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12 years from now Maria will be twice as old as Steven. The current sum of the ages of Maria and Steven is 36. How old is Steven right now?
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Maria + 12 = 2 × (Steven + 12) Maria + Steven = 36 Maria = 36 - Steven 36 - Steven + 12 = 2 × (Steven + 12) 48 - Steven = 2 × Steven + 24 48 = 3 × Steven + 24 3 × Steven = 48 - 24 = 24 Steven = 8
Abhay’s age after six years will be three – seventh of his father age. Ten years ago the ratio of their ages was 1 : 5. What is Abhay’s father’s age at present?
Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,
Abhay’s age after 6 years = (x + 10) + 6 = (x + 16) years
Father’s age after 6 years = (5x + 10) + 6 = (5x + 16) years.
(x + 16) = (5x+16) ⇔ 7 (x + 16) = 3 (5x + 16) ⇔ 7x + 112 = 15x +48
⇔ 8x = 64 ⇔ x = 8
Hence, Abhav's father's present age = (5x + 10) = 50 years.
The average age of a class of 20 students is 20 years. When the age of the teacher is also included, the average will be increased by 2 years. What is the age of the teacher?
simple logic ---
We know that 20 student’s average = 20 years
20 people total age = 20 × 20 = 400 years
Including Teacher’s
21 people average = 22 years
21 people total age = 21 × 22 = 462
We know the age of 20 students = 400 years
We know the age of 21 people (20 students + Teacher) = 462
So the age of Teacher will be 462 – 400 = 62 Years.
The ratio between the school ages of Nikita and Sonam is 5 : 6 respectively. If the ratio between the one-third age of Nikita and half of Sonam’s age is 5 : 9, then what is the school age of Sonam?
Let the school ages of Nikita and Sonam be 5x and 6x years respectively. Then,
⇔ 15 = 15.
Thus, sonam's age cannot be determined
9 years from now Cindy will be 57 years old. In 13 years, the sum of the ages of Cindy and Miguel will be 126. How old is Miguel right now?
Cindy + 9 = 57 Cindy = 57 - 9 = 48 (Cindy + 13) + (Miguel + 13) = 126 (48 + 13) + (Miguel + 13) = 126 Miguel + 74 = 126 Miguel = 126 - 74 = 52
A man is 24 years older than his son. In two years, his will be twice the age of his son. The present age of his son is:
Let the son’s present age be x years. Then, man’s present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
6 years from now Jennifer will be 50 years old. In 5 years, the sum of the ages of Jennifer and Maria will be 96. How old is Maria right now?
Jennifer + 6 = 50 Jennifer = 50 - 6 = 44 (Jennifer + 5) + (Maria + 5) = 96 (44 + 5) + (Maria + 5) = 96 Maria + 54 = 96 Maria = 96 - 54 = 42
One year ago, the ratio of Gaurav’s and Sachin’s age was 6 : 7 respectively. Four years hence, this ratio would become 7 : 8. How old is Sachin?
Let Gaurav’s and Sachin’s ages one year ago be 6x and 7x years respectively. Then Gaurav’s age 4 years
Hence = (6x + 1) + 4 = (6x + 5) years
⇔8 (6x + 5) = 7 (7x + 5) ⇔ 48x + 40 = 49x + 35 ⇔ x = 5.
Hence, sachin's present age = (7x+1) = 36 years.
Amar is as much younger than Raja as he is older than Kiran. If the ages of Amar and Raja are 30 years and 36 years respectively, what is the age of Kiran now?
Simple logic……
Amar is as much younger than Raja as he is older than Kiran. Try to understand this sentence. According to this sentence you can understand that
Amar is younger than Raja that means there is some X years difference between Amar and Raja.
Amar is older than Kiran with same age difference (X years) between Amar and Kiran.
But we know that the ages of Amar and Raja are 30 and 36 years.
So the difference between their ages is = 6 years
So the difference between Amar and Kiran should be = 6 years.
We know the age of Amar as 30 years and Kiran is younger than Amar for 6 years. So he should be of 24 years.
With a single glance you can calculate answer for these type of problems.
The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56 ⇔ 20x = 80 ⇔ x = 4
∴ Their present ages are 16 yers, 28 years and 36 years respectively.
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