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Age Test 3
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Age Test 3
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  • Question 1/9
    1 / -0

    The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband?

    Solutions

    Explanation-

    Sum of ages is 360 years.The ratio of children and parents ages is 2:1.

    Total age of parents = 360 x 1 / 3 = 120 years

    Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70

    Hence the age of husband is 70 years.

     

  • Question 2/9
    1 / -0

    The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years?

    Solutions

    Explanation –

    Let A’s age and B’s age be 6X years and 7X years respectively

    Then, 7X – 6X = 4

    X = 4

    Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

     

  • Question 3/9
    1 / -0

    Sush was thrice as old as Poonam 6 years back. Sush will be 5/3 times as old as Poonam 6 years hence. How old is Poonam today?

    Solutions

    Explanation –

    Let Poonam age 6 years back = x.

    Then, Sush age 6 years back = 3x.

    (5/3) * (X + 6 + 6) = (3X + 6 + 6)

    So 5(x+ 12) = 3(3x+ 12),

    so x=6.

    Poonam Age = (x+ 6) years = 12 years

     

  • Question 4/9
    1 / -0

    Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years?

    Solutions

    Explanation –

    Let the present ages of Simmi and Anu be 5x years and 4x years respectively

    Then, [5X + 3] / [4X + 3] =11/9

    x=6

    Anu’s present age = 4X = 24 years

     

  • Question 5/9
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    If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj?

    Solutions

    Explanation –

    Let Anuj’s age be X

    Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 – 2 = 3)

    If Arun had born 6 years before, his age would had been X – 6. As per the question, X – 6 should be 18 times as that of Gokul’s age.

    i.e. (X – 6) /18= 3

    X-6 =3 x 18

    x = 60

     

  • Question 6/9
    1 / -0

    Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age?

    Solutions

    Explanation –

    Let Khush’s present age be x years and Sam’s present age be y years

    Then, according to the first condition,

    x – 10 = 3(y – 10)

    or, x – 3y = -20 ……..(1)

    Now. Khush’s age after 10 years = (x + 10) years

    Sam’s age after 10 years = (y + 10)

    (x+10) = 2(y+10)

    or, x – 2y = 10 ……..(2)

    Solving (1) and (2), we get

    x = 70 and y = 30

    Khush’s age = 70 years and Sam’s age = 30 years

     

  • Question 7/9
    1 / -0

    Father is aged three times more than his son Mohit. After 8 years, he would be two and a half times of Mohit’s age. After further 8 years, how many times would he be of Mohit’s age?

    Solutions

    Explanation –

    Let Monit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years.

    (4X + 8) =5/2 x (X + 8)

    8X + 16 = 5X + 40

    3X = 24 so, X=8

    Hence, required ratio = (4X + 16) / (X + 16)=48 / 24 = 2

     

  • Question 8/9
    1 / -0

    A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was:

    Solutions

    Explanation – Let son’s present age be X years. Then, (38 – X) = X

    2X = 38

    X = 19

    Son’s age 5 years back = (19 – 5) years = 14 years

     

  • Question 9/9
    1 / -0

    One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years?

    Solutions

    Explanation – Let one year ago

    Sam’s age be 4X years

    And, Ash’s age be 3X years

    Present age of Sam = (4X + 1) years

    Present age of Ash= (3X + 1) years

    One year hence

    Sam’s age = (4X + 2) years

    Ash’s age = (3X + 2) years

    According to question,

    [4X + 2] divide by [3X + 2] = 5 / 4

    16X + 8 = 15X + 10

    or, X = 2

    Sum of their present ages = 4X + 1 + 3X + 1

    = 7X + 2

    = 7 x 2 + 2 = 16 years.

     

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