Please wait...

Mensuration Test 4
Menu grid icon
Result Result point icon
Mensuration Test 4
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0

    After measuring 100m of a rope, it was discovered that the metre rod was 2cm longer. The true length of the rod is

    Solutions

    Explanation :

    100*2 = 200cm measured long

    Correct length = 100 – (200/100) = 100 -2 = 98m

     

  • Question 2/10
    1 / -0

    A circle is drawn circumscribing a rectangle of sides 8cm and 6cm, find the area of the circle

    Solutions

    Explanation :

    Diagonal of rectangle = Diameter of circle

    Diameter = √ (64+36)  = 10

    Radius = 5cm

    Area of circle = 3.14*5*5 = 78.5cm2

     

  • Question 3/10
    1 / -0

    If the sides of a equilateral triangle is increased by 10% , 30%and 60%then a new triangle is formed. By what % perimeter of the triangle is increased ?

    Solutions

    Explanation :

    Let a = side of the triangle

    Perimeter = 3a

    New perimeter = a*110/100 + a*130/100 + a*140/100

    = a(11+13+16)/10 = 4a

    % increased in perimeter = (4a – 3a/3a)*100

    = 100/3 = 33.33%

     

  • Question 4/10
    1 / -0

    If length, breadth and height of a hall is 14m,8m,8m then find the diagonal of the hall ?

    Solutions

    Explanation :

    Diagonal = √ (142+82+82)

    = √ (196+64+64)

    = √324

    = 18m

     

  • Question 5/10
    1 / -0

    The base and the other side of an isosceles triangle is 8cm and 12cm. Find its triangle ?

    Solutions

    Explanation :

    Area = b/4√ (4a2 –b2)

    = 8/4√ (4*144 – 64)

    = 2(22.6) = 45.2cm2

     

  • Question 6/10
    1 / -0

    Find the area of sheet required to prepare an 60m height cone with base radius 32cm.

    Solutions

    Explanation :

    L = √(602 + 322) = 68

    Area = 3.14*r(h+l)

    Area of sheet = 3.14*32(60+68) = 12861.44 = 128612cm2

     

  • Question 7/10
    1 / -0

    A hall is 80m long 65m wide. It has to be designed by tiles of 15m*10m. Find no of tiles required  ?

    Solutions

    Explanation :No of tiles = 80*65/15*10 = 5200/150 = 34.7 = 35

     

  • Question 8/10
    1 / -0

    Find the cost of carpenting a room 12 m long and 7 m broad with a carpet 10m long and 6m wide and at the rate of Rs.150 per meter.

    Solutions

    Explanation :

    Area of the room = 12 × 7 => 84 m2

    Area of carpet = 10*6 = 60 m2

    Cost = (84/60)*150 = 210

     

  • Question 9/10
    1 / -0

    The side of a cube is 13 cm, Find its surface area?

    Solutions

    Explanation :Surface area = 6a2 = 6*13*13 = 1014cm2

     

  • Question 10/10
    1 / -0

    The length of box 12 Cm long, 6 Cm breadth and 4Cm height. Find the maximum length of scale in that box?

    Solutions

    Explanation :

    Diagonal = √l2+b2+h2

    = √122+62+42

    = √196 => 14 Cm

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now