Please wait...

Mixture and Alligation Test 1
Menu grid icon
Result Result point icon
Mixture and Alligation Test 1
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0

    Two equal glasses filled with mixtures of alcohol and water in the proportions of 2 : 1 and 1 : 1 respectively were emptied into third glass. What is the proportion of alcohol and water in the third glass?

    Solutions

    Alcohol in 1st glass = ⅔;

    water in 1st glass = ⅓

    Alcohol in 2nd glass = ½ ;

    water in 2nd glass = ½

    ∴ In 3rd glass,

    water =

    ∴ Required ratio

  • Question 2/10
    1 / -0

    A vessel is fully filled with a special liquid. Four litres of liquid is drawn out of this vessel and is replaced with water. If the ratio of the special liquid to the water becomes 1: 2, then what is the capacity the vessel?

    Solutions

    Let capacity of the vessel be x litres.

    Therefore,

    ∴ x = 6

  • Question 3/10
    1 / -0

    A cane contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the cane is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the cane initially?

    Solutions

    Suppose the cane initially contains 7x and 5x litres of mixtures A and B respectively.

    Quantity of A in mixture left

    =

    Quantity of B in mixture left

    =

    ⇒ 252 x – 189 = 140 x + 147

    ⇒ 112 x = 336

    ⇒ x = 3.

    So, the cane contained 21 litres of A.

  • Question 4/10
    1 / -0

    A jar of oil was four fifths full. When six bottles of oil were taken out and four bottles of oil were poured into, it was three fourths full. How many bottles of oil were contained by the jar?

    Solutions

    Let the capacity of the jar be of x bottles.

    Since 6 bottles were taken out from jar and 4 bottles of oil poured into it

    ∴ 2 bottles were taken out

    Therefore, we have

    ⇒ 

    ⇒ 

    ⇒ x = 40

  • Question 5/10
    1 / -0

    In three vessels, the ratio of water and milk is 6 : 7, 5 : 9 and 8 : 7, respectively. If the mixtures of the three vessels are mixed together, then what will be the ratio of water and milk?

    Solutions
      Water Milk Total
    1st vessel 6 7 13
    2nd vessel 5 9 14
    3rd vessel 8 7 15

    LCM of 13, 14 & 15 = 2730

    Increase value of total to 2730 as follows.

    1st vessel 1260 1470 2730
    2nd vessel 975 1755 2730
    3rd vessel 1456 1274 2730
    Total 3691 4499 8190

    ∴ Required ratio

    Alternate method is dividing options by 13, 14 & 15.

  • Question 6/10
    1 / -0

    An alloy contains copper and zinc in the ratio 5 : 3 and another alloy contains copper and tin in the ratio 8 : 5. If equal weights of both the alloys are melted together, then the weight of tin in the resulting alloy per unit will be:

    Solutions

    The first type of alloy does not contain tin. Second type alloy contains tin. Therefore, quantity of tin in 2 units of the resulting alloy = ⁵⁄₁₃

    ⇒ Quantity of tin in 1 unit of the resulting alloy

  • Question 7/10
    1 / -0

    A mixture (40 litres) contains tonic and water in the ratio 3 : 1. To make the ratio 7 : 2, how much additional amount of water is required?

    Solutions

    Tonic = 30 litres, Water = 10 litres

    Let x litres of water be added, then

    ⇒ 70 + 7x = 80 + 2x

    ⇒ 5x = 10

    ⇒ x = 2 litres.

  • Question 8/10
    1 / -0

    In a mixture of 45 litres, the ratio of milk and water is 4 : 1. How much water must be added to make the mixture ratio 3 : 2?

    Solutions

    Quantity of milk

     = 36 litres

    Quantity of water

     = 9 litres

    Let x litres of water be added to make the ratio 3 : 2

    Then, 

    ⇒ 72 = 27 + 3x

    ⇒ x = 15 litres

  • Question 9/10
    1 / -0

    In a mixture of 45 litres, the ratio of milk and water is 3 : 2. How much water must be added to make the ratio 9 : 11?

    Solutions

    Quantity of milk

    Quantity of water

    Let x litres of water be added to make the ratio 9 : 11.

    ∴ 

    ⇒ 18 + x = 33

    ⇒ x =15 litres

  • Question 10/10
    1 / -0

    Gold is 19 times as heavy as water and copper is 9 times heavy. In what ratio must these metals be mixed so that the mixture may be 15 times as heavy as water?

    Solutions

    By the rule of alligation, we have

    ∴ required ratio

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)


  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now