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SBI Clerk 2019 Aptitude Test - 6
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SBI Clerk 2019 Aptitude Test - 6
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  • Question 1/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

    1. if x > y

    2. if x < y

    3. if x ≥ y

    4. if x ≤ y

    5. if x = y or no relation can be established between ‘x’ and ‘y’.

    ...view full instructions

    1. 2x^2 - 11x + 15 = 0

    2. 21y^2 - 23y + 6 = 0

    Solutions

    I.2x^2 - 6x - 5x + 15 = 0

    or,2x(x - 3) - 5(x - 3) = 0

    or, (2x - 5) (x - 3) = 0

    x = 3, 5/2

    II.21y^2- 14y - 9y + 6 = 0

    or,7y(3y - 2) - 3 (3y - 2) = 0

    or,(7y - 3)(3y - 2) = 0

    y = 3/7, 2/3

     x > y

     

  • Question 2/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

    1. if x > y

    2. if x < y

    3. if x ≥ y

    4. if x ≤ y

    5. if x = y or no relation can be established between ‘x’ and ‘y’.

    ...view full instructions

    I. 5x^2 - 16x + 11= 0

    II. 5y^2 - 3y - 2 = 0

    Solutions

    I.5x^2 - 5x - 11x + 11 = 0

    or,5x(x - 1) - 11(x - 1) = 0

    or,(x - 1) (5x - 11) = 0

    x = 1,11/5

    II.5y^2- 5y + 2y - 2 = 0

    or, 5y (y - 1) + 2(y - 1) = 0

    or, (5y + 2)(y - 1) = 0

    y = 1, -2/5

    x ≥ y

     

  • Question 3/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

    1. if x > y

    2. if x < y

    3. if x ≥ y

    4. if x ≤ y

    5. if x = y or no relation can be established between ‘x’ and ‘y’.

    ...view full instructions

    I. x^2 + 11x + 28 = 0

    II. 2y^2 + 13y + 20 = 0

    Solutions

    I.x^2+ 4x + 7x + 28 = 0

    or, x(x + 4) +7(x + 7) = 0

    or, (x + 4) (x + 7) = 0

    x = - 4, - 7

    II.2y^2+ 8y + 5y + 20 = 0

    or, 2y(y + 4) + 5(y + 4) = 0

    or, (y + 4) (2y + 5) = 0

     y = -4,-5/2

    x ≤ y

     

  • Question 4/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

    1. if x > y

    2. if x < y

    3. if x ≥ y

    4. if x ≤ y

    5. if x = y or no relation can be established between ‘x’ and ‘y’.

    ...view full instructions

    I. 6x^2 + 29x + 35 = 0

    II. 3y^2 + 19y + 30 = 0

    Solutions

    I.6x^2+ 15x + 14x + 35 = 0

    or, 3x(2x + 5) + 7(2x + 5) = 0

    or,(3x + 7) (2x + 5) = 0

    x=-7/3,  -5/2

    II.3y^2+ 9y + 10y + 30 = 0

    or, 3y(y + 3) +10(y + 3) = 0

    or,(3y + 10) (y + 3) = 0

    y = -3, -10/3

    x > y

     

  • Question 5/10
    1 / -0

    Directions For Questions

    In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

    1. if x > y

    2. if x < y

    3. if x ≥ y

    4. if x ≤ y

    5. if x = y or no relation can be established between ‘x’ and ‘y’.

    ...view full instructions

    I. 2x + 5y = 6

    II. 5x + 11y = 9

    Solutions

    Eqn (I) × 5 - eqn(II) × 2

    (10x + 25y = 30) – (10x ± 22y = 18) =

    3y = 12

     y = 4 and x = -7

    y > x

     

  • Question 6/10
    1 / -0

    What approximate value should come in place of question mark (?) in the following questions?

    184.96% of 4699.658 + 274.93% of 6279.88 – 648 = ?

    Solutions

    ? = 184.96% of 4699.658 + 274.93% of 6279.88 – 648

    = (185/100)×4700 + (275/100) ×6280 – 648

    = 185 × 47 + 200 % of 6280 + 75% of 6280 – 648 = 8695 + 12560 + 4710 – 648

    ?= 8695+17270 – 648 = 25317 = 25320

     

  • Question 7/10
    1 / -0

    What approximate value should come in place of question mark (?) in the following questions?

    8789.879 ÷ 375.002 × 24.996 + 6937.004 = ?

    Solutions

    ? = 8789.879 ÷ 375.002 × 24.996 + 6937.004

    = 8790 ÷ 375 × 25 + 6937

    = (8970/375) × 25 + 6937 = (8790/15) + 6937 = 586 + 6937 = 7523 = 7525

     

  • Question 8/10
    1 / -0

    What approximate value should come in place of question mark (?) in the following questions?

    (17.67)2 + (16.87)3 – (8.947)3 ÷ 103.897 = ?

    Solutions

    (17.67)2 + (16.87)3 – (8.947)3 ÷103.897 = ?

    Or, ? = (17.7)2 + (16.9)3 – (9)3 ÷ 104

    = 313.29 + 4826.809 – 729 ÷ 104

    = 313 + 4827 – 7 = 5133 = 5130

     

  • Question 9/10
    1 / -0

    What approximate value should come in place of question mark (?) in the following questions?

    5 3/10 × 7  6/7 × 9 ½ = ?

    Solutions

    5 3/10 × 7 6/7 × 9 ½ = ?

     = (53/10) × (55/7) × (19/2)

    = 55385/140 = 395 = 400

     

  • Question 10/10
    1 / -0

    What approximate value should come in place of question mark (?) in the following questions?

    (2892 ÷12) × 13 = ? % of 2410

    Solutions

    (2892 ÷12) × 13 = ? % of 2410

    241 *13 = (x/100) * 2410

    3133 *100 /2410 =x

    x= 130

     

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