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Simple Interest Test 5
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Simple Interest Test 5
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  • Question 1/10
    1 / -0

    Arjun took a certain sum as loan from Bank at a rate of 10% simple interest per annum. Arjun lends the same amount to Bala at 14% simple interest per annum. If at the end of five years. Arjun made profit of Rs.800 from the deal, how much was the original sum ?

    Solutions

    Explanation :

    (x*14*5)/100 – (x*10*5)/100 = 800

    70x – 50x/100 = 800

    X = 80000/20 = 4000

     

  • Question 2/10
    1 / -0

    The simple interest accrued on a sum of certain principal is Rs.1000 in 4 years at the rate of 6% pa. What would be the SI accrued on thrice of that principal at the rate of 4%pa in 3yrs.

    Solutions

    Explanation :

    P = (1000*100)/(6*4) = 100000/24 = 4166.6 = 4167

    Interest = (3*4167*4*3)/100 = 1500.12 = 1500

     

  • Question 3/10
    1 / -0

    A sum of money amounts to Rs. 1500 after 3 years and Rs.2000 after 5 years at the same rate of SI. Find the rate of interest per annum ?

    Solutions

    Explanation :

    3 yr = 1500

    5yr = 2000

    Then SI 2yr (5-3) = 500

    SI 1yr = 250

    SI 3yr = 250*3 = 750

    P = 1500 – 750 = 750

    R = 750*100/750*3 = 33.3%

     

  • Question 4/10
    1 / -0

    At what interest per annum will a sum of money double in 14 yrs ?

    Solutions

    Explanation :

    Let principal = SI = P and N = 14

    R = (100*P)/(P*14) = 100/14 = 7.14%

     

  • Question 5/10
    1 / -0

    A sum of Rs.1500 is lent out into 2 parts, one at 10% and another one at 6%. If the total annual income is Rs.100, Find the money lent at each rate.

    Solutions

    Explanation :

    (x*10*1)/100 + ([1500-x]*6*1)/100 = 100

    10x+9000-6x = 10000

    4x = 1000

    X= 1000/4 = 250

    1500-x = 1500-250 = 1250

     

  • Question 6/10
    1 / -0

    A certain amount was put at SI at R% for 3yrs. Had it beet put at 3% higher rate, it would have fetched Rs.450 more.Find the sum.

    Solutions

    Explanation :

    [P*(R+3)*3/100] – [(P*R*3)/100] = 450

    3PR+9P-3PR = 45,000

    P = 45,000/9 = 5000

     

  • Question 7/10
    1 / -0

    What will be the ratio of SI earned by certain amount at the same rate of interest for 6yrs and 8yrs ?

    Solutions

    Explanation :

    6PR/8PR = 6/8 =3/4

    3:4

     

  • Question 8/10
    1 / -0

    Yuvraj invested 1/2 of his capital at 4% and the remainder at10%.If his annual income is Rs.600,Find the capital.

    Solutions

    Explanation :

    (x/2*4/100)+(x/2*10/100) = 600

    4x/200 + 10x/200 = 600

    14x = 120000

    X = 120000/14 = 8571

     

  • Question 9/10
    1 / -0

    The difference between the SI received from two different sources on Rs.2500 for 2 yrs is Rs.15. The difference between the rate of interest is.

    Solutions

    Explanation :

    (2500*R*2) – (2500*r*2) = 15*100

    5000(R-r) = 1500

    (R-r) = 1500/5000 = 0.3%

     

  • Question 10/10
    1 / -0

    If annual rate is of SI is increased from 8% to 11%, a man’s yearly income increases by Rs.1500.Find the principal.

    Solutions

    Explanation :

    11x – 8x = 1500*100

    3x = 1,50,000

    X = 150000/3 = 50,000

     

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