Aptitude Test 2

Result

Aptitude Test 2

/

Score
-

Rank

Time Taken: -

Question 1/10
1 / -0

The pie diagrams on the monthly expenditure of two families A and B are drawn with radii of two circles taken in the ratio 16 : 9 to compare their expenditures.

Which one of the following is the appropriate data used for the above mentioned pie diagram?

Correct

Wrong

Skipped
A
Rs. 16,000 and Rs. 9,000

Correct

Wrong

Skipped
B
Rs. 8,000 and Rs. 4,500

Correct

Wrong

Skipped
C
Rs. 25,600 and Rs. 8,100

Correct

Wrong

Skipped
D
Rs. 4,000 and Rs. 3,000

Verify mobile number to view the solution

Solutions

In pie chart, Data ∝ Area

Area = πr²

∴ Income ∝ Radius²

Income of A/Income of B = (16/9)² = 256/81

In option (3)

Income of A/Income of B = 25600/8100 = 256/81

∴ The appropriate data is Rs. 25,600 and Rs. 8,100
Question 2/10
1 / -0

Consider the following statements:

Statement I: The value of a random variable having the highest frequency is mode

Statement II: Mode is unique

Which one of the following is correct in respect to the above statements?

Correct

Wrong

Skipped
A
Both Statement I and Statement II are true and Statement II is the correct explanation of Statement I

Correct

Wrong

Skipped
B
Both Statement I and Statement II are true and Statement II is not the correct explanation of Statement I

Correct

Wrong

Skipped
C
Statement I is true but Statement II is false

Correct

Wrong

Skipped
D
Statement I is false but Statement II is true

Verify mobile number to view the solution

Solutions

Mode is defined as the data with maximum frequency. In case two or more data have same frequencies, then both are mode

∴ Mode is not unique

For example, If the data set is 13, 14, 14, 15, 15 and 16

Both 14 and 15 are modes

∴ Statement I is true but Statement II is false
Question 3/10
1 / -0

Which one of the following is not correct?

The proportion of various items in a pie diagram is proportional to the

Correct

Wrong

Skipped
A
Area of slices

Correct

Wrong

Skipped
B
Angles of slices

Correct

Wrong

Skipped
C
Lengths of the curved surface arcs of slices

Correct

Wrong

Skipped
D
Perimeters of the slices

Verify mobile number to view the solution

Solutions

Data in a pie chart ∝ Area

Area = θ/360 × πr²

∴ Area ∝ θ

∴ Data ∝ θ, where θ is the angle of slice

Length of the curved surface = θ/360 × 2πr

∴ Length of curved surface of arc ∝ θ

∴ Data ∝ Length of the curved surface

Perimeter of slices = θ/360 × 2πr + 2r

∴ Perimeter of slices is not proportional to the data
Question 4/10
1 / -0

The geometric mean of x and y is 6 and the geometric mean of x, y and z is also 6. Then the value of z is

Correct

Wrong

Skipped
A
12

Correct

Wrong

Skipped
B
√6

Correct

Wrong

Skipped
C
6

Correct

Wrong

Skipped
D
∛6

Verify mobile number to view the solution

Solutions

Geometric mean of n numbers = (Product of numbers)^1/n

⇒ Geometric mean of x and y = (xy)^1/2

⇒ 6 = (xy)^1/2

⇒ Squaring on both the sides

⇒ 36 = xy

Geometric mean of x, y and z = (xyz)^1/3

⇒ 6 = (xyz)^1/3

Cubing on both the sides

⇒ 216 = xyz

⇒ 216 = 36z

∴ z = 216/36 = 6
Question 5/10
1 / -0

The heights (in cm) of 5 students are 150, 165, 161, 144 and 155. What are the values of mean and median (in cm) respectively?

Correct

Wrong

Skipped
A
165 and 161

Correct

Wrong

Skipped
B
155 and 155

Correct

Wrong

Skipped
C
160 and 155

Correct

Wrong

Skipped
D
155 and 161

Verify mobile number to view the solution

Solutions

On arranging the heights in ascending order

144, 150 155, 161 and 165

Median = Middle most term = 155

Sum of the heights = 144 + 150 + 155 + 161 + 165 = 775

Mean = Sum/Number of observations = 775/5 = 155

∴ Mean and median are 155 and 155 respectively
Question 6/10
1 / -0

The total number of live births in a specific locality during different months of a specific year was obtained from the office of the Birth registrar. This set of data may be called

Correct

Wrong

Skipped
A
Primary data

Correct

Wrong

Skipped
B
Secondary data

Correct

Wrong

Skipped
C
Recorded data

Correct

Wrong

Skipped
D
Countable data

Verify mobile number to view the solution

Solutions

The data required was not collected directly from source but from others

∴ It is secondary data
Question 7/10
1 / -0

The average height of 22 students of a class is 140 cm and the average height of 28 students of another class is 152 cm. What is the average height of students of both classes?

Correct

Wrong

Skipped
A
144.32 cm

Correct

Wrong

Skipped
B
145.52 cm

Correct

Wrong

Skipped
C
146. 72 cm

Correct

Wrong

Skipped
D
147.92 cm

Verify mobile number to view the solution

Solutions

The difference in the averages of the first class and second class = 152 – 140 = 12

This difference from 28 students will be now distributed to all students

Increase in average = 28 × Difference/Number of students

⇒ 28 × 12/ (28 + 22) = 6.72

∴ New average = 140 + 6.72 = 146.72 cm
Question 8/10
1 / -0

To maintain 8 cows for 60 days, a milkman spends Rs. 6400. To maintain 5 cows for n days, he spends Rs. 4800. What is the value of n?

Correct

Wrong

Skipped
A
46 days

Correct

Wrong

Skipped
B
50 days

Correct

Wrong

Skipped
C
58 days

Correct

Wrong

Skipped
D
72 days

Verify mobile number to view the solution

Solutions

Amount spent for maintaining 8 cows for 60 days = Rs. 6400

⇒ Amount spent for maintaining 8 cows for 1 day = 6400/60 = Rs. 1600/15

⇒ Amount spent for maintaining 1 cow for 1 day = (1600/15) /8 = Rs. 200/15

⇒ Amount spent for maintaining 5 cows for 1 day = 200/15 × 5 = 200/3

⇒ Amount spent for maintaining 5 cows for n days = 200n/3 = Rs. 4800

⇒ 4800 = 200n/3

∴ n = 4800 × 3/200 = 72 days
Question 9/10
1 / -0

A student secure 40% of the marks to pass an examination. He gets only 45 marks and fails by 5 marks. The maximum marks are

Correct

Wrong

Skipped
A
120

Correct

Wrong

Skipped
B
125

Correct

Wrong

Skipped
C
130

Correct

Wrong

Skipped
D
150

Verify mobile number to view the solution

Solutions

Total marks required for passing = 45 + 5 = 50 marks

50 marks is 40% of the maximum marks

⇒ 50 = 40/100 × Maximum marks

∴ Maximum mark = 50 × 100/40 = 125 marks
Question 10/10
1 / -0

What is the value of u in the system of equations 3 (2u + v) = 7uv, 3 (u + 3v) = 11uv?

Correct

Wrong

Skipped
A
0

Correct

Wrong

Skipped
B
1/4

Correct

Wrong

Skipped
C
1/2

Correct

Wrong

Skipped
D
1

Verify mobile number to view the solution

Solutions

3 (2u + v) = 7uv

On dividing by uv

⇒ 6/v + 3/u = 7 ---- 1

3 (u + 3v) = 11uv

On dividing by uv

⇒ 3/v + 9/u = 11 ---- 2

2 × Equation 2 – Equation 1

⇒ 6/v + 18/u – 6/v – 3/u = 22 – 7

⇒ 15/u = 15

∴ u = 15/15 = 1

Question 1/10

Rs. 16,000 and Rs. 9,000

Rs. 8,000 and Rs. 4,500

Rs. 25,600 and Rs. 8,100

Rs. 4,000 and Rs. 3,000

Question 2/10

Both Statement I and Statement II are true and Statement II is the correct explanation of Statement I

Both Statement I and Statement II are true and Statement II is not the correct explanation of Statement I

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Question 3/10

Area of slices

Angles of slices

Lengths of the curved surface arcs of slices

Perimeters of the slices

Question 4/10

12

√6

6

∛6

Question 5/10

165 and 161

155 and 155

160 and 155

155 and 161

Question 6/10

Primary data

Secondary data

Recorded data

Countable data

Question 7/10

144.32 cm

145.52 cm

146. 72 cm

147.92 cm

Question 8/10

46 days

50 days

58 days

72 days

Question 9/10

120

125

130

150

Question 10/10

0

1/4

1/2

1