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IBPS PO 2018 Aptitude Test - 2
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IBPS PO 2018 Aptitude Test - 2
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  • Question 1/10
    1 / -0

    what should come in place of question mark (?) in the following questions?

    [(3024 ÷ 189)1/2 + (684 ÷ 19)2] = (?)2 + 459

    Solutions

     

  • Question 2/10
    1 / -0

    what should come in place of question mark (?) in the following questions?

    4.4 × 5/16 of 30% of 216 = ?

    Solutions

    ? = 4.4 × 5/16 × 64.8 = 89.1

     

  • Question 3/10
    1 / -0

    what should come in place of question mark (?) in the following questions?

    (0.0729 ÷ 0.1)3 ÷ (0.081 × 10)5 × (0.3 × 3)5 = (0.9)?+3

    Solutions

     

  • Question 4/10
    1 / -0

    what should come in place of question mark (?) in the following questions?

    Solutions

     

  • Question 5/10
    1 / -0

    In each of the following questions, a number series is given. Identify the wrong number in the series.

    5531, 5506, 5425 ,5304, 5135, 4910, 4621

    Solutions

    The number should be 5555 in place of 5531. 
    −72,−92,−112,−132,−152,−172...

     

  • Question 6/10
    1 / -0

    In each of the following questions, a number series is given. Identify the wrong number in the series.

    6, 7 ,9, 13 ,26, 37 ,69

    Solutions

    The number should be 21 in place of 26. 
    +1, +2, +4, +8, +16, +32

     

  • Question 7/10
    1 / -0

    In each of the following questions, a number series is given. Identify the wrong number in the series.

    1, 3 ,10 ,36 ,152 ,760 ,4632

    Solutions

    The number should be 770 in place of 760. 
    ×1 + 2, × 2 + 4, × 3 + 6, × 4 + 8, × 5 + 10, × 6 + 12,...

     

  • Question 8/10
    1 / -0

    The fare of a bus is Rs. x for the first five kilometres and Rs.13 per kilometre thereafter. If a passenger pays Rs. 2402 for a journey of 187 kilometres, what is the value of X?

    Solutions

    Let the fare of first five kilometres be x .
    Total distance = 187 km 
    Remaining distance = 187 – 5 = 182 km 
    Now,  x + 182  ×× 13 = 2402 
    x = 2402 – 2366 =Rs. 36

     

  • Question 9/10
    1 / -0

    The product of three consecutive even numbers is 4032. The product of the first and the third number is 252. What is five times the second number?

    Solutions

     

  • Question 10/10
    1 / -0

    The sum of the ages of 4 members of a family 5 years ago was 94 years. Today, when the daughter has been married off and replaced by a daughter-in-law, the sum of their ages is 92. Assuming that there has been no other change in the family structure and all the people are alive, what is the difference between the age of the daughter and that of the daughter-in-law?

    Solutions

    There are four members in a family. five years ago the sum of ages of the family members = 94 years 
    Now, sum of present ages of family members = 94 + 5  × 4 = 114 years 
    Daughter is replaced by daughter-in-law. 
    Thus, sum of family member’s ages becomes 92 years. 
    ∴∴  Difference = 114 – 92 = 22 years

     

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