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(√3 + 1)² = ? + √12
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Answer : 4. 4
Explanation : (√3 + 1)² = ? + √12 3 + 2√3 + 1 = ? + 2√3 = 4
(62.5 * 14 * 5) ÷ 25 + 41 = (?)³
Answer – 2. 6
Explanation : (62.5 * 14 * 5) ÷ 25 + 41 = (?)³ 4375 ÷ 25 + 41 = (?)³ (?)³ = 216 x = 6
The average expenditure of Vinay for the January to June is Rs. 5200 and he spent Rs. 1200 in January and Rs.3000 in July. The average expenditure for the months of February to July is:
Answer : 4. 5500
Explanation: Total Expenditure(Jan – June) = 5200 * 6 = 31200 Total Expenditure(Feb – June) = 31200 – 1200 = 30000 Total Expenditure(Feb – July) = 30000 + 3000 = 33000/6 = 5500
The prices of two pens are in the ratio 3 : 4. If the price of the first pen be increased by 10% and that of the second pen by Rs. 4, the original ratio remains the same. The original price of the second pen is
Answer : 1. Rs.40
Explanation: Let the price of two pens are 3X and 4X. After increment the ratio will be: 110% of 3x/(4X+4) = 3/4 x=10 Thus the CP of second pen = 4X = 4*10 = Rs. 40.
Two pipes M and N can fill a container in 24 minutes and 27 minutes respectively. If both the pipes are opened simultaneously, after how much time should N be closed so that the container is full in 16 minutes?
Answer : 2. 9 minutes
Explanation : Required time = y(1-(t/x)) = 27(1-(16/24))= 9 minutes
325 – (12)² + 75 = (?)² – 68
Answer : 4. 18
Explanation : 325 – (12)² + 75 = (?)² – 68 325 – 144 + 75 + 68 = (?)² (?)² = 324 x = 18
621 ÷ 27 * 2 – 37 = √?
Answer : 3. 81
Explanation : 621 ÷ 27 * 2 – 37 = √? 23 * 2 – 37 = √? = 9 x = 81
48356 + 5412 – 736 = ? * 40
Answer : 3. 1325.8
Explanation : 48356 + 5412 – 736 = x * 40 53032 = x * 40 x = 1325.8
5, 12, ?, 41, 87, 214
Answer : 3.22
Explanation : 5+7 = 12 12+(7+3=10) =22 22+(10+9=19) = 41 41+(19+27=46) = 87 87+(46+81=127) = 214
Ajay travels first one-third of the total distance at the speed of 10 kmph and the second one-third distance at the speed of 20 kmph and the third one – third distance at the speed of 60 kmph. What is the average speed of Ajay?
Answer : 1. 18 kmph
Explanation: Time for first 1/3 of distance = ((y/3)/ 10) Time for second 1/3 of distance = ((y/3)/20) Time for third 1/3 of distance = ((y/3)/60) Time for entire trip = x = ((y/3)/10) + ((y/3)/20) + ((y/3)/60) 180x = 6y +3y + y 180x = 10y x = y/18 Average speed = D/T = y/x = y / (y/18) = y * (18/y) = 18 km/hr
Vinay and Vijay are two partners and they have invested Rs. 54,000 and Rs. 90,000 in business respectively. After one year Vinay received Rs 1200 as his share of profit out of total profit of Rs. 4200 including his certain commission on total profit since he is a working partner and rest profit is received by Vijay. What is the commission of Vinay as a percentage of the total profit?
Answer : 1. 1200
Explanation: Ratio of profit of Vinay : Vijay (excluding commission of Vinay) = 54000 : 90000 =>3 : 5 Now the share of profit of Vijay = 4200 – 1200 = Rs. 3000 So the share of profit Vinay (excluding commission) = Rs. 1800 So the commission of Vinay = 3000 – 1800 = 1200
29, ?, 79, 131, 201
Answer : 4.45
Explanation : 29+(18*1-2) = 29+16 = 45 45+(18*2-2) = 45+34 = 79 79+(18*3-2) = 79+52 = 131 131+(18*4-2) = 131+70 = 201
480/x = [480/(x – 8)] – 3
y(10y – 1) = 2
Answer : 5. X = Y or relation cannot be established
Explanation: 480/x = [480/(x – 8)] – 3 x = 40, -32 y(10y – 1) = 2 10y2 – y – 2 = 0; y = 0.5, -0.4
If Siva is as much elder than Ramesh as he is younger to Deepak and sum of the ages of Ramesh and Deepak is 46 year, then what will be the age of Siva after six years?
Answer : 4. 29
Explanation : Let the present ages of Siva is x year and he is younger to Deepak by y year Then Deepak’s age = x + y Ramesh’s age = x – y (x + y) + (x – y) = 46 x = 23 The age of Siva after five years is – 29
A Cultural Competition is organised by the college A through which they will provide scholarship of rupees one lakhs to only one student. There are 100 fourth year students, 150 third year students, 200 second year students and 250 first year students. What is the probability that a second year student is chosen.
Answer : 2. 2/7
Explanation : Second year students = 200 Probability = 200/700 = 2/7
(9.8 * 2.3 + 4.46) ÷ 3 = 3^?
Answer : 1. 2
Explanation : 9.8 * 2.3 = 22.54 22.54 + 4.46 = 27; 27/3 = 9
(?)^1/4/ 8 = 48/(?)^3/4
Answer : 3. 384
Explanation : x = 48 * 8 = 384
3/14 of 5/13 of 6/7 of 3822 = ?
Answer : 4. 270
Explanation : 3/14 of 5/13 of 6/7 of 3822 = 3 * 5 * 6 * 3 = 270
(786*74) ÷ x = 1211.75
Answer : 4. 48
Explanation : (786*74) ÷ x = 1211.75 x = 48
2, 4, 7, ?, 87, 344
Answer : 2.24
Explanation : 2 + 1² + 1 = 4 4 + 2² – 1 = 7 7 + 4² + 1 = 24 24 + 8² – 1 = 87 87 + 16² + 1 = 344
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