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IBPS PO 2018 Aptitude Test - 6
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IBPS PO 2018 Aptitude Test - 6
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  • Question 1/10
    1 / -0

    DIRECTIONS: What will come in place of the question mark (?) in the following questions?

    74% of 1275 = 35% of 1056 + ? – 

    Solutions

    74% of 1275 = 35% of 1056 + ? – 

    943.5 – 369.6 = ? – (29 + 21)

    573.9 = ? – 50 

    ? = 573.9 + 50 = 623.9

     

  • Question 2/10
    1 / -0

    DIRECTIONS: What approximate value will come in place of the question mark (?) in the following questions?

    Solutions

     

  • Question 3/10
    1 / -0

    DIRECTIONS: What approximate value will come in place of the question mark (?) in the following questions?

    (7898 – 4267 + 1298) ÷ (524 – 156 – 98) = ? ÷ 43

    Solutions

    (7898 – 4267 + 1298) ÷ (524 – 156 – 98) =? ÷ 43

    4929 ÷ 270 = ? ÷ 43

    18.3 × 43 = ? 

    ? = 786.9 = 787

     

  • Question 4/10
    1 / -0

    DIRECTIONS: What will come in place of the question mark (?) in the following questions?

    Solutions

     

  • Question 5/10
    1 / -0

    DIRECTIONS: What value comes in place of the question mark (?) in the following series?

    14, 68, 338, ?, 8438, 42188

    Solutions

    14 × 5 – 2 = 68

    68 × 5 – 2 = 338

    338 × 5 – 2 = 1688

    1688 × 5 – 2 = 8438

    8438 x 5 – 2 = 42188

     

  • Question 6/10
    1 / -0

    DIRECTIONS: What value comes in place of the question mark (?) in the following series?

    72, 18, ?, 9, 18, 72

    Solutions

    72 × 1/4 = 18

    18 × 2/4 = 9

    9 × 4/4 = 9

    9 × 8/4 = 18

    18 × 16/4 = 72

     

  • Question 7/10
    1 / -0

    A man sells two radios for the same price, one at a loss of 10% and the other at a profit of 20%. What is the net profit%?

    Solutions

    Let the S.P. of each radio = Rs.360(LCM of 90 and 120)

    C.P. of one radio = 360/0.9 = Rs.400

    C.P. of second radio = 360/1.2 = Rs.300

    Total C.P. = Rs.700

    Total S.P. = Rs.720

     

  • Question 8/10
    1 / -0

    From 500 litres of pure milk, 10% is withdrawn and replaced by 50 litres of a mixture that contains 50% milk. If this operation is carried out for a total of 4 times, what is the final quantity of milk as a percentage of the initial quantity of milk approximately?

    Solutions

    From pure milk, 10% i.e. 50 litres milk is removed and replace by a mixture that contains 25 litres milk.

    After first replacement, amount of milk = 475 litres.

    After second replacement, amount of milk = 475 – 47.5 + 25 = 452.5 litres

    After third replacement, amount of milk = 452.5 – 45.25 + 25 = 432.25 litres

    After forth replacement, amount of milk = 432.25 – 43.225 + 25 = 414.025 litres

     

  • Question 9/10
    1 / -0

    An internet service provider charges a fixed amount as a service charge and Rs. 20/GB for downloads in excess of 1 GB. Only the service charge is billed in the event of downloads not exceeding 1 GB. One month, a user who had downloaded more than 3 GB was charged Rs. 650. The following month, the amount of downloads reduced by one third, and the bill was Rs. 510. What is the fixed service charge for the internet service?

    Solutions

     

  • Question 10/10
    1 / -0

    The area of a rectangle increases by 7 sq. units when its breadth alone is increased by 1 unit. Its area increases by 5 sq. unit when its length alone is increased by 1 unit. Find the perimeter of the original rectangle.

    Solutions

    Let length = l and breadth = b

    Area = l × b

    Case 1 : l(b + 1) – lb = 7

    l = 7

    Case 2: (l + 1)b – lb = 5

    b = 5

    Required perimeter = 2(l + b) = 2 (7 + 5) = 24 units

     

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