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IBPS PO 2019 Aptitude Test - 8
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IBPS PO 2019 Aptitude Test - 8
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  • Question 1/10
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    Each question contains two quantities as Quantity I and Quantity II. You have to determine the relationship between these quantities and choose the option accordingly.

    Quantity I: What is difference between the successive discounts of 20% and 30% on the marked price Rs.780 and the successive discounts of 40% and 10% of the marked price Rs.800?

    Quantity II: The ratio of the price of Shirt and Table is 3:5. If the cost price of shirt is Rs.2 less than that of table, then find the cost price of Table?

    Solutions

    From quantity I,

    The successive discounts on 780 = 780 * (80/100) * (70/100) = 436.8

    The successive discounts on 800 = 800 * (60/100) * (90/100)  = 432

    Difference = 436.8 - 432 = 4.8

    From quantity II,

    The ratio of the price of Shirt and Table = 3:5

    5x – 2x = 2

    X=1

    Cost price of table = 5(1) = 5

    So,

    Quantity II > Quantity I

     

  • Question 2/10
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    Each question contains two quantities as Quantity I and Quantity II. You have to determine the relationship between these quantities and choose the option accordingly.

    Quantity I: The average weight of 8 students in the class is decreased by 4kg when two students with weight 30kg and 32kg are replaced by two new students. Find the average weight of the new students?

    Quantity II: The present age of A and B in the ratio of 4:5 and 8 years after their age will be in the ratio 6:7. What is the present age of A?

    Solutions

    From quantity I,

    Total decreased weight = 4*8 = 32kg

    Total weight of new students=30+32-32=30

    Average=30/2=15 kg

    From quantity II,

    The present age of A and B = 4 : 5

    After 8 years age of A and B = 6 : 7

    (4x+8) / (5x+8) = 6/7

    28x+56=30x+48

    2x=8

    x=4

    A’s present age = 4(4) =16 years

    So ,

    Quantity II > Quantity I

     

  • Question 3/10
    1 / -0

    Each question contains two quantities as Quantity I and Quantity II. You have to determine the relationship between these quantities and choose the option accordingly.

    Quantity I: The difference between SI and CI on certain sum at 20% per annum for 2 years is Rs.20. Find the sum?

    Quantity II: What would be the CI obtained on Rs.2000 at rate of 10% per annum for 2 years?

    Solutions

    From quantity I,

    The difference between  SI and CI for 2 years = PR2/1002

    20=(P*20*20) / (100*100)

    P=500

    From quantity II,

    Compound interest =( p (1+(r/100))2 ) - p

    CI=2000(1+10/100)2 - 2000

    CI=420

    So,

    Quantity I > Quantity II

     

  • Question 4/10
    1 / -0

    Each question contains two quantities as Quantity I and Quantity II. You have to determine the relationship between these quantities and choose the option accordingly.

    Quantity I: 20 women can do the piece of work in 12 days for working 8 hours per day. How many women are required to complete the work by 10 hours per day in 6 days?

    Quantity II: If 30% of three-fourth of 40% of the number is 18, then what is the 45% of 30% of that number?

    Solutions

    From quantity I,

    Work done by 20 women in one day = 1/(12*8) = 1/96

    Work done by one women in one day = 1/(96*20) = 1/1920

    So total work  = 1920

    Work done by one women in 6 days working in 10 hours per day = 60

    So the number of women required to complete the work in6 days working in 10 hours per day = 1920 /60 = 32

    Or,

    20*12*8=10*6*x

    32=x

    From quantity II,

    (30/100) * (3/4) * (40/100) * x = 18

    X = 200

    200 * (45/100) * (30/100) = 27

    So,

    Quantity I > Quantity II

     

  • Question 5/10
    1 / -0

    Each question contains two quantities as Quantity I and Quantity II. You have to determine the relationship between these quantities and choose the option accordingly.

    Quantity I: The ratio of the length, height and breadth of the cuboid is 2:4:1. If the volume of the cuboid is 512, then find the height of the cuboid?

    Quantity II: The length of the rectangle is increased by 20% and the breadth of the rectangle is decreased by 25% and the obtained area is 27cm2. Find the original area?

    Solutions

    From quantity I,

    The ratio of the length, height and breadth of the cuboid = 2:4:1

    2x * 4x * x = 512

    X = 4

    Height = 4*4 = 16cm

    From quantity II,

    X * (120/100) * (75/100) = 27

    x=30

    So,

    Quantity II > Quantity I

     

  • Question 6/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given bar graph shows the price (per kg) of five different fruits.

    ...view full instructions

    The average price of Cherry in all the years together is approximately what percent of the average price of Orange in all the years together?

    Solutions

    Average price of cherry = (50+150+200) / 3 = 400/3

    Average price of Orange = (200+150+100) / 3 = 450/3

    Required percentage = ((400/3) / (450/3))*100 = 88.889 = 89%

     

  • Question 7/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given bar graph shows the price (per kg) of five different fruits.

    ...view full instructions

    Suresh buys 10kg of apple and 25kg of Guava in the year 2014. He sells all these fruits in 2016 at the cost price in that year. Find the approximate profit percentage he got?

    Solutions

    Total price in 2014 = 10*150+25*50 = 2750

    Total price in 2016 = 10*250+25*150 = 6250

    Required percentage = ((6250-2750) / 2750) * 100 = 127%

     

  • Question 8/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given bar graph shows the price (per kg) of five different fruits.

    ...view full instructions

    A shopkeeper sells the Orange at the rate in the year 2015 to the customers. 25% of the profit would be earned, if the selling price of the orange was decrease by 20%, then how much profit was earned on every kg of orange sold?

    Solutions

    SP=150 * (80/100 ) = 120

    Cost price= (120*100) /125=96

    Profit = 150-96 = Rs.54

     

  • Question 9/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given bar graph shows the price (per kg) of five different fruits.

    ...view full instructions

    A shopkeeper mixes the Cherry in 2016 and 2015. He sells mixture at a profit of 25%. Total mixture is 450kg.If cost price of the mixture is Rs.180 per kg, find the difference between the total cost price of highest cost price and total selling price of the mixture?

    Solutions

    =2:3

    Highest cost cherry = (3/5) * (450 * 200) = Rs.54000

    Selling the mixture = (450*180*125)/100 = 101250

    Required Difference= 101250 – 54000 = 47250

     

  • Question 10/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given bar graph shows the price (per kg) of five different fruits.

    ...view full instructions

    What is the ratio of the average price of all the fruits in 2014 and the average price of all the fruits in 2016?

    Solutions

    The average price of all the fruits in 2014 = (150+200+100+50+50)/5 = 110

    The average price of all the fruits in 2016 =(250+100+150+200+150)/5= 170

    Required ratio =110:170=11:17

     

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