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Average Test 23
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Average Test 23
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  • Question 1/10
    1 / -0

    The average age of Husband and wife was 30yr, 4 yr ago. What will be their average age at present ?

    Solutions

    Explanation :

    Avg of H  and W age 4yr ago = 30

    Present avg age of H  and W = 30+4 = 34

     

  • Question 2/10
    1 / -0

    The average weight of 20 students is 60kg.If the weight of the teacher is added, average is increased by 2kg.What was the teacher’s weight ?

    Solutions

    Explanation :

    x/20 =60; x = 1200

    x/21 = 62; x = 1302

    1302 – 1200 = 102

     

  • Question 3/10
    1 / -0

    The average mark in 2 subjects is 35 and in three other subject is 40.Then find the average mark in all the five matches ?

    Solutions

    Explanation :

    x/2 = 35; x = 70

    x/3 = 40; x = 120

    5 sub avg = (70+120)/5 = 38

     

  • Question 4/10
    1 / -0

    The average height of 15 students is calculated as 75. But later it was found that the height of 1 student wrongly entered as 35 instead of 38 and another as 46 instead of 63.The correct average is.

  • Question 5/10
    1 / -0

    Among the three number the first is thrice the third number and second number is half of the first number. If the average of the three number is 65.8 then find the third number.

    Solutions

    Explanation :

    Let third num = x, 1st numb = 3x, second no = 3x/2

    [3x+(3x/2)+x] / 3 = 65.8

    11x/2 = 197.4

    X = (2×197.4) / 11 = 35.89

     

  • Question 6/10
    1 / -0

    The average weight of 3 students P,Q and R is 84kg.Anothe students S joins the group and the average becomes 80kg. If another man T whose weight is 3kg more than that of S, replaces P, then the average weight of Q,R,S and T becomes 79 kg then the weight of P is.

    Solutions

    Explanation :

    P+Q+R = 84*3 = 252

    P+Q+R+S = 4*80 = 320

    S = 320 – 252 = 68

    Q+R+S+T = 79*4 = 316

    Q+R+2S+3 = 316

    S =68, Q+R =177

    P = 252 – 177 = 75

     

  • Question 7/10
    1 / -0

    The average of 5 consecutive number is 58.Find the first number ?

    Solutions

    Explanation :

    X+x+1+x+2+x+3+x+4 = 58*5 = 290

    5x+10 = 290

    X = 290 – 10/5 = 280/5 = 56

     

  • Question 8/10
    1 / -0

    The average weight of 8 staff is increased by 3kg when one of them whose weight is 50kg is replaced by a new staff. The weight of the new staff is.

    Solutions

    Explanation :50+(8*3) = 50 + 24 = 74.

     

  • Question 9/10
    1 / -0

    The average age of 15  army men is 60yrs.5 new army men of average age 30yrs join them. Find the new average age.

    Solutions

    Explanation :

    15 army men age = 15*60 =900

    5 army men age = 5*30 = 150

    New avg = 900+150/20 =52.5

     

  • Question 10/10
    1 / -0

    The average ages of 4 member, each having the age difference of 2yrs is 54 yrs.What is the sum of the youngest and oldest family member ?

    Solutions

    Explanation :

    X+X+2+X+4+X+6 = 54*4 = 216

    4X+12 = 216

    X = 216-12/4 =51

    X+6 = 51+6 = 57

    Required = 51+57 = 108

     

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