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RRB Office Assistant Aptitude Test - 4
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RRB Office Assistant Aptitude Test - 4
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  • Question 1/10
    1 / -0

    What should come in place of question mark (?) in the following number series?

    4, ?, 4, 9, 32, 155

    Solutions

    4 × 1 – 1 = 3

        3 × 2 – 2 = 4

        4 × 3 – 3 = 9

        9 × 4 – 4 = 32

        32 × 5 – 5 = 155

    Hence, 3 will replace the question mark.

     

  • Question 2/10
    1 / -0

    What should come in place of question mark (?) in the following number series?

    16, 14, 25, 71, ?, 1389

    Solutions

    16 × 1 – 2 = 14

        14 × 2 – 3 = 25

        25 × 3 – 4 = 71

        71 × 4 – 5 = 279

        279 × 5 – 6 = 1389

    Hence, 279 will replace the question mark.

     

  • Question 3/10
    1 / -0

    What should come in place of question mark (?) in the following number series?

    12, 43, 74, 108, 148, ?

    Solutions

    Hence, 197 will replace the question mark.

     

  • Question 4/10
    1 / -0

    What should come in place of question mark (?) in the following number series?

    ?, 212, 112, 64, 42, 33

    Solutions

    416 ÷ 2 + 4 = 212

        212 ÷ 2 + 6 = 112

        112 ÷ 2 + 8 = 64

        64 ÷ 2 + 10 = 42

        42 ÷ 2 + 12 = 33

    Hence, 416 will replace the question mark.

     

  • Question 5/10
    1 / -0

    What should come in place of question mark (?) in the following number series?

    2, 24, 14, 122, 34, ?

    Solutions

    22  – 2 = 4 – 2 = 2

    33 – 3 = 27 – 3 = 24

    42 – 2 = 16 – 2 = 14

    53  – 3 = 125 – 3 = 122

    62 – 2 = 36 – 2 = 34

    73 – 3 = 343 – 3 = 340

    Hence, 340 will replace the question mark.

     

  • Question 6/10
    1 / -0

    Two equations are given in each of the questions given below. Find the value of x and y by solving equations and answer as:

    I. x2 = 169

    II. y2  – 24y + 144 = 0

    Solutions

    ∴ Relation can't be established

     

  • Question 7/10
    1 / -0

    Two equations are given in each of the questions given below. Find the value of x and y by solving equations and answer as:

    I.  3x– 13x + 12 = 0

    II.  3y2 – 13y + 14 = 0

    Solutions

    ∴ Relation can't be established

     

  • Question 8/10
    1 / -0

    Two equations are given in each of the questions given below. Find the value of x and y by solving equations and answer as:

    I. x =  √144

    II.  3y2 + 10y – 13 = 0

    Solutions

     

  • Question 9/10
    1 / -0

    In the following question, two statements numbered I and II are given, on solving them, we get quantities I and II respectively. Compare both the quantities and choose the correct option. 

    Quantity I- A man sells a plot of land at 6% profit. If he had sold it at 10% profit, he would have received 

    ₹200 more. What is the selling price of the land?

    Quantity II- The cost price of an article is 

    ₹3,90 and sold at a profit of 3.12%, how much would be its approximate selling price?

    Solutions

    From Quantity I- 

    According to question;

    6% + 200 = 10%

    ⇒ Cost price = 100% = 50 × 100 = 5000

    ∴ Selling Price = 5000 + 5000 × 6 / 100

    = Rs. 5300

    From Quantity II- 

     S.P. = 390 + 3.12% of 390 = ₹402.168.

     

  • Question 10/10
    1 / -0

    In the following question, two statements numbered I and II are given, on solving them, we get quantities I and II respectively. Compare both the quantities and choose the correct option. 

    Quantity I - Anu and Bharti invested Rs.20,000 and Rs. 24,000 respectively in a business. Bharti left the business with his money after 8 months. At the end of the first year they earned a profit of Rs.1,620. What is the share of Anu in the profit? 

    Quantity II - A and B started a business by investing ₹28000 & ₹36000. After four months, B withdraw ₹3000 & A invested ₹8000 more. At the end of the year, the total profit is ₹ 2020. What is the difference between the profit earned by A and B?

    Solutions

     

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