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Let the length and breadth of the original rectangular field be x m and y m respectively.
Area of the original field
= x × y = 144 m²
∴
… (i)
If the length had been 6 m more, then area will be
(x + 6) y = 144 + 54
⇒ (x + 6) y = 198 … (ii)
Putting the value of x from eq (i) in eq (ii), we get

⇒ 144 + 6y = 198
⇒ 6y = 54 ⇒ y = 9 m
Putting the value of y in eq (i) we get x = 16 m