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Solutions
From statement I, cannot be determine because work completed by C alone cannot be given.
From statement II. Let total work LCM of 20, 30 and 15 =60 units.
Work completed by A in one day = 60/20 = 3 units
Work completed by B in one day = 60/30 = 2 units
Work completed by C and D together in one day = 60/15 = 4 units
Work completed by A, B, C and D together in one day = 3 + 2 +4 =9 units
Work completed by A, B, C and D together in 5 days =5 x 9 =45 unts
Remaining work = 60 -45 =15 units.
Remaining work completed by A = 15/3 = 5 days