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Mensuration Test 5
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Mensuration Test 5
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  • Question 1/10
    1 / -0

    The area of a square field is 4050 m2the length of its diagonal is

    Solutions

    Explanation :

    1/2 d2 = 4050

    d2 = 8100

    d = 90 m

     

  • Question 2/10
    1 / -0

    The Surface area of cube is 216 m2. Find it’s diagonal

    Solutions

    Explanation :

    6a2 = 216

    a2 = 216/6 = 36

    a= 6

    Diagonal = a√3 = 6*1.73 = 10.38m

     

  • Question 3/10
    1 / -0

    The length of a rope by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is

    Solutions

    Explanation :

    22/7×r2 =2826

    r2 =(2826×7/22) = 899.18 = 900

    r = 30 m

     

  • Question 4/10
    1 / -0

    The number of rounds that a wheel of diameter14m will make in going 2 km is

    Solutions

    Explanation :N = 2000/(14*22/7) = 2000/44 = 45.45 = 45 rounds

     

  • Question 5/10
    1 / -0

    The ratio of length to breadth of a rectangle is 7:6. The perimeter of the plot is 260m. Find the area of the plot ?

    Solutions

    Explanation :

    2(7x+6x) = 260

    26x = 260

    X = 260/26 = 10

    Area = 70*60 = 4200

     

  • Question 6/10
    1 / -0

    In a parallelogram the length of adjacent sides are 13m and 11m. If the length of one diagonal is 18m, find the length of the other diagonal ?

    Solutions

    Explanation :

    d12+d22 = 2(a2+b2)

    324+d22 = 2(169+121) = 580

    d22 =  580 – 324 = 256

    d  = 16m

     

  • Question 7/10
    1 / -0

    The circumference of the 2 circle is 212cm and 412cm. What is the difference between the area of the 2 circles ?

    Solutions

    Explanation :

    2*3.14*r1 = 212

    R1 = 212/6.28 = 33.75 = 34cm

    2*3.14*r2 = 412

    R1 = 412/6.28 = 65.60= 66cm

    Diff = 3.14(662-342)

    = 3.14(4356-1156) = 3.14*3200

    = 10048

     

  • Question 8/10
    1 / -0

    If the length of the rectangular field is increased by 10% and the breadth is reduced by 10%, now the area of rectangle will be 217 cm2 .Find the area of the original rectangle ?

    Solutions

    Explanation :

    % change = 10 – 10 – 10*10/100 =  -1%

    99x/100 = 217

    X = 217*100/99 = 219.19 = 219

     

  • Question 9/10
    1 / -0

    The area of right angle triangle is 100sq cm. The ratio of base to its height is 4:5.Find the length of the hypotenuse ?

    Solutions

    Explanation :

    Area = ½(4x*5x)

    100 = 20x^2/2

    X^2 = 100/10 =10

    x = 3.16

    4x:5x = 12.64:15.8

    Hypotenuse = √12.642+15.82

    = √409.40

    = 20.23 = 20

     

  • Question 10/10
    1 / -0

    How many bricks, each measuring 20 cm x 8 cm x 5 cm, will be needed to build a wall of 10 m x 7 m x 20cm?

    Solutions

    Explanation :

    Number of bricks =Volume of the wall/Volume of  brick

    = 1000 x 700 x 20/20 x 8x 5

    = 17500

     

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