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The following table shows the number (lakhs) of TV sets manufactured by six companies over the years
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What is the average number of TV sets manufactured by company C for all the given years?
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Average no. by C = (48+52+50+45+55+47)/6 = 49. 5 in lakhs
The number of TV sets manufactured by company E in 2004 is approximately what percent of the total number of TV sets manufactured by all the companies together in 2004 ?
No.of TV sets manufactured by E in 2004 = 56(in lakhs)
By all in 2004 = 281(lakhs)
% = 56/281*100 = 19.92%= 20%
What is the ratio between the total number TV sets manufactured by all the companies together in 2006 and that in 2007 respectively?
in 2006 =46+30+55+50+54+50 = 285
In 2007= 52+38+47+40+51+52 = 280
ratio = 285:280 = 57:56
Total number of TV’s manufactured by company A is approx. what percent of the total TVs manufactured by company F for all the given years together ?
By A = 45+40+48+49+46+52=280
By F = 49+45+48+44+50+52 =288
%=280/288 *100 = 97%
The number of TVs manufactured by company A is approx. what percent of the total number of TVs manufactured by company B in all the years together ?
By A= 280
Ratio = (280/208)*100 = 134.6%
There are two coaching classes P and Q of a institute, consisting of 46 and 54 candidates respectively. If the average weight of class P is 50kg and that of class Q is 45 kg, find the average weight of the whole institute.
Total number of candidates = 46+54=100
Weight of 46 candidates= 46*50=2300 kg
Weight of 54 candidates=54*45=2430 kg
Total weight of 100 candidates= 2300 kg+2430 kg=4730kg
Therefore average weight of the whole institute =4730/100 Therefore average weight=47.3 kg
A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is
Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have (X/2)/40 + (X/2)/50 = 4 X/80 + X/100 = 4
5X + 4X = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.
Water flows through a cylindrical faucet internal diameter 14cm at 4m per second. If the faucet is always half full, then what is the volume of water (in litres) discharged in 20 mins.
Volume of water flow in 1 sec =r2
=(22/7 *14 /2*14/2 *400)cu.cm
=61600 cu.cm
Volume of water flow in 20 min = (61600*60*20) cu.cm
=(61600*60*20 / 1000) litres
=73920 litres.
A pedal boat goes 12km upstream and 14km downstream in 3hrs. It goes 15km upstream and 10.5km downstream in 3 hrs 15mins. The speed of the boat in still water is
Let ‘x’ be the speed of the boat in still water
Let ‘y’ be the speed of the current.
Pedal boat will travel downstream at (x + y) km/hr and upstream (x – y) km/hr
Therefore 14/x +y + 12/ x –y = 3
10.5/(x+y) + 15/(x-y) = 3 ¼ = 13/4
70/(x+y) +60 /(x-y) =15 --à1
42 /(x+y) + 60/(x-y) = 13 --à2
From 1 and we get,
x+y = 14 ; x-y = 6
Therefore x= 10 ; y = 4
The speed of the pedal boat is 10 km/hr
The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son
Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years
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