 × (-2)3 - 7 × (-2)2 - 2 × k - 1 = 3

    ⇒ 16 + 32 - 28 - 2k - 1 = 3

    ⇒ -2k = -16

    ⇒ k = 8

  • Question 8/10
    2 / -0.5

    Two successive discounts of (x + 4)% and (x + 8)% are given on an article marked at Rs 4800. The selling price of an article is Rs 3225.6. Find the selling price (in Rs) if the discount is (4x + 2)%

    Solutions

    The correct answer is option 4 i.e. 2400.

    Let x + 4 = y

    Marked price = Rs.4800

    Selling price = Rs 3225.6

    Let the total discount percentage be d

    ⇒ (100 - d) % of 4800 = 3225.6

    ⇒ (100 - d) = 67.2

    ⇒ d = 32.8%

    Successive discount = a + b + ab/100

    Two discounts will be y and y + 4

    Total discount = y + y + 4 - y(y + 4)/100

    ⇒ 200y + 400 - y2 - 4y = 32.8 × 100

    ⇒ y2 - 196y + 2880 = 0

    ⇒ y = 16, 180 (16 is possible)

    ⇒ x + 4 = y

    ⇒ 16 = x + 4

    ⇒ x = 12

    Value of 4x + 2 = 50

    After 50% discount, SP = 4800 × 1/2 = Rs.2400

  • Question 9/10
    2 / -0.5

    Find the value of '?':

    (1369)1/2 - (2197)1/3+ 276 - ?2 = (4225)1/2 + 171

    Solutions

    The correct answer is Option 2 i.e. 8

    (1369)1/2 - (2197)1/3+ 276 - ?2 = (4225)1/2 + 171

    ⇒ 37 - 13 + 276 - ?2 = 65 + 171

    ⇒ 24 + 276 – (?)2 = 236

    ⇒ 300 – 236 = (?)2

    ⇒ ? = 8

  • Question 10/10
    2 / -0.5

    If a number 418X367 is completely divisible by 9, then the smallest whole number in place of X is:

    Solutions

    The correct answer is Option 2 i.e. 7.

    If the sum of the digit of a given number is divisible by 9 then, the number is divisible by 9.

    The given number is 418X367,

    the sum of the digit of the number is 4 + 1 + 8 + X + 3 + 6 + 7 = 29 + X

    The smallest whole number X will be 7 then the sum is divisible by 9.

    So, the possible value of X is 7

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