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Simple Interest Test 7
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Simple Interest Test 7
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  • Question 1/10
    1 / -0

    Niharika borrows Rs.10000 for 2 years at 4% p.a. Simple interest. She immediately lends money to Girish at 50/4% p.a. for 2 years. Find the gain of 1 year?

    Solutions

    Explanation :(10000*50*1/ 4*100 ) –  (10000*4*1 / 100)

    1250-400 = 850

     

  • Question 2/10
    1 / -0

    A certain amount of money amounts to Rs. 720 in 2 years and to Rs. 870 in 4(1/2) years. Find the rate of interest if S.I. is reckoned.

    Solutions

    Explanation :

    Trick: (A1*T2- A2*T1) / T2-T1

    (720*9/2 )–(870* 2)   /  ( 9/2) -2

     

  • Question 3/10
    1 / -0

    At what percent per annum will  a sum of money triple in 16 years?

    Solutions

    Explanation :

    P = P, SI=2P, T=16

    Rate= 100*2P/P*16

     

  • Question 4/10
    1 / -0

    The Simple Interest on a certain sum of money for 3(1/2) years at 16% p.a. is 60 less than the SI on the same sum for 4(1/2) years at 14% p.a. Find the sum.

    Solutions

    Explanation :X*9*14/ 100*2 – x*7*16/ 100*2  =60

     

  • Question 5/10
    1 / -0

    A man lends Rs.20000 in four parts if he gets 8% on Rs.4000, 6(1/2)% on Rs. 8000 and 8(1/2)% on Rs.6000. What percent must he get for the remainder, if his average annual interest is 9.13%?

    Solutions

    Explanation :

    (4000*8*1)/100 + (8000*13*1)/2*100  +(6000*17*1)/100 + (2000*R*1)/100 =9.13/100 *20000

     

  • Question 6/10
    1 / -0

    A sum was put at S.I. at certain rate for 4 years. Had it been put at 6% higher rate, it would have fetched Rs.800 more. Find the sum.

    Solutions

    Explanation :

    At 6% higher, increase in SI for 4 years= Rs.800

    For 1 year= 800/4= 200

    200 is 6% of the sum

    1%= 200/6

    Sum= 200*100 / 6

     

  • Question 7/10
    1 / -0

    If a sum of money becomes 16 times in 4 years at SI. The rate of interest is

    Solutions

    Explanation :

    Trick: 100(x-1) / T i.e. 100(16-1) / 4

    X= No. of times it becomes

     

  • Question 8/10
    1 / -0

    A certain sum of money amounts to Rs.800 in 2 years and to Rs. 920 in 3 years then the sum is.

    Solutions

    Explanation :

    Trick: (A2 –  A1)/ T2-T1

    (920-800)  /1 = 120

    P = 800-240 = 560

     

  • Question 9/10
    1 / -0

    The SI on a sum of money will be Rs.2500 after 5 years. In the next 5 years Principal is trebled, what will be the total interest at the end of the 10th year?

    Solutions

    Explanation :

    Trick: (n+1) * x  i.e.  (3+1) *2500

    N= No. of times it become

    X= SI

  • Question 10/10
    1 / -0

    A sum of money becomes 8 times at SI rate of 5% p.a. At what rate percent will it become twelve fold?

    Solutions

    Explanation :

    [ (m-1) *r ] / n-1

    [(12-1) *5] /(8-1)

     

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