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LIC AAO Aptitude Test - 12
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LIC AAO Aptitude Test - 12
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  • Question 1/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the question given below-

    (A) Quantity I > Quantity II

    (B) Quantity I < Quantity II

    (C) Quantity I ≥ Quantity II

    (D) Quantity I ≤ Quantity II

    (E) Quantity I = Quantity II or no relation

    ...view full instructions


    Quantity I – Find the volume of the cylinder which height and radius is equal to breadth and length of rectangle respectively. The ratio between length to breadth of the rectangle is 2 : 1 and area is 220.5 cm2 .

    Quantity II - Find the volume of the cone which diameter is 56 cm and height is 18 cm.

    Solutions

    Quantity I – Let length and breadth of rectangle be 2x cm & x cm

    2x × x = 220.5

    x= 110.25

    x = 10.5 cm

    Length of rectangle  =10.5 × 2 = 21cm

    Breadth of rectangle = 10.5 cm

    Volume of cylinder = 22/7 × 21 × 21 × 10.5

    = 14553 cm3

    Quantity II - Volume of cone =  1/3 × 22/7 × 28 × 28 × 18

    =14784 cm3

     

  • Question 2/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the question given below-

    (A) Quantity I > Quantity II

    (B) Quantity I < Quantity II

    (C) Quantity I ≥ Quantity II

    (D) Quantity I ≤ Quantity II

    (E) Quantity I = Quantity II or no relation

    ...view full instructions


    Quantity I-  A, B and C can do a work in 12 days, while A & B together can do the same work in 16 days and B & C can do the same work is 24 day. Find in how many days A & C will complete work together.

    Quantity II -  P & Q can do a work in 24 days and 16 days respectively. R takes  days more than as P & Q takes together, then find in how many days R can do the same work alone?

    Solutions

    Quantity I  Total work = 48 units

    Efficiency of A + B + C  = 4 units/day

    Efficiency of A + B = 3 units/day

    Efficiency of B + C = 2 units/day

    Efficiency of B = 3 - 2 = 1 units/day

    So, efficiency of A and C = 4 – 1 =3 units/day

    A + C will do = 48/3 = 16 days

    Quantity II  

    Total work = 48 units

     

  • Question 3/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the question given below-

    (A) Quantity I > Quantity II

    (B) Quantity I < Quantity II

    (C) Quantity I ≥ Quantity II

    (D) Quantity I ≤ Quantity II

    (E) Quantity I = Quantity II or no relation

    ...view full instructions


    Quantity I : Shopkeeper marked price of article 40% above the cost price and allow two discounts of    & 4% respectively. If shopkeeper made a profit of Rs. 792, then find cost price of article.

    Quantity II :  A man sold a article and found he had made a loss of 4%, if he had sold the article Rs. 552 more, then he would made a profit of 7.5%. Then find cost price of article.

    Solutions

     

  • Question 4/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the question given below-

    (A) Quantity I > Quantity II

    (B) Quantity I < Quantity II

    (C) Quantity I ≥ Quantity II

    (D) Quantity I ≤ Quantity II

    (E) Quantity I = Quantity II or no relation

    ...view full instructions


    Quantity I:   A basket has 5 white and 9 green balls. There is another basket, which has 7 white and 7 green balls. One ball is to drawn from either of the two baskets. What is probability of drawing a green ball?

    Quantity II:   A tray contains 30 eggs out of which 8 are rotten. Two eggs are chosen at random. What is the probability that only one of the chosen eggs is rotten?

    Solutions

     

  • Question 5/10
    1 / -0

    Directions For Questions

    Read the following information carefully and answer the question given below-

    (A) Quantity I > Quantity II

    (B) Quantity I < Quantity II

    (C) Quantity I ≥ Quantity II

    (D) Quantity I ≤ Quantity II

    (E) Quantity I = Quantity II or no relation

    ...view full instructions


    Quantity I   Find the value 125% of P, if   of 75% of 80% of P is 5670.

    Quantity II    Find the value of Q, if 40% of 75% of 80% of Q is 45 more than square of 75.

    Solutions

     

  • Question 6/10
    1 / -0

    Ram can do 60% of a task in 12 days, while Shyam can do 40% of same task in  days and Mohan takes  days to complete 55% of same task. If all three work together, then find how many days required to complete the work?

    Solutions

     

  • Question 7/10
    1 / -0

    A fruit seller bought  dozens of bananas at the rate of Rs. 8 per banana. Out of total bananas some are good quality and some are bad quality, if seller sold good quality banana at the rate of Rs. 10 and bad quality banana at the rate of Rs. 2.8 per banana, so in this transaction there is no gain and no loss. Find total good quality of banana sold by fruit seller?

    Solutions

    Let good quality bananas are ‘x’ and bad quality banana are (90-x)

     

  • Question 8/10
    1 / -0

    P, Q and R inter into a business by making a investment of Rs. X , Rs (x + 2000) and Rs. (x + 3500) respectively. if P, Q and R invested for 9 months, 8 months and 6 months respectively. Find investment of P, if ratio between total profit share of P and (Q + R) is 12 : 31? 

    Solutions

    Let P invested for T months

    Ratio between profit share of P, Q and R =  x × 9 : (x + 2000) × 8 : (x + 3500) × 6

    = 9x : 8x + 16000 : 6x + 21000

    ATQ,


     

  • Question 9/10
    1 / -0

    Prashant took a loan of Rs. 250,000 from SBI at the rate of 12% compounded annually. If at the end of every year Prashant paid Rs. 120,000, then find amount should Prashant have to pay for clear his loan at the end of three years?

    Solutions

     

  • Question 10/10
    1 / -0

    A man have two dices. if he rolled both dice, then find the probability of that the sum of digits of both dice will be either 6 or 9?

    Solutions

    Total possible cases = 6 x 6 = 36

    Number of way which sum of two digits should be 6 = (3, 3) (2, 4) (1,5) (4,2) (5,1)

    So, total number of 5 cases possible

    Number of way which sum of two digits should be 9 = (3,6) (4 ,5) (6,3) (5,4)

    So, total number of 4 cases possible

    Total possible cases = 5 + 4 = 9

    Required probability =  9/36

    =1/4

     

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