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SBI Clerk 2019 Aptitude Test - 7
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SBI Clerk 2019 Aptitude Test - 7
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  • Question 1/10
    1 / -0

    Forty percent of Mouli’s annual salary is equal to 160% of Surya’s annual salary. Surya’s monthly salary is 80%of Gowthaman’s monthly salary. If Gowthaman’s annual salary is 12 lacs, what is Mouli’s monthly salary? (At some places annual income and in some place monthly income is given)

    Solutions

     Gowthaman’s monthly salary = 12,00,000/12

      = 1,00,000

     Surya’s monthly salary = 1,00,000 x 80/100

      = 80,000

    Mouli’s monthly salary = 80,000x 160/40

    =3,20,000

     

  • Question 2/10
    1 / -0

    A receptacle is in the form of a hemi-spherical bowl on which is mounted a hollow cylinder. The diameter of the sphere is 22 cm and the total height of receptacle is 35cm, find the capacity of the receptacle.
     

    Solutions

    Diameter is 22, so radius is 11cm
    Total height = 35 cm, so height of cylinder = 35-11 = 24cm (because height of hemisphere is same as its radius)
    Capacity of vessel = volume of cylinder + volume of hemisphere
    So = πr2h + 2/3 *πr3
    = 22/7 * 11 * 11 * 24+ 2/3 * 22/7 * 11 * 11 * 11

    = 9126.85+2788.76

    = 11915.61cu cm

     

  • Question 3/10
    1 / -0

    Suprith bought 40 kg of rava at the rate of Rs.8.50 per kg and 55 kg at the rate of Rs.8.75 per kg. He mixed the two. Approximately at what price per kg should he sell the mixture to make 40% profit at the cost price?

    Solutions

    Total cost price = 40* 8.5+ 55* 8.75

    = 821.25

    Total selling price = 821.25*140/100

    = 1149.75

    Required selling price per kg = 1149.75/95= Rs. 12

     

  • Question 4/10
    1 / -0

    A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mins to cover a distance of 10km upstream. Find the speed of the river current in km/hr(Approx).

    Solutions

    Rate downstream = (30 / 5 ½ ) km/hr

    = 30 / (11/2) km/hr

    = 30 * 2 / 11 km/hr

    = 60/11 km/hr

    Rate upstream     = (10 / 4 ¼)km/hr

    = 10 / (17/4)km/hr

    = 10 * 4 / 17 km/hr

    = 40 / 17 km/hr

    Speed of current    = 1 / 2 (a – b) km/hr

    =1 / 2 (60 /  11 – 40 / 17)

    = 1.5 km/hr (approx.)

     

  • Question 5/10
    1 / -0

    Consider a pack contains 2black, 9 white and 3 pink pencils. If a pencil is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 black pencils and 1 pink pencil?

    Solutions

    Here, total number of pencils = 14

    Probability of drawing 1 black pencil = 2/14
    Probability of drawing another black pencil = 2/14
    Probability of drawing 1 pink pencil = 3/14
    Probability of drawing 2 black pencils and 1 pink pencil = 2/14 * 2/14 * 3/14 = 3/686

     

  • Question 6/10
    1 / -0

    Sakthi running at 27 kmph along the railway track. He was 272 metres ahead of the engine. A 240 metres long train running at 135 kmph in the same direction of sakthi. How much time will the train take to pass sakthi?

    Solutions

     Speed of the train = 135 kmph

    Speed of  sakthi = 27 kmph

    Speed of train relative to sakthi = (135-27) kmph

    =108 kmph

    We have to find the time in seconds, so convert the speed in the unit of m/sec.

    108 kmph = (108 * 5/18) m/s

    = 30 m/s

    Length of the train = 240 m

    Distance covered by sakthi = 272m

    Total Distance to be covered = (240 +272) m

    = 512 m

    Speed of the train = Distance / Time

    Therefore Time taken = (512 / 30) sec

    = 17 sec

     

  • Question 7/10
    1 / -0

    In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam?

    Solutions

    Let the number of paper be A.

    Then total marks earned him = 75A

    from questions,

    75A + 33+ 27= 78A

    3A = 60=> A=20 = number of subjects

     

  • Question 8/10
    1 / -0

    Sukumar purchases 10 goats at Rs. 1500 each. 1 goat died. He sold 2 goats at 5% loss, at what rate he should sale the remaining goat, so as to gain a Profit of 10 % on the total Cost?

    Solutions

    Selling Price with Profit of 10 % of total cost = 1500*10*110/100

    = 16500

    Selling Price of 2 goat with 5% loss= 3000*95/100

    = 2850

    Difference = 16500-2850= 13650

    So rate of the goats for selling to gain 10% profit on total = 13650/7

    = Rs. 1950

     

  • Question 9/10
    1 / -0

    Agalya started a work with Rs. 144000 and after 3 months Bhuvana joined with her the amount of Rs. 116000. At the end of the year bhuvana received a profit of Rs. 20960 including 16% as a commission for maintain the work. Find the profit earned by agalya at the end of the year approximately?

    Solutions

    Ratio of agalya & bhuvana

    144000*12: 116000*9= 48:29

    Let the total profit be Z.

    Profit earned by bhuvana =16 % of Z+ 29/77 of 84 % of Z=20960

    524Z= 20960 * 100 *11 => Z= Rs.44000.

    Total profit by agalya          

    =48/77 *84/100 *44000 = Rs.23040.

     

  • Question 10/10
    1 / -0

    Kriya deposits an amount of Rs. 65800 to obtain in a simple interest at the rate of 14 p.c.p.a. for 4 years. What total amount will Kriya get at the end of 4 years?

    Solutions

    100===156

    65800===?

    102648

     

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