Number of products sold by company P in 2018 = 42/100 x 250000 = 105000

Number of products sold by company P in 2017 = 105000 x 80/100 = 84000

Number of products sold by company Q in 2018 = 58/100 x 320000 = 185600

Required ratio = 84000 :185600 = 105 : 232

Number of products which are not sold by company R in 2018 = (100 – 46)/100 x 210000

= 54/100 x 210000

= 113400

Number of products which are not sold by company S in 2018 = (100 – 62)/100 x 180000

= 38/100 x 180000

= 68400

Required percentage = 113400/68400 x 100 = 165.78% = 166% approx.

Number of products sold by company P in 2018 = 42/100 x 250000 = 105000

Number of products sold by company R in 2018 = 46/100 x 210000 = 96600

Number of products sold by company T in 2018 = 54/100 x 150000 = 81000

Required average = (105000 + 96600 + 81000)/3

= 282600/3

= 94200

Number of products sold by company S in 2018 = 62/100 x 180000 = 111600

Number of products produced by company S in 2017 = 111600 x 90/100 = 100440

Total number of products sold by company S in 2017 = 45/100 x 100440 =45198

Number of products sold by company P in 2018 = 42/100 x 250000 = 105000

Number of products sold by company Q in 2018 = 58/100 x 320000 = 185600 (Maximum)

Number of products sold by company R in 2018 = 46/100 x 210000 = 96600

Number of products sold by company S in 2018 = 62/100 x 180000 = 111600

Number of products sold by company T in 2018 = 54/100 x 150000 = 81000

Let, initial amounts invested by Ramesh, Nimo and Bina be Rs.5k, Rs.8k and Rs.3k respectively.

Ratio of shares in the profit:

Ramesh : Nimo : Bina = (5k x 2 + 10k) : (8k + 12k x 2) : (3k + 6k x 2)

= 20k : 32k : 15k

= 20 : 32 : 15

Share of Nimo in the profit = [32/(20 + 32 + 15) ]x 134000

= 32/67 x 134000

= Rs.64000

Let, the fraction be p/q.
According to the question
(p x 120/100)/(q x 95/100) = 6/5
=> 120p/95q = 6/5
=> p/q = 6/5 x 95/120
=> p/q = 19/20
40% of the original fraction is 19/20 * 40/100 = 19/50

Let, monthly income of Raju = Rs.P

P x (100 – 10 – 5)/100 x (100 – 20)/100 x (100 – 10)/100 = 12240

=> P = 12240 x 100/90 x 100/80 x 100/85

=> P = Rs.20000

Amount spent by him on children’s education = 5/100 x 20000 = Rs.1000

1/Kunal + 1/Himesh + 1/Hamid = 1/15 ------------ (i)

1/Kunal + 1/Himesh + 1/Hamid + 1/Dinesh = 1/10 ----------- (ii)

1/Dinesh + 1/Himesh = 1/25 ------------ (iii)

From (i) and (ii)

1/15 + 1/Dinesh = 1/10

=> 1/Dinesh = 1/10 – 1/15

=> 1/Dinesh = (3 – 2)/30

=> 1/Dinesh = 1/30

From (iii)

1/30 + 1/Himesh = 1/25

=> 1/Himesh = 1/25 – 1/30

=> 1/Himesh = (6 – 5)/150

=> 1/Himesh = 1/150

From (i)

1/Kunal + 1/Hamid + 1/150 = 1/15

=> 1/Kunal + 1/Hamid = 1/15 – 1/150

=> 1/kunal + 1/Hamid = (10 – 1)/150

=> 1/Kunal + 1/Hamid = 9/150

=> 1/Kunal + 1/Hamid = 3/50

Let, required number of days = n

n x (1/30 + 3/50) = 1

=> n x (5 + 9)/150 = 1

=> n = 150/14

=> n = 75/7 days

Let the ages of Lili and Baby before two years be 4k years and 3k years respectively.

According to the question

(4k + 6)/(3k + 6) = 5/4

=> 4 x (4k + 6) = 5 x (3k + 6)

=> 16k + 24 = 15k + 30

=> 16k – 15k = 30 – 24

=> k = 6

Present age of Lili = 4k + 2 = 4 x 6 + 2 = 26 years

Present age of Baby = 3k + 2 = 3 x 6 + 2 = 20 years

Present age of Suman = (26 + 20)/2 = 46/2 = 23 years