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Ajay’s present age is 1.5 times of Hardik’s present age. If after 4 years, Ajay’s age will be twice of Hardik’s age 4 years ago. What is the sum of the present ages of Ajay and Hardik?
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Answer : 3. 60 years
Explanation :
A = 1.5 * H
A + 4 = 2 * (H – 4)
A + 4 = 2H – 8
A + 12 = 2H
1.5H + 12 = 2H
H = 24
A = 24 * 1.5 = 36
Sum = 36 + 24 = 60
The cost of servicing of a Etios car at one of the Toyota Service Centers is Rs. 400. Manager of service center told that for the second service within a year a customer can avail a 10% discount and further for third and forth servicing the customer can avail 10% discount of the previous amount paid, within a year Further if a customer gets more than 4 services within a year he has to pay just 60% of the servicing charges on these services. Vijay availed 5 services from the same servicing station, What is the total percentage discount fetched by Vijay?
Answer : 1. 19.42%
Let Amount paid in 1st service = 100
Amount paid in 2nd service = 90
Amount paid in 3rd service = 81
Amount paid in 4th service = 72.9
Amount paid in 5th service = 60
Total amount paid = 403.9
Discount = 500 – 403.9 = 96.1
Discount % = (96.1 / 500) * 100 = 19.42%
A boat’s speed in still water is 5 kmph. While river is flowing with a speed of 2 kmph and time taken to cover a certain distance upstream is 4 hours more than time taken to cover the same distance downstream. Find the distance?
Answer : 2. 21 km
Let the distance be D km.
Speed download = (5+2) = 7 km/h
and speed upstream = (5-2) = 3 km/h
According to the question,
D/3 – D/7 = 4
⇒ 7D – 3D = 21 x 4
D = (21 x 4)/4 = 21 km
Out of the three semester examinations, each with a total of 500 marks, a student secured average marks of 45% and 55% in the first and second semester examinations. To have an overall average of 60%, how many marks does the student need to secure in the third semester examination?
Answer : 2. 400
Total marks for three semester examinations = 3x 500 = 1500
Total required marks in three semester examinations = 60% of 1500
=( 3 x 500 x 60 ) / 100 = 900
Marks secured in first semester examination = 45 % of 500
=( 500 x 45 ) / 100 =225
Marks secured in third semester examination = 55 % of 500
=( 500 x 55 ) / 100 =275
Thus, the required marks in third semester examination
=900 – ( 225 + 275 ) =900 – 500 = 400
An aspirant attempted 12 questions in a competitive exam and secured full marks in all of them. If he obtained 60% in the competitive exam and each questions carry equal marks, then what was the total number of questions in the competitive exam?
Answer : 4. 20
Let the number of question be Y.
60% of Y = 12
60Y / 100 =12
Y = 20
x(35 – x) = 124 y(2y + 3) = 90
Answer : 5. X = Y or relation cannot be established
Explanation:
x(35 – x) = 124
x = 31, 4
y(2y + 3) = 90
y = -7.5, 6
2x² + 11x + 12 = 0 y² – 14y + 48 = 0
Answer : 2. X < Y
2x² + 11x + 12 = 0
x = – 4, – 1.5
y² – 14y + 48 = 0
y = 6, 8
2x² – 3x – 20 = 0 2y² – 18y + 40 = 0
Answer – 4. X ≤ Y
2x² – 3x – 20 = 0
x = – 2.5, 4
y² + 9y + 18 = 0
y = 4, 5
(9 ÷ 2 * 27 ÷ 9)/(18 ÷ 7.5 * 5 ÷ 4)
Answer – 4. 4.5
(9 ÷ 2 * 27 ÷ 9)/(18 ÷ 7.5 * 5 ÷ 4) = 27/6 = 4.5
12 7 9 22 96 ?
Answer : 2.784
12 * 0.5 + 1 = 7
7 * 1 + 2 = 9
9 * 2 + 4 = 22
22 * 4 + 8 = 96
96 * 8 + 16 = 784
(2222.5 – 1680 * 0.75)*1.2 = ?
Answer : 5. 1155
2222.5 – 1260 = 962.5; 962.5*1.2 = 1155
[(3√8 + √8) x (8√8 + 7√8)] – 98 = ?
Answer : 2. 382
[√8(3 + 1) x √8(8 + 7)] – 98
[4√8 x 15√8] – 98
480 – 98 = 382
572 ÷ 26 * 12 – 200 = (2)^?
Answer : 2. 6
572 ÷ 26 * 12 – 200
= 22 * 12 – 200 = 264 – 200 = 64 = (2)^6
350% of ? ÷ 50 + 248 = 591
Answer : 2. 4900
x = (343 * 100 * 50) / 350 = 4900
6561 ÷ (10.8 * 2.5) ÷ 3 = ?
Answer : 3. 81
= 6561 ÷ (27) ÷ 3 = 81
66, 71, 64, 75, 62, ?
Answer : 2. 79
66 – 64 = 2
75 – 71 = 4
64 – 62 = 2…..
(√5 – 2)^2 = ? – √80
Answer : 5. 9
= 5 + 4 – 4√5 + 4√5 = 9
x² – 13x + 40 = 0 y² – 8y + 15 = 0
Answer : 3. X ≥ Y
x² – 13x + 40 = 0
x = 8, 5
y² – 8y + 15 = 0
y = 5, 3
22240 ÷ √? = 34 * 12
Answer : 3. 3025
34 * 12 = 408
√? = 22240/408 = 54.5 = 55 => x = 3025
The profit earned after selling a book for Rs 1516 is the same as the loss incurred after selling the book for Rs 1112. What is the cost price of the book?
Answer : 1. Rs 1314
CP = 1516 + 1112 / 2 = 2628/2 = 1314
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