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SBI Clerk 2019 Aptitude Test - 4
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SBI Clerk 2019 Aptitude Test - 4
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  • Question 1/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

    A . x> y

    B.  x < y

    C. x ≥ y

    D. x ≤ y

    E. x = y or relationship cannot be determined

    ...view full instructions

    I. 4x2 – 9x – 9 = 0,

    II. 4y2 + 11y + 6 = 0

    Solutions

    4x2 – 9x – 9 = 0
    4x2 – 12x + 3x – 9 = 0
    Gives x = -3/4, 3
    4y2 + 11y + 6 = 0
    4y2 + 8y + 3y + 6 = 0
    Gives y = -2, -3/4
    Put all values on number line and analyze the relationship
    -2…. -3/4….3

     

  • Question 2/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

    A . x> y

    B.  x < y

    C. x ≥ y

    D. x ≤ y

    E. x = y or relationship cannot be determined

    ...view full instructions

    I. 3x2 – 2x – 21 = 0,

    II. 6y2 + 17y + 7 = 0

    Solutions

    3x2 – 2x – 21 = 0
    3x2 – 9x + 7x – 21 = 0
    Gives x = -7/3, 3
    6y2 + 17y + 7 = 0
    6y2 + 3y + 14y + 7 = 0
    Gives y = -7/3, -1/2

     

  • Question 3/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

    A . x> y

    B.  x < y

    C. x ≥ y

    D. x ≤ y

    E. x = y or relationship cannot be determined

    ...view full instructions

    I. 3x2 – 13x + 14 = 0,

    II. 3y2 – 20y + 32 = 0

    Solutions

    3x2 – 13x + 14 = 0
    3x2 – 6x – 7x + 14 = 0
    Gives x = 2, 7/3
    3y2 – 20y + 32 = 0
    3y2 – 12y – 8y + 32 = 0
    Gives y = 8/3, 4

     

  • Question 4/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

    A . x> y

    B.  x < y

    C. x ≥ y

    D. x ≤ y

    E. x = y or relationship cannot be determined

    ...view full instructions

    I. 3x2 – 2x – 16 = 0,

    II. 3y2 – 20y + 32 = 0

    Solutions

    3x2 – 2x – 16 = 0
    3x2 – + 6x – 8x – 16 = 0
    Gives x = -2, 8/3
    3y2 – 20y + 32 = 0
    3y2 – 12y – 8y + 32 = 0
    Gives y = 8/3, 4

     

  • Question 5/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

    A . x> y

    B.  x < y

    C. x ≥ y

    D. x ≤ y

    E. x = y or relationship cannot be determined

    ...view full instructions

    I. 5x2 – 16x – 16 = 0,

    II. 3y2 – 14y + 8 = 0

    Solutions

    5x2 – 16x – 16 = 0
    5x2 – 20x + 4x – 16 = 0
    Gives x = -4/5, 4
    3y2 – 14y + 8 = 0
    3y2 – 12y – 2y + 8 = 0
    Gives y= 2/3, 4

     

  • Question 6/10
    1 / -0

    Meera, Swapna and Rishwi started a business where their initial capital was in the ratio of 1:2:3. At the end of 6 months, Meera invested an amount such that his total capital became equal to Rishwi's initial capital investment. If the annual profit of Swapna is Rs.4500 then what is the total profit  ? 

    Solutions

    Ratio of investments of Meera, Swapna & Rishwi =(1×6+3×6) : 2×12 :3×12

    = (6+18) : 24 : 36

    = 24: 24 : 36

    =2:2:3

    But given that the annual profit of Swapna is Rs.4500

    2 ratio = 4500

    Then for the total annual profit of partners is

    7 ratio = 4500 x 7/2

    = 15,750

     

  • Question 7/10
    1 / -0

    A car worth Rs.300000 is sold by Rajesh to Praveen at 10% profit. Praveen sells the car back to Rajesh at 4% loss. Then in the entire transaction Rajesh gets the loss/ gain is?

    Solutions

    Money spent by Rajesh = Rs.300000

    Money received by Rajesh = 110% of Rs.300000

    =110/100 * 300000

    =Rs.330000

    =96/100*330000

    =Rs.316800

    Rajesh gains = S.P – C.P

    =330000 – 316800

    =Rs.13200

     

  • Question 8/10
    1 / -0

    Sanjai got gold medal for his studies 4 years ago. His present age is 3/2 times his age at the time of he got the prize. Sanjai’s brother was 5 years younger to him at the time of his prize event. The age of sanjai’s brother is.

    Solutions

    Let sanja’s present age be x yrs

    Then, his age at the time of he got the prize = (x-4)yrs

    Therefore x = 3/2(x-4)

    2x = 3(x-4)

    2x = 3x -12

    3x – 2x =12

    X = 12

    Sanjai’s brother age at the time of he got the gold medal

    =((x-4) – 5) yrs

    =((12 – 4) – 5)

    =(12-9)

    3 yrs

    Sanjai’s brother present age = (x+4) yrs

    =3+4

    =7 yrs

     

  • Question 9/10
    1 / -0

    5 years ago, the average age of Mr. Ravi family of 5 members was 30 years. 2 children having been born with the difference of 3 years, the present average age of the family is the same. The present age of the youngest child is.

    Solutions

    Total age of 5 members, 5 yrs ago = (30*5)

    =150yrs

    Total age of 5 members now = (150 + (5*5))

    =150+25 = 175 yrs

    Total age of 7 members now = (30*7) = 210 yrs

    Sum of the ages of 2 children = (210 – 175) yrs

    =35 yrs

    Let the age of the younger child be x yrs.

    Then age of the elder child = (x+3) yrs

    So x=x+3 = 35

    2x +3 = 35

    2x = 32

    X=16

    Age of younger child is 16 yrs

     

  • Question 10/10
    1 / -0

    Daniel speaks truth in 2/5 cases and Sherin lies in 3/7 cases. What is the percentage of cases in which both Daniel and Sherin contradict each other in stating a fact?

    Solutions

    Daniel and Sherin will contradict each other when one speaks truth and other speaks lies.

    Probability of Daniel speak truth and Sherin lies

    =2/5*3/7

    =6/35

    Probability of Sherin speak truth and Daniel lies

    =4/7*3/5

    =12/35

    The two probabilities are mutually exclusive. 
    Hence, probabilities that Daniel and Sherin contradict each other:

    =6/35 +12/35

    =18/35

    =18/35*100

    =51.4%

     

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