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Probability Test 3
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Probability Test 3
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  • Question 1/9
    1 / -0

    A five digit number is formed with the digits 0,1,2,3 and 4 without repetition.Find the chance that the number is divisible by 5

    Solutions

    Explanation :

    5 digit number = 5! = 120

    Divisible by 5 then the last digit should be 0

    Then the remaining position have the possibility = 4! =24

    P = (4!/5!) = 24/120 = 1/5

     

  • Question 2/9
    1 / -0

    A bag contain  6 white balls and 4 red balls .Three balls are drawn randomly.What is the probability that one ball is red and other 2 are white

    Solutions

    Explanation :

    Total no of balls = 6+ 4 = 10

    3 balls drawn = 10C3 =(10×9×8)/(3×2×1) =120

    one ball is red and other 2 are white = 4C1×6C2    

    4C1×6C2 =(4×6×5)/(1×2)= 60

    P = 60/120 = ½

     

  • Question 3/9
    1 / -0

    A box contain 10 red balls, 7 green balls and 12 blue balls. A ball is drawn at random. What is the probability that the ball drawn is either red or green ?

    Solutions

    Explanation :

    Total no of balls =10+7+12 = 29

    P(R) =10/29

    P(G) = 7/29

    P(Either red or green) = 10/29 + 7/29 = 17/29

     

  • Question 4/9
    1 / -0

    A dice is thrown twice . What is the probability that at least one of them comes up with number 4

    Solutions

    Explanation :

     

  • Question 5/9
    1 / -0

    From a group of 5 men and 2 women , 2 persons are selected at random. Find the probability that at least one woman is selected ?

    Solutions

    Explanation :

    n(S) = 7C2  = (7×6)/(1×2) = 21

    n(E) = 2C2+5C1 * 2C1 = 1+11

    P = n(E)/n(S) = 11/21

     

  • Question 6/9
    1 / -0

    A bag contains 11 red and 5 green balls. Find the probability that 4 balls  are red and 3 balls are green when 7 balls  are drawn at random.

    Solutions

    Explanation :

    n(S) = 16C7 = 11440

    n(E) = 11C4 ×5C3 = 330×10 = 3300

    P = n(E)/ n(S) = 3300/11440 = 15/52

     

  • Question 7/9
    1 / -0

    A box contain 8 red balls, 6 green balls and 8 blue balls. A ball is drawn at random. What is the probability that the ball drawn is neither red nor green ?

    Solutions

    Explanation :

    Total no of balls =8+6+8 = 22

    P(B) =8/22

    P(neither red nor green) = 8/22 = 4/11

     

  • Question 8/9
    1 / -0

    A box contains 5 green , 4 yellow and 3 white marbles. Three marbles are drawn at random. What is the probability that they are not of the same colour ?

    Solutions

    Explanation :

    n(E) = 5C3+ 4C3+3C3 = 10+4+1 = 15

    n(S) = 12C3 = 220

    P = n(E)/ n(S) = 15/220 =3/44

    Required probability = 1-3/44 = 41/44

     

  • Question 9/9
    1 / -0

    Two dice are thrown simultaneously .What is the probability of getting 2 numbers whose product is even ?

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