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IBPS Clerk 2018 Aptitude Test - 1
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IBPS Clerk 2018 Aptitude Test - 1
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  • Question 1/10
    1 / -0

    The diameter of a sphere is 8 cm. It is melted and drawn into a wire of diameter 3 mm. Find the length of the wire -

    Solutions

     

  • Question 2/10
    1 / -0

    A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a pole, then the length of the train is -

    Solutions

    Speed = 12/10 × 60 = 72 kmph = 20 m/sec.

    ∴ Length of train = 20 × 6 = 120 m.

     

  • Question 3/10
    1 / -0

    In this question two equations I and II are given. You have to solve both  equations and choose the right option.

    I. x2 – 5x – 84 = 0

    II. y2 – 3y – 28 = 0

    Solutions

     

  • Question 4/10
    1 / -0

    In this question two equations I and II are given. You have to solve both equations and choose the right option.

    I. x2 – 4x + 3 = 0

    II. y2 – 7y + 12 = 0

    Solutions

     

  • Question 5/10
    1 / -0

    What approximate value should come in place of question mark in following question ?

    12.50 × 14 ÷ 8.75 + 18 = 20 + ?

    Solutions

     

  • Question 6/10
    1 / -0

    What approximate value should come in place of question mark in following question ?

    42.6 × 162.8 ÷ 642.8 × 22.8 = 4?

    Solutions

    42.6 × 42 × 2.8 ÷ 43 × 2.8 × 41.4 = 4?

    42.6 + 5.6 – 8.4 + 1.4 = 4?

    ? = 1.2

     

  • Question 7/10
    1 / -0

    What approximate value should come in place of question mark in following question ?

    12.5% of 860 + 26% of 1240 = ?

    Solutions

     

  • Question 8/10
    1 / -0

    What approximate value should come in place of question mark in following question ?

    65% of 380 + 18% of 420 = ?

    Solutions

    ? = 322

     

  • Question 9/10
    1 / -0

    Cost of fencing a circular plot at the rate of 15 Rs./m is Rs. 3300. What will be the cost of flooring the plot at the rate of Rs. 100 per square metre ?

    Solutions

    Circumference of plot =  = 220 m

    ∴ 2πr = 220

    r = 35 m.

    ∴ Area of floor = 22/7 × 35 × 35 = 3850 m2

    So cost of flooring = 3850 × 100 = Rs. 385000

     

  • Question 10/10
    1 / -0

    In how many different ways can the letters of the word "LADDER" be arranged ?

    Solutions

     

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