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Solutions
Total possible cases = 6 x 6 = 36
Number of way which sum of two digits should be 6 = (3, 3) (2, 4) (1,5) (4,2) (5,1)
So, total number of 5 cases possible
Number of way which sum of two digits should be 9 = (3,6) (4 ,5) (6,3) (5,4)
So, total number of 4 cases possible
Total possible cases = 5 + 4 = 9
Required probability = 9/36
=1/4