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SBI Clerk 2019 Aptitude Test - 13
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SBI Clerk 2019 Aptitude Test - 13
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  • Question 1/10
    1 / -0

    The average monthly salary of 25 employees in an organization is Rs. 3000. If the manager’s salary is added, then the average salary increases by Rs. 500. What is the manager’s monthly salary? 

    Solutions

    Manager’s monthly salary = Rs. (3500 × 26 - 3000 × 25) = Rs. 16000. 

     

  • Question 2/10
    1 / -0

    The sum of the present ages of a father and his son is 75 years. Five years ago father’s age was four times the age of the son. After 4 years, son’s age will be: 

    Solutions

    Let the present ages of son and father be x and (75 - x) years respectively.

    Then, (75 - x) - 5 = 4 (x - 5) ⇔  70 - x = 4x - 20 ⇔ 5x = 90 ⇔  x = 18. 

    ∴ Son’s age after 4 years = (x + 4) = 22 years.  

     

  • Question 3/10
    1 / -0

    In an examination, there are three papers and a candidate has to get 40% of the total to pass. In one paper, he gets 62 out of 150 and in the second 45 out of 150. How much must he get, out of 180, in the third paper to just qualify for a pass?  

    Solutions

    Let the marks required be x. Then, (62 + 45 + x) = 40% of (150 + 150 + 180) 

    ⇔ 107 + x = (40/100) ×480 ⇔ x=192-107=85. 

     

  • Question 4/10
    1 / -0

    At what percent above the cost price must a shopkeeper mark his goods so that he gains 40% even after giving a discount of 20% on the marked price? 

    Solutions

    Let C.P. = Rs. 100. Then, S.P. = Rs. 140. 

    Let marked price be Rs. x. Then, 80% of x = 140 ⇒ x= ((140 × 100)/80) =175 

    ∴ Marked price =75% above C.P.   

     

  • Question 5/10
    1 / -0

    The prices of a scooter and a T.V. are in the ratio 6: 5. If the scooter costs Rs. 10000 more than a T.V. set, then the price of a T.V. set is:  

    Solutions

    Let the prices of a scooter and a T.V. set be Rs. 6x and Rs. 5x respectively. Then, 6x - 5x = 10000 ⇔ x = 10000

    ∴ Price of T.V. set = Rs. (5 × 10000) = Rs. 50000.

     

  • Question 6/10
    1 / -0

    The sum of five consecutive even numbers is equal to 180. What is the sum of the largest number amongst them and the square of the second smallest number amongst them together?  

    Solutions

    Let the five consecutive even numbers are 2x, 2x + 2, 2x + 4, 2x + 6, 2x + 8 respectively. 

    According to the question, 

    2x + 2x + 2 + 2x + 4 + 2x + 6 + 2x + 8 = 180 

    10x + 20 = 180 

    10x = 160 

    x=160/10=16  

    ∴ The five numbers are 32, 34, 36, 38, 40 respectively. 

    ∴ Required sum =(34)2+40=1156+40=1196 

     

  • Question 7/10
    1 / -0

    The size of a plastic block is 15*30 *60 cm. how many such blocks will be required to construct a solid plastic cube of minimum size?

    Solutions

    Side of smallest cube = LCM of 15, 30 and 60

    LCM of 15, 30 and 60 = 60cm

    Volume of the cube = (60*60*60) cu.cm

    =216000cu.cm

    Volume of the block = (15*30*60) cu.cm

    =27000 cu.cm

    No. of blocks = volume of the cube / volume of the block

    =216000 / 27000

    =8

     

  • Question 8/10
    1 / -0

    Manohar got 56 marks in Hindi, 75 marks in Science, 89 marks in Maths, 69 marks in Social Science and 91 marks in English. The maximum marks of each subject are 100. How much overall percentage of marks did he get? 

    Solutions

    Marks in all subjects = 56 + 75 + 89 + 69 + 91 = 380 

    Total maximum marks = 5 × 100 = 500 

    ∴ Required percentage =380/500×100=76%

     

  • Question 9/10
    1 / -0

    7 women cam complete a piece of work in 16 h. In how many hours will 14 women complete the same piece of work? 

    Solutions

    7 women can complete a piece of work in = 16 h 

    1 woman can complete a piece of work in = (16 × 7) h = 112 h 

    ∴ 12 women can complete a piece of work in =112/14 = 8 h 

     

  • Question 10/10
    1 / -0

    The length of a rectangle is 42 cm which is 14 cm more than the diameter of a circle. What is the area of the circle? 

    Solutions

    ∴ Diameter of a circle = 42 - 14 = 28 cm 

    ∴ Radius of a circle =28/2 = 14 cm 

    ∴ Area of a circle =πr^2=22/7×14×14=616 sq cm

     

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