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IBPS PO 2019 Aptitude Test - 9
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IBPS PO 2019 Aptitude Test - 9
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  • Question 1/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given pie chart shows the percentage of students enrolled in different activities in the school.

    The given table shows the ratio of the number of boys to girls enrolled in these activities.

    ...view full instructions

    Quantity I: Number of girls in the school.

    Quantity II: Number of boys in the school.

    Solutions

    Swimming:

    Girls = (3/8) * (16/100) * 1200 = 72

    Boys = (5/8) *(16/100) * 1200=120

    Dance:

    Girls = (8/15) * (25/100) * 1200 = 160

    Boys =(7/15) * (25/100) * 1200 = 140

    Singing:

    Girls = (3/5) * (20/100) * 1200 = 144

    Boys = (2/5) * (20/100) * 1200= 96

    Drawing:

    Girls = (5/9) * (15/100) * 1200=100

    Boys = (4/9) * (15/100) * 1200 = 80

    Drama:

    Girls = (2/9) * (24/100) * 1200 = 64

    Boys = (7/9) * (24/100) * 1200 = 224

    Answer: C

    From quantity I,

    Number of girls = 72+160+144+100+64=540

    From quantity II,

    Number of boys = 120+140+96+80+224=660

    So, Quantity II > Quantity I

     

  • Question 2/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given pie chart shows the percentage of students enrolled in different activities in the school.

    The given table shows the ratio of the number of boys to girls enrolled in these activities.

    ...view full instructions

    The boys enrolled in singing and drama is approximately what percent of the number of girls enrolled in Dance and drawing?

    Solutions

    Swimming:

    Girls = (3/8) * (16/100) * 1200 = 72

    Boys = (5/8) *(16/100) * 1200=120

    Dance:

    Girls = (8/15) * (25/100) * 1200 = 160

    Boys =(7/15) * (25/100) * 1200 = 140

    Singing:

    Girls = (3/5) * (20/100) * 1200 = 144

    Boys = (2/5) * (20/100) * 1200= 96

    Drawing:

    Girls = (5/9) * (15/100) * 1200=100

    Boys = (4/9) * (15/100) * 1200 = 80

    Drama:

    Girls = (2/9) * (24/100) * 1200 = 64

    Boys = (7/9) * (24/100) * 1200 = 224

     Answer: A

    Boys enrolled in singing and drama = 96+224=320

    Girls enrolled in Dance and drawing = 100+160=260

    Required percentage =(320/260) * 100 = 123%

     

  • Question 3/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given pie chart shows the percentage of students enrolled in different activities in the school.

    The given table shows the ratio of the number of boys to girls enrolled in these activities.

    ...view full instructions

    What is the ratio of the number of girls enrolled in Swimming and Drama together to the number of boys enrolled in Dance and Drawing together?a

    Solutions

    Swimming:

    Girls = (3/8) * (16/100) * 1200 = 72

    Boys = (5/8) *(16/100) * 1200=120

    Dance:

    Girls = (8/15) * (25/100) * 1200 = 160

    Boys =(7/15) * (25/100) * 1200 = 140

    Singing:

    Girls = (3/5) * (20/100) * 1200 = 144

    Boys = (2/5) * (20/100) * 1200= 96

    Drawing:

    Girls = (5/9) * (15/100) * 1200=100

    Boys = (4/9) * (15/100) * 1200 = 80

    Drama:

    Girls = (2/9) * (24/100) * 1200 = 64

    Boys = (7/9) * (24/100) * 1200 = 224

    Answer: B

    Required ratio = (72+64) : (140+80)

    =136:220 = 34:55

     

  • Question 4/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given pie chart shows the percentage of students enrolled in different activities in the school.

    The given table shows the ratio of the number of boys to girls enrolled in these activities.

    ...view full instructions

    What is the percentage of girls in the school?

    Solutions

    Swimming:

    Girls = (3/8) * (16/100) * 1200 = 72

    Boys = (5/8) *(16/100) * 1200=120

    Dance:

    Girls = (8/15) * (25/100) * 1200 = 160

    Boys =(7/15) * (25/100) * 1200 = 140

    Singing:

    Girls = (3/5) * (20/100) * 1200 = 144

    Boys = (2/5) * (20/100) * 1200= 96

    Drawing:

    Girls = (5/9) * (15/100) * 1200=100

    Boys = (4/9) * (15/100) * 1200 = 80

    Drama:

    Girls = (2/9) * (24/100) * 1200 = 64

    Boys = (7/9) * (24/100) * 1200 = 224

    Answer: A

    Number of girls = 72+160+144+100+64=540

    Required percentage = (540/1200) * 100 = 45%

     

  • Question 5/10
    1 / -0

    Directions For Questions

    Study the following information carefully and answer the given questions:

    The given pie chart shows the percentage of students enrolled in different activities in the school.

    The given table shows the ratio of the number of boys to girls enrolled in these activities.

    ...view full instructions

    The number of girls enrolled in Dance, Drawing and Singing together is approximately what percent of the number of boys in the school?

    Solutions

    Swimming:

    Girls = (3/8) * (16/100) * 1200 = 72

    Boys = (5/8) *(16/100) * 1200=120

    Dance:

    Girls = (8/15) * (25/100) * 1200 = 160

    Boys =(7/15) * (25/100) * 1200 = 140

    Singing:

    Girls = (3/5) * (20/100) * 1200 = 144

    Boys = (2/5) * (20/100) * 1200= 96

    Drawing:

    Girls = (5/9) * (15/100) * 1200=100

    Boys = (4/9) * (15/100) * 1200 = 80

    Drama:

    Girls = (2/9) * (24/100) * 1200 = 64

    Boys = (7/9) * (24/100) * 1200 = 224

    Answer: A

    Number of boys = 120+140+96+80+224 = 660

    Required percentage = ((160+100+144)/660) * 100 = 61%

     

  • Question 6/10
    1 / -0

    The ratio of the speed of train A and train B is 3:2. Train A crosses the platform of equal length in 54 seconds and train B crosses the pole in 18 seconds. Length of train A is what percent more than that of the length of train B?

    Solutions

    Let ,

    Length of train A=x

    Length of train B=y

    The speed of train A and train B = 3S : 2S

    Distance = speed * time

    2x = 3S * (5/18) * 54

    X = 45/2S

    Y = 2S *(5/18) * 18

    y= 10S

    Required percentage =((45S/2-10S) / 10S)*100

    = (25S / 20S) * 100=125%

     

  • Question 7/10
    1 / -0

    Rahul invested certain amount in scheme A which offers simple interest and the amount becomes three-two of itself after 10 years. He also invested Rs.12000 in scheme B which offers compound interest and got Rs.1996.8 after 2 years. What is the difference between the rate of interest in scheme A and the rate of interest in scheme B?

    Solutions

    Scheme A

    Consider the principle as P and rate of interest as R,

    (3/2) P – P = P*10*R/100

    P/2 = PR/10

    R=5%

    Scheme B

    1996.8=12000 * (1+R/100)2 - 12000

    13996.8= (6/5) * (100+R)2

    108 = (100+R)

    R = 8%

    Required Difference = 8-5=3%

     

  • Question 8/10
    1 / -0

    The ratio of the speed of stream to speed of the boat in still water is 2:7. If the boat travels against the current at 20kmph, then how much time does it takes to travel 36km downstream?

    Solutions

    Speed of the boat in still water:  speed of stream= 2 : 7

    Upstream speed = speed of the boat in still water - speed of stream = 20kmph

    ⇒ 5x = 20kmph

    ⇒ X = 4 kmph

    Speed of stream= 8kmph

    Speed of the boat in still water=28 kmph

    Downstream speed= speed of the boat in still water + speed of stream

    ⇒ 28+8=36kmph

    Required time = 36/36 =1 hours

     

  • Question 9/10
    1 / -0

    The average weight of the students in the class is 32kg. 5 new students whose average weight is 28kg joined the class and then average weight of the class becomes 30kg. Find the total number of students in the class?

    Solutions

    Ratio of old students to new student = 2 : 2 = 1 : 1

    Total number of students = (5/1) * 2=10

     

  • Question 10/10
    1 / -0

    The ratio of the ages of A and B is 3:2 and the ratio of ages of B and C after 4 years is 1:2. The present age of A is 60% of the present age of C. Find the present age of B?

    Solutions

    The ratio of the ages of A and B = 3:2

    A= (60/100) * C

    A= (3/5) * C

    ((3/5) * C) / B = 3/2

    C/B = 5/2

    (5x+4) / (2x+4) = 2/1

    5x+4 = 4x+8

    x= 4

    B’s present age = 2(4)= 8 years

     

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