Please wait...

Mixture and Alligation Test 5
Menu grid icon
Result Result point icon
Mixture and Alligation Test 5
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0

    2 varieties of juice are mixed in the ratio of 4:5. The price of 1st variety juice is Rs.14per litre while the second variety is Rs.17 per litre.Find the  average price of the mixture ?

    Solutions

    Explanation :

    Let X = avg price

    x-14/17-x = 5/4

    4x-56 = 85-5x

    5x+4x = 85+56 = 141

    9x = 141

    X = 141/9 = 15.67

     

  • Question 2/10
    1 / -0

    A milkman mixes 6 litres of free tap water with 18litres of pure milk. If the cost of pure milk is Rs.28 per litre the % Profit of the milkman when he sells all the mixture at the cost price is

    Solutions

    Explanation :Profit % = 6*100/18 = 33(1/3)

     

  • Question 3/10
    1 / -0

    From a tank of petrol, which contains 500 litres of petrol initially, the seller sells 50litres of petrol each time and replenishes the tank with kerosene. Every time he sells out only 50litres of petrol.After replacing 4th time petrol with kerosene, find the total amount of kerosene in the mixture ?

    Solutions

    Explanation :

    Amount of petrol left = 500[1-50/500]4

    = 500[9/10]4= 500*6561/10000

    = 328.05

    Amount of kerosene = 500-328.05 = 171.95litres

     

  • Question 4/10
    1 / -0

    In a 80 litre mixture of milk and water, the % of water is only 25%. The milkman gave 15 litres of this mixture to a customer and then added 15 litres of water to the remaining mixture. What is the % of milk in the final mixture ?

    Solutions

    Explanation :

    Water = 80*25/100 = 20litre

    Milk = 80-20 = 60litre

    18litre mixture

    Milk = 15*60/80 = 11.25litres

    Remaining quantity of milk = 60-11.25 = 48.75litres

    % of milk in the mixture = 48.75*100/80 = 60.93 = 61%

     

  • Question 5/10
    1 / -0

    A jar containing 60litres of mixture of milk and water. The respective ratio of milk and water in the ratio 7:5. From the jar 12litres of mixture was taken out and 6 litres of pure milk was added. What is the respective ratio of milk and water after the final operation ?

    Solutions

    Explanation :

    7x+5x = 60

    Milk = 35litres, water = 25litres

    10litres of mixture taken out

    Milk = 35-12(7/12) = 35-7 = 28

    Water = 25-12(5/12) = 25-5 = 20

    28+6 : 20 = 34:20 = 17:10

     

  • Question 6/10
    1 / -0

    In 600 gram of mixture of salt and water, there is 40 % water. How much water should be converted to steam so that water in the mixture remains 25 %.

    Solutions

    Explanation :

    = 600*(40-25)/(100-25)

    =600*(15/75)

    = 120gm

     

  • Question 7/10
    1 / -0

    A goldsmith has two qualities of gold, one of 10 carats and another of 5 carates purity. In what proportion should he mix both to make an ornament of 8 carats purity ?

    Solutions

    Explanation :

    10                                  5

    ……………..8……………..

    8-5 = 3                       10-8 =2

    3:2

     

  • Question 8/10
    1 / -0

    A dishonest milkman professes to sell his milk at cost price but  he mixes  with water and there by gains 20% .The percentage of water in the mixture is?

    Solutions

    Explanation :

    P of 1 liter milk = Re 1.

    S.P of 1 liter mixture=Re 1. Gain=20%

    C.P of 1 liter mixture =Re(100/120*1) = Re 5/6.

    C.P of 1 liter milk Re 1                         C.P of 1 liter of water 0

    5/6

    5/6                                                                       1/6

    Ratio of milk to water =5/6 : 1/6 = 5:1

    % of water in the mixture=1/6*100=16.67%

     

  • Question 9/10
    1 / -0

    The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

    Solutions

    Explanation :

    4/7                                    2/5

    …………………1/2………………….

    1/10                                  1/14

    Required ratio = 1/10 : 1/14 = 7:5

     

  • Question 10/10
    1 / -0

    A can contains a mixture of two liquids A and B in the ratio 9:7 when 8 liters of mixture are drawn off and the can is filled with B,the ratio of A and B becomes 9:8.How many liters of liquid A was contained by the can initially?

    Solutions

    Explanation :

    Initial =  9x and 7x

    Quantity of A in mixture left = (9x- (9/16)*8)

    = 9x – (9/2)

    Quantity of B in mixture left = (7x – (7/16)*8)

    = 7x – (7/2)

    [9x – (9/2)]/[7x – (7/2)+8] = 9/8

    18x-9/14x + 9 = 9/8

    144x-72 = 126x+81

    18x=153

    X = 153/18 = 8.5

    9x = 9*8.5 = 76.5litre

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now