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IBPS PO 2018 Aptitude Test - 7
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IBPS PO 2018 Aptitude Test - 7
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  • Question 1/10
    1 / -0

    DIRECTIONS: In the given question two expressions numbered I and II are given. You have to solve both the expressions and give answer:

    I.   (729)−3 ÷ (6561)−4

    II.  81 × (3)10

  • Question 2/10
    1 / -0

    DIRECTIONS: What approximate value should come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value)

    11.89 × 12.14 ÷ 3.97 – 47.06 + 1.91 = ?

    Solutions

     

  • Question 3/10
    1 / -0

    DIRECTIONS: What will come in place of question mark (?) in the following number series?

    219, 223, 232, 248,?

    Solutions

     

  • Question 4/10
    1 / -0

    DIRECTIONS: What will come in place of question mark (?) in the following number series?

    4, 8, 32, 512, ?

    Solutions

     

  • Question 5/10
    1 / -0

    DIRECTIONS: Two equations are given in each question. Find the value of x and y and answer as

    I.  3x2    – 17x + 24 = 0

    II.  2y2    + 11y + 14 = 0

    Solutions

    Hence, x > y.

     

  • Question 6/10
    1 / -0

    DIRECTIONS: Two equations are given in each question. Find the value of x and y and answer as

    I.  7x2    – 47x – 14 = 0

    II.  3y2    – 16y – 12 = 0

    Solutions

    Hence, x > y and x < y both are possible.

    Hence, relation can't be established between x and y.

     

  • Question 7/10
    1 / -0

    A vessel of 80 liter is filled with milk and water. 70% of milk and 30% of water are taken out of the vessel. It is found that the vessel is empty by 55%. Find the initial quantity of milk and water.

    Solutions

    Here the % values of milk and water that is taken from the vessel should be taken into consideration.

     

  • Question 8/10
    1 / -0

    By selling 20 metres of cloth, a man gains the selling price of 4 metres of cloth. The gain percent is:

    Solutions

    % profit  = 4/16 × 100 = 25% 

    Alternate Solution:

    SP of 20m – CP of 20m = Gain = SP of 4m

    Therefore, SP of (20-4=16 m)=CP of 20m

    Let CP of each meter be Rs.1 then CP of 16m = Rs.16

    SP of 16m = Rs.20

    So, Gain% =(4/16)*100=25%

     

  • Question 9/10
    1 / -0

    Mr. More spent 20% of his monthly income on food and 15% on children’s education, 40% of the remaining he spent on entertainment and transport together and 30% on medical. He is left with an amount of ₹8775 after all these expenditures. What is Mr. More’s monthly income?

    Solutions

    Let the monthly income of Mr. More be=100x

    Remaining income after the expenditure on food and children education=65x

    A T Q,

    65x-65x (40+30)%=8775

    19.5x =8775

    =45,000

     

  • Question 10/10
    1 / -0

    At present. Pia is 6 year older to Ray. The respective ratio between the present ages of Pia and Mini is 3 : 4. At present, Ray is 14 year younger to Mini. What is Ray’s present age?

    Solutions

     

    18 years 

    Let Ray's present age is x years

    Then, Pia’s age =(x+6)yr

    Mini’s present age = x + 14

    Hence, Ray’s present age is 18 yr.

     

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